There is an object "LETTERS" which displays all letters from "a" to "z". Is
there any similar object whicg displays the "months" as well in
chronological order? like "jan", "feb",...,"dec"
Thanks,
--
View this message in context:
http://www.nabble.com/Is-there-any-%22month%22-object-lik
On Fri, 11-Sep-2009 at 06:12AM +0200, Johannes Huesing wrote:
|> Martin Maechler [Wed, Sep 02, 2009 at
09:17:42AM CEST]:
|> > > "PaCo" == p connolly
|> > > on Wed, 02 Sep 2009 12:19:31 +1200 writes:
|> >
|> > PaCo> On Mon, 31-Aug-2009 at 08:25PM +1000, Jim Lemon wrote:
|> >
Dear R users
I have a data frame that looks like this:
m j X1 X2
1 1
1 2
1 ...
1 J
2 1
2 2
2 ...
2 J
.
.
.
M 1
M 2
M ...
M J
The data frame essentially looks like a
have a look at ave() and/or tapply().
I hope it helps.
Best,
Dimitris
Reynaerts, Jo wrote:
Dear R users
I have a data frame that looks like this:
m j X1 X2
1 1
1 2
1 ...
1 J
2 1
2 2
2 ...
2 J
On Thu, 10-Sep-2009 at 04:47PM -0400, S. Few wrote:
|> For my Redhat 5.2 Linux box, which version of R would be most stable?
Redhat 5.2 is *very* old. That was around about the time of
Windows98, IIRC. Or do you mean RHEL 5.2?
|>
|> I am doing forecasting, statistics, etc.
|>
|>
|> Thanks!
Maybe I'm missing something, but how about using the shell function?
Bart
Duncan Murdoch-2 wrote:
>
> On 9/10/2009 9:25 AM, H Rao wrote:
>> Hi,
>> I am looking to execute an R script from VB as below.
>> The script runs fine but the redirection doesnt seem to happen. The
>> redirection opera
Hello R-users
I have a situation like this
x=c(1,3,2)
y=data.frame("a"=1:3, "b"=4:6, "c"=7:9)*2
So we have
> t(t(x))
[,1]
[1,]1
[2,]3
[3,]2
And
> y
a b c
1 2 8 14
2 4 10 16
3 6 12 18
I would like to obtain a vector with number taken from the data.frame: x is
needed as
emorway wrote:
In the plot below, there are some grid cells that have values below 10, which
is the lowest "cut" value I have specified. Is there a way, without
adjusting the number of cuts, to tell R to fill in those cells with the
lowest possible color (in this case greeen)? There is a white
Hello,
I have a question about "ipred" package. I am working on a data set which
contains 1000 individual swho came from 588 regions.
I calculated misclassification error rate with cross validation and its
smooted version "bootstrap 632" for different sample sizes in LDF. I am
doubting whether er
Dear R users,
I have to call fortran program from within R (R 2.8.1 on ubuntu 8.10
machine).
Suppose I have a fortran code like this (this is only a toy model, my
working model is far more complex, but input/output is similar)
DOUBLE PRECISION FUNCTION model(times, alfa, beta)
DOU
Hello,
I have a question about "ipred" package. I am working on a data set which
contains 1000 individual swho came from 588 regions.
I calculated misclassification error rate with cross validation and its
smooted version "bootstrap 632" for different sample sizes in LDF. I am
doubting whether er
Dear R users
I have basic knowledge of R and unaware of many more.
I am confused about how can I compare the result of two different models?
Have count data of plant species and want to correlate with altitude, rri,
pH, moisture, temperature etc. I have made some models using GLM of
different ord
Dear All!
It's now weeks that I'm going crazy with R, and as I'm a new user I now ask for
help (also because I still have only a few days to finish..)...
So shortly I describe you my Experiment in which I was looking for the
decomposition of herbivore dung under different treatments:
I made a b
On 11/09/2009 4:39 AM, Giacomo Santini wrote:
Dear R users,
I have to call fortran program from within R (R 2.8.1 on ubuntu 8.10
machine).
Suppose I have a fortran code like this (this is only a toy model, my
working model is far more complex, but input/output is similar)
DOUBLE PREC
> Da: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> Per conto di Luca Braglia
> Inviato: venerdì 11 settembre 2009 10.17
> A: r-help@r-project.org
> Oggetto: [R] how to do this?
> in this case the ouput should be
>
> 2
> 16
> 12
>
Obviously this
id.match = rep(0,
Thanks! now it works !
Giacomo
Duncan Murdoch wrote:
On 11/09/2009 4:39 AM, Giacomo Santini wrote:
Dear R users,
I have to call fortran program from within R (R 2.8.1 on ubuntu 8.10
machine).
Suppose I have a fortran code like this (this is only a toy model, my
working model is far more c
Try this:
> y[matrix(c(seq_along(x), x), ncol = 2)]
[1] 2 16 12
On Fri, Sep 11, 2009 at 4:17 PM, Luca Braglia wrote:
> Hello R-users
>
> I have a situation like this
>
> x=c(1,3,2)
>
> y=data.frame("a"=1:3, "b"=4:6, "c"=7:9)*2
>
> So we have
>
>> t(t(x))
> [,1]
> [1,] 1
> [2,] 3
> [3,]
Greetings,
Is there a package in R that will run multilevel models (e.g. students
nested in schools) where sampling weights can be employed at both levels?
Thanks in advance.
David
--
===
David Kaplan, Ph.D.
Professor
Department of
> Da: Linlin Yan [mailto:yanlinli...@gmail.com]
> Inviato: venerdì 11 settembre 2009 11.19
> A: Luca Braglia
> Cc: r-help@r-project.org
> Oggetto: Re: [R] how to do this?
>
> Try this:
> > y[matrix(c(seq_along(x), x), ncol = 2)]
> [1] 2 16 12
Very interesting!
So I can give as index to a data
On Fri, Sep 11, 2009 at 8:13 AM, megh wrote:
>
> There is an object "LETTERS" which displays all letters from "a" to "z". Is
> there any similar object whicg displays the "months" as well in
> chronological order? like "jan", "feb",...,"dec"
You could construct a vector of the first of t
Hi,
See if this helps,
polygon.regular <- # return a matrix of xy coordinates for a regular
polygon centered about (0,0)
function (sides = 5)
{
n <- sides
if (n < 3)
n <- 3
if (n > 8)
n <- 50
th <- pi * 2/n
costh <- cos(th)
sinth <- sin(th)
On 09/11/2009 05:15 PM, Patrick Connolly wrote:
...
|> and in previous versions, you could always do M-x cua-mode for
|> the same effect. Talk about a well-hidden function mostly directed
|> at beginners ...
Perhaps the thinking was that by the time they find it, they'll
already have noticed
This script worked for me. Be sure to put in your correct link.
link <- "C:\\R_Home\\Charts & Graphs Blog\\R_Chart_Doc\\text_data.csv"
testdata<- read.table(link, head = T, sep = ",",na.strings = "na")
test_date = as.Date(testdata$Date,"%d-%m-%y")
plot(test_date, testdata$Model, type="l
On 11-Sep-09 10:41:21, Jim Lemon wrote:
> On 09/11/2009 05:15 PM, Patrick Connolly wrote:
>> ...
>> |> and in previous versions, you could always do M-x cua-mode for
>> |> the same effect. Talk about a well-hidden function mostly directed
>> |> at beginners ...
>>
>> Perhaps the thinking was tha
On 11/09/2009 6:53 AM, (Ted Harding) wrote:
On 11-Sep-09 10:41:21, Jim Lemon wrote:
On 09/11/2009 05:15 PM, Patrick Connolly wrote:
...
|> and in previous versions, you could always do M-x cua-mode for
|> the same effect. Talk about a well-hidden function mostly directed
|> at beginners ...
See ?Constants
On Fri, Sep 11, 2009 at 3:13 AM, megh wrote:
>
> There is an object "LETTERS" which displays all letters from "a" to "z". Is
> there any similar object whicg displays the "months" as well in
> chronological order? like "jan", "feb",...,"dec"
>
> Thanks,
> --
> View this mes
On Thu, 2009-09-10 at 05:27 -0700, FMH wrote:
> Thank you for the scripts, but the label and the values in the x and y-axis
> suddently dissapear even the 'axis' function is used as stated in the command
> below. Could you help on this?
>
> axis(1, at = seq(100, 800, by = 100))
> axis(2, at = se
Try this:
y[cbind(seq(length(x)), x)]
On Fri, Sep 11, 2009 at 5:17 AM, Luca Braglia wrote:
> Hello R-users
>
> I have a situation like this
>
> x=c(1,3,2)
>
> y=data.frame("a"=1:3, "b"=4:6, "c"=7:9)*2
>
> So we have
>
> > t(t(x))
> [,1]
> [1,]1
> [2,]3
> [3,]2
>
> And
>
> > y
>
Hi Clair,
Good one for pointing out that dates on the x-axis are messy (and for
bringing my mistake in the coloring of the ordinates to my attention).
Attached is a revised version of the function that will be in the next
version of plotrix. Try this:
twoord.plot(x.Left, y.Left, x.Right, y.Ri
Dear All,
what determines if a difference between POSIXct objects gets
expressed in days or seconds?
In the following example, it's sometimes seconds, sometimes days.
as.POSIXct('2009-09-01') - as.POSIXct(NA)
Time difference of NA secs
c(as.POSIXct('2009-09-01'), as.POSIXct(NA)) -
c(as.POSI
Maybe:
do.call(rbind, lapply(with(xy <- rbind(x, y), split(xy, list(a, b), drop =
TRUE)), tail, 1))
On Fri, Sep 11, 2009 at 3:45 AM, jo wrote:
> Thanks for the post-processing ideas. But is there any way to do that
> in one step?
>
> On Thu, Sep 10, 2009 at 7:20 PM, Henrique Dallazuanna
> wrot
Hello,
I am working with graph and adjacency matrix, the package 'graph' seems to be
appropriate for this.
An example in the package
> mat <- rbind(c(0, 0, 1, 1),
+ c(0, 0, 1, 1),
+ c(1, 1, 0, 1),
+ c(1, 1, 1, 0))
> rownames(mat) <- colnames(mat) <- letters
you can use the 'mar' parameter of 'par' to setup the margins of the
graph and then use the height/width option when opening the graphic
device to control the plotting area.
On Thu, Sep 10, 2009 at 6:10 AM, rajesh j wrote:
> Hi,
>
> I need my plot to occupy a thin strip-like area but the plot are
Hi all,
Is there any process to conduct a search for a particular digit or letter in
a ch. string? For example I want to make a search where 1st numeric figure
appears in the string "asd123". Here the answer should be "4"
Thanks,
--
View this message in context:
http://www.nabble.com/Searching
Try this:
head(unlist(gregexpr("[0-9]", "asd123")), 1)
On Fri, Sep 11, 2009 at 10:02 AM, RON70 wrote:
>
> Hi all,
>
> Is there any process to conduct a search for a particular digit or letter
> in
> a ch. string? For example I want to make a search where 1st numeric figure
> appears in the stri
Try this script. I converted test_date to numeric decimal year
link <- "C:\\R_Home\\Charts & Graphs Blog\\R_Chart_Doc\\text_data.csv"
testdata<- read.table(link, head = T, sep = ",",na.strings = "na")
test_date = as.Date(testdata$Date,"%d-%m-%y")
# Convert dates to decimal year
my_yr <-
'-' calls 'difftime' which, if you don't specify the units, makes the
following assumptions in the code:
> difftime
function (time1, time2, tz = "", units = c("auto", "secs", "mins",
"hours", "days", "weeks"))
{
time1 <- as.POSIXct(time1, tz = tz)
time2 <- as.POSIXct(time2, tz = tz)
Try this:
> regexpr("[0-9]", "asd123")
[1] 4
attr(,"match.length")
[1] 1
On Fri, Sep 11, 2009 at 9:02 AM, RON70 wrote:
>
> Hi all,
>
> Is there any process to conduct a search for a particular digit or letter in
> a ch. string? For example I want to make a search where 1st numeric figure
> appe
Jim - Thank you very much for this explanation and the hint to use difftime.
Heinz
At 15:09 11.09.2009, jim holtman wrote:
'-' calls 'difftime' which, if you don't specify the units, makes the
following assumptions in the code:
> difftime
function (time1, time2, tz = "", units = c("auto", "sec
I have made program code for Vector Auto Regressive in terms
of completing my undergraduate program using R. I have an important
question related to my project.
If I have:
data(Canada)
var.2c <- VAR(Canada, p = 2, type = "const")
var.2c.stabil <- stability(var.2c, type = "O
I have following object :
> date2
[,1] [,2]
[1,] "apr" "1992"
[2,] "aug" "1992"
[3,] "dec" "1992"
[4,] "feb" "1992"
[5,] "jan" "1992"
[6,] "jul" "1992"
[7,] "jun" "1992"
[8,] "mar" "1992"
[9,] "may" "1992"
[10,] "nov" "1992"
[11,] "oct" "1992"
[12,] "sep" "1992"
[1
Try this:
data2[order(data2[,2], match(data2[,1], tolower(month.abb))),]
On Fri, Sep 11, 2009 at 10:46 AM, megh wrote:
>
> I have following object :
>
> > date2
> [,1] [,2]
> [1,] "apr" "1992"
> [2,] "aug" "1992"
> [3,] "dec" "1992"
> [4,] "feb" "1992"
> [5,] "jan" "1992"
> [6,] "j
Hello everyone,
I am trying to implement completion for proto objects. Proto extends
environment in a hierarchical way. Thus completion should list all the
names in all it's parent environments.
For "normal" classes defining names.class would do the job, but completion
for "environment"
You might want to add a date column it you are planning to operate on
the data with dates:
> a # your data
X..1. X..2.
1apr 1992
2aug 1992
3dec 1992
4feb 1992
5jan 1992
6jul 1992
7jun 1992
8mar 1992
9may 1992
10 nov 1992
11 oct 1992
12 sep
Here it is using zoo and classic graphics.
1. Just paste this into your R session:
library(zoo)
URL <- "http://www.nabble.com/file/p25398419/test%2Bchart%2Bdata.csv";
z <- read.zoo(URL, header = TRUE, format = "%d-%m-%y", sep = ",")
cols <- c("green", "red", "blue")
plot(z, screen = 1, col = c
See ?assignInNamespace
On Fri, Sep 11, 2009 at 10:02 AM, Vitalie S. wrote:
>
> Hello everyone,
>
> I am trying to implement completion for proto objects. Proto extends
> environment in a hierarchical way. Thus completion should list all the names
> in all it's parent environments.
>
> For "normal
Hi,
On Sep 11, 2009, at 8:22 AM, Arber Ngjela wrote:
Hello,
I am working with graph and adjacency matrix, the package 'graph'
seems to be appropriate for this.
An example in the package
mat <- rbind(c(0, 0, 1, 1),
+ c(0, 0, 1, 1),
+ c(1, 1, 0, 1),
+ c
On Fri, 11 Sep 2009, Duncan Murdoch wrote:
On 11/09/2009 6:53 AM, (Ted Harding) wrote:
On 11-Sep-09 10:41:21, Jim Lemon wrote:
> On 09/11/2009 05:15 PM, Patrick Connolly wrote:
> > ...
> > | > and in previous versions, you could always do M-x cua-mode for
> > | > the same effect. Talk ab
Hello all.
Has anyone out there had experience using R with voice recognition
software? I got this query from a student with nerve damage in her hand
who wants to program in R.
Thanks, Chris
__
R-help@r-project.org mailing list
https://stat.ethz
Thanks Jorge,
That is what I was looking for.
Cheers,
James
From: Jorge Ivan Velez [mailto:jorgeivanve...@gmail.com]
Sent: 08 September 2009 18:41
To: Arnold, James
Cc: r-help@r-project.org
Subject: Re: [R] Mapping factors to a new set of factors
Hi James,
Take a look at the "recode" function
Thank you it is what I was looking for.
--
View this message in context:
http://www.nabble.com/Mantel-test-least-square-line-tp25235402p25401329.html
Sent from the R help mailing list archive at Nabble.com.
__
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https:
Dear R users,
I have a file that contains a text header followed by a gzipped data chunk.
I thought I would be able to read this by doing something like this.
con<-file('myfile','rb')
header<-readLines(con,10)
gzf<-gzcon(con)
data<-readBin(gzf,"int",n=1e7)
But what I find is that gzcon resets
On 11-Sep-09 14:16:44, Clint Bowman wrote:
> On Fri, 11 Sep 2009, Duncan Murdoch wrote:
>
>> On 11/09/2009 6:53 AM, (Ted Harding) wrote:
>>> On 11-Sep-09 10:41:21, Jim Lemon wrote:
>>> > On 09/11/2009 05:15 PM, Patrick Connolly wrote:
>>> > > ...
>>> > > | > and in previous versions, you coul
Good day,
I read some data from a PostgreSQL database by a following script:
library(Rdbi)
library(RdbiPgSQL)
# conn becomes an object which contains the DB connection:
conn <- dbConnect(PgSQL(), host="localhost", dbname="BVS",
user="postgres", password = "***")
query_duj_kal <- dbSendQuery(
Dear all,
I'd like to use the package RPostgreSQL. I'm using R version 2.8.1 and I've
download the last version RPostgreSQL. When I load the package, I get something
like "the file LIBPQ.DLL is missing".
Do you have any idea about what I'm suppose to do ? Thanks everyone.
__
Thanks a lot Phil,
Recode is exactly what I was looking for. I managed to get my old function
working using sapply, but the performance was horrendously slow!
One other thing was that the lvls vector can only seem to be set within the
global scope of R, and local variables within a function do
Thanks Jim,
I managed to get my function to work by putting it within an sapply.
Unfortunately the performance was terrible, so I've gone with the suggestion of
other posters to use recode in the car package.
Cheers,
James
-Original Message-
From: jim holtman [mailto:jholt...@gmail.com
Ted, I think I share your feelings about mice (e.g., that is why I use
window managers where the mouse is not needed or is actually
discouraged) but ...
On Fri, Sep 11, 2009 at 4:46 PM, Ted Harding
wrote:
> On 11-Sep-09 14:16:44, Clint Bowman wrote:
>> On Fri, 11 Sep 2009, Duncan Murdoch wrote:
>
Hello everybody,
I am writing a review paper about State Space models in R, and I would
like to cover as many packages as I reasonably can.
So far I am familiar with the following tools to deal with SS models:
* StructTS, Kalman* (in stats)
* packages dse[1-2]
* package sspir
* package dlm
I
On my R 2.9.2 installation, ?Constants just says "No documentation
...". I don't know why Gabor and I would have different results.
However, ?LETTERS does provide the requested information.
-Don
At 7:30 AM -0400 9/11/09, Gabor Grothendieck wrote:
See ?Constants
On Fri, Sep 11, 2009 at 3:13 A
Lore M wrote:
> Dear all, I'd like to use the package RPostgreSQL. I'm using R
> version 2.8.1 and I've download the last version RPostgreSQL. When I
> load the package, I get something like "the file LIBPQ.DLL is
> missing". Do you have any idea about what I'm suppose to do ? Thanks
> everyone.
l
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Don MacQueen
> Sent: Friday, September 11, 2009 8:16 AM
> To: Gabor Grothendieck; megh
> Cc: r-help@r-project.org
> Subject: Re: [R] Is there any "month" object like "LETTERS" ?
>
Being more specific:
On Fri, 2009-09-11 at 17:03 +0200, Tomas Lanczos wrote:
> Good day,
>
> I read some data from a PostgreSQL database by a following script:
>
> library(Rdbi)
> library(RdbiPgSQL)
> # conn becomes an object which contains the DB connection:
> conn <- dbConnect(PgSQL(), host="l
At the risk of stating the obvious:
- rm(.) # clears specific objects out of memory as soon as they're no
longer needed in the routine.
- sapply(ls(), function(x) object.size(get(x))) #lists all objects with
the memory each is using.
- rm(list=ls()) #clears out all objects, e.g. be
Thanks - that works great.
Do you have any suggestions about the grid() problem - i.e. that the
vertical gridlines do not line up with the x-axis tickmarks (which are
years)?
I can't see on what basis the vertical gridlines are being positioned, but
it doesn't look good that they are not lined u
Hi
One of the most important calculation in applied finance is the number of
days between dates.
That kind of calculus become annoying when a specific calendar must be used.
That is the case for the business days calculus.
The package timeDate has a function isBizday to perform that kind of thing
>
>
>I have made program code for Vector Auto Regressive in terms
>of completing my undergraduate program using R. I have an important
>question related to my project.
>If I have:
>data(Canada)
>var.2c <- VAR(Canada, p = 2, type = "const")
>var.2c.stabil <- stability(var.2c,
Arber Ngjela wrote:
> Hello,
> I am working with graph and adjacency matrix, the package 'graph' seems to be
> appropriate for this.
> An example in the package
>> mat <- rbind(c(0, 0, 1, 1),
> + c(0, 0, 1, 1),
> + c(1, 1, 0, 1),
> + c(1, 1, 1, 0))
>> rowna
I have a vector T and a scalar m such that 1 <= m <= sum(T). I also have a
vector U that satisfies three properties...
1. length(T)==length(U)
2. sum(U)==m
3. for (i in 1:length(T)) U[i]<=T[i]
The function "nextu" (given below) calculates the "next" vector subject to the
same restrictions.
You might try:
RSiteSearch("state space")
and try the search engine at rseek.org
On Fri, Sep 11, 2009 at 11:04 AM, Giovanni Petris wrote:
>
> Hello everybody,
>
> I am writing a review paper about State Space models in R, and I would
> like to cover as many packages as I reasonably can.
>
> So
Hi, Giovanni:
1. I've used primarily "sspir" and "dlm". There is apparently a
new release of "sspir", which I have not used. When I last tried
"sspir", it did NOT have a forecast function, while "dlm" did. The two
packages have functions with the same name but incompatible code. It
month.abb should do the trick
_
View your other email accounts from your Hotmail inbox. Add them now.
__
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PLEA
I'm sure this is a really simple problem, but I've spent hours digging and I
keep running into roadblocks.
I'm trying to get a simple chart with three time series. Similar to the
attached example
http://www.nabble.com/file/p25398419/Excel%2Bchart%2Bexample.pdf
Excel+chart+example.pdf , somethin
On Fri, 11 Sep 2009 16:07:45 +0200, Gabor Grothendieck
wrote:
See ?assignInNamespace
thanks for the hint. It works to some extent. Functions are redefined in
"base" but utils:::specialCompletions seems not to preform properly:
ls.proto <- function(x){ # function to complete
.local
Hi Jeannine,
I'm just forwarding this Q&A back to the r-help list, you'll get more
eyes on it and other people might have better solutions.
Answers inline:
On Sep 11, 2009, at 12:25 PM, Jeannine Cavender-Bares wrote:
Dear Steve,
Greetings! You helped me earlier this summer with an R quest
You might check the bugs section on the proto home page
and if any of those seem to apply try the devel version of
proto (or the workaround mentioned) as all known bugs are fixed
in the devel version. If that does not help let me know offline
and I will try to help you.
See: http://r-proto.google
Hi,
It might be a primitive question but how it is possible to determine if a
variable is initialized in an environment? Suppose that we start a R session
and wants to run a script which use the variable i. Which function could
evaluate if i is already initialized or not and if not, then ask int
Hi all,
I have been using R on Windows for a long time, but now I am ready to move to
Mac OS X, but I was just wondering if R works better on Mac than on Windows.
This is because I had some memory size issues in the past.
Another question is if some of you know an R editor for Mac (just like
Dear All,
I have large matrix (46000 x 11250). I would like to do the linear regression
for each row. I wrote a simple function that has lm() and used
apply(mat,1,func). The issue is that it takes ages to load the file and also to
finish the lm. I am using LINUX 64 bit with 32G mem. Is there an
On Sep 11, 2009, at 12:15 PM, carol white wrote:
Hi,
It might be a primitive question but how it is possible to determine
if a variable is initialized in an environment? Suppose that we
start a R session and wants to run a script which use the variable
i. Which function could evaluate if i
Hi,
It might be a primitive question but how it is possible to determine if a
variable is initialized in an environment? Suppose that we start a R session
and wants to run a script which uses the variable i. Which function could
evaluate if i exists already and has been initialized or not? The p
Try this also:
subset(as.data.frame.table(m), !is.na(Freq))
On Fri, Sep 11, 2009 at 1:48 PM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi Jeannine,
>
> I'm just forwarding this Q&A back to the r-help list, you'll get more eyes
> on it and other people might have better solutions
Hi Corrado,
Not being familiar with your research goals or data I can't make
recommendations, but I can suggest a couple of places to look for
information: Frank Harrell's Regression Modeling Strategies and his
Design library available on CRAN, and Hastie et al's The Elements of
Statistical Learn
R / S Programmer - New York
Description:
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their research based in New York City. We are looking for highly
motivated individuals to work in a customer-focused environment.
This is a unique opportunity to develop with a leading
On Sep 11, 2009, at 12:15 PM, Victor Manuel Garcia Guerrero wrote:
Hi all,
I have been using R on Windows for a long time, but now I am ready
to move to Mac OS X, but I was just wondering if R works better on
Mac than on Windows. This is because I had some memory size issues
in the past.
Hi,
On Sep 11, 2009, at 1:15 PM, Victor Manuel Garcia Guerrero wrote:
Hi all,
I have been using R on Windows for a long time, but now I am ready
to move to Mac OS X, but I was just wondering if R works better on
Mac than on Windows. This is because I had some memory size issues
in the pa
HI all,
raw_urine =
read.table("Z:\\bruce.9.3.09.sample.stability.analysis\\urine\\mz.spot.sam.dat.new",
header = TRUE )
pvalue =
read.table("Z:\\bruce.9.3.09.sample.stability.analysis\\urine\\all.urine.features.t.test.result",
header = TRUE )
library(compositions)
p = function(a,b){
y = pvalue[,a]
I am trying to automate a report that my company does every couple of years
for the state of Maine. In the past we have used SPSS to run the data and then
used complicated Excel template to make the tables/graphics which we then
imported into Word. Since there are 256 tables/graphics for this re
Hi,
On Sep 11, 2009, at 1:15 PM, A Ezhil wrote:
Dear All,
I have large matrix (46000 x 11250). I would like to do the linear
regression for each row. I wrote a simple function that has lm() and
used apply(mat,1,func). The issue is that it takes ages to load the
file and also to finish th
Hi Edward,
On Sep 11, 2009, at 1:47 PM, Edward Chen wrote:
HI all,
raw_urine =
read.table("Z:\\bruce.9.3.09.sample.stability.analysis\\urine\\mz.spot.sam.dat.new
",
header = TRUE )
pvalue =
read.table("Z:\\bruce.9.3.09.sample.stability.analysis\\urine\\all.urine.features.t.test.result
",
he
Dear all,
Does anyone have any suggestions on how to block multiple columns of data
one at a time in the midst of an analysis, having specified the blocking
variable?
I am running a random effects model using lmer, and my data set has
multiple columns.
Individuals in the study are grouped i
Try the textplot function in the gplots package:
nf <- layout(matrix(1:2), height = lcm(12))
par(mar = c(2, 8, 2, 2))
barplot(prop.table(example.table, 1), beside = TRUE)
textplot(round(prop.table(example.table, 1), 2), halign = 'left',
mar = c(0,0,0,0), show.colnames = FALSE, cex = 2,
Hi
I have written a code to do some averaging of data over uneven
intervals. The for loop keeps missing particular depths and I once got
an error message reading:
*** caught segfault ***
address 0xc023, cause 'memory not mapped'
Possible actions:
1: abort (with core dump, if enabled)
2
When I use the command for PACF, lags 5, 10, 15, and 20 are labeled. I would
like to label lag 1. I would greatly appreciate if someone could tell me how
to do this. Below is the command that I am using:
pacf(data$R1,main="Series R1 Residuals")
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__
Hi
Sorry I don't seem to have explained what I'm trying to do very clearly.
The piece of code below multiplies the two matrices together a number of
times based on the value in the matmult(InitialPop,1) term in this case one
(year), this gives me the end population for the analysis.
InitialPop<
I am trying to use one of the variance function classes (e.g., varClasses
-varConstPower or varPower)
When I run the model under default conditions or specify varIdent explicitly
I do not have any problems. If I try to use anything else I get error
messages of the form
"Error in na.fail.defaul
Hi Stephanie,
Take a look at the "xaxt" argument under ?par as well as ?axis. Here is an
example modified from ?pacf :
acf(lh, xaxt = "n")
axis(1, 0:16, 0:16, cex.axis = 0.8)
HTH,
Jorge
On Fri, Sep 11, 2009 at 12:02 PM, Stephanie Cooke wrote:
> When I use the command for PACF, lags 5, 10,
Try this:
pacf(data$R1, main = "Series R1 Residuals", xaxt = 'n')
axis(1, c(1, axTicks(1)))
On Fri, Sep 11, 2009 at 1:02 PM, Stephanie Cooke
wrote:
> When I use the command for PACF, lags 5, 10, 15, and 20 are labeled. I
> would
> like to label lag 1. I would greatly appreciate if someone could
Hi,
I'm a daily user of both mac and Linux so wanted to offer some thoughts:
1) R runs great on a Mac. There is a standard install from the cran
website that has a nice GUI built into it. You can do things like drag
files to the console and it will fill in the path name.
2) I like using B
If I understand you can use replicate:
replicate(10, matmult(InitialPop, 1))
On Fri, Sep 11, 2009 at 1:11 PM, RFish wrote:
>
> Hi
>
> Sorry I don't seem to have explained what I'm trying to do very clearly.
> The piece of code below multiplies the two matrices together a number of
> times base
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