Hello,
On 7/1/09, Michael wrote:
> More pointers about using R for efficiency in development are highly
> apprecaited!
>
This is more from the point of view of the beginner; something that I
wrote recently on r-sig-teaching:
" I will mention a recent discussion [1] on r-sig-gui that
would---I b
A reasonable place to start would be to look at the packages recommended
in the Machine Learning section of CRAN Task Views:
http://cran.r-project.org/web/views/MachineLearning.html . You could
also try to search the archive for this list which often recommend the
same package (e.g.
http://to
Gabor Grothendieck wrote:
It can be done without setting locales using chron:
library(chron)
as.Date(chron("1970-Jan-01", format = "Year-Month-Day"))
[1] "1970-01-01"
On Wed, Jul 1, 2009 at 10:09 AM, Ben Bolker wrote:
Dear r-helpers,
This is a little bit more of a Windows problem than
a
...Does anybody know more about the way R computes the fitting values of
a logistic model? Should I ask to R-devel?
Fabrizio Renzi
-Messaggio originale-
Da: Renzi Fabrizio
Inviato: 01 July 2009 09:43
A: 'ted.hard...@manchester.ac.uk'; Marc Schwartz
Cc: r-help@r-project.org
Oggetto: R: [R
On Thu, 2009-07-02 at 00:01 -0500, Gene Leynes wrote:
> playwith(xyplot(z3), time.mode = TRUE)
WoW! Looks (and is) GrEaT!
Nikos
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Michael wrote:
I saw my friend has a R Console window which has automatic syntax
reminder when he types in the first a few letters of R command. And
he's using R under MAC. Is that a MAC thing, or I could do the same on
my PC Windows?
Yes, the Mac GUI for R is a lot nicer than the Windows vers
On Jul 1, 2009, at 4:27 AM, Andrea Storto wrote:
Dear all,
Does anyone know if there exist a R function
in some package to compute streamlines
given the two components of a vectorial field?
Thanks in advance,
Have you looked at arrow.plot {fields}?
David Winsemius, MD
Heritage Laboratories
Hi,
I would like to write text on top of an arrow.How can I do this?
--
Rajesh.J
[[alternative HTML version deleted]]
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Thanks again David,
I apologize for not getting back to you immediately.
I do not want to cost too much of your time, but if it's ok for you, I will
try to clarify what I'm looking for:
Yes, I'm not looking for density estimates. I need to characterize spatial
_patterns_ of objects distributed a
On 7/2/09, Warren Young wrote:
> reason it has to be that way. Maybe someone will port some of the Mac GUI's
> features over to the Windows version.
>
Or in the mean-time someone would try JGR to see whether it gets
farther than the Windows Rgui.
Liviu
___
Dear R-users (and developers),
I am looking for an efficient framework to carry out parameter
estimations based on MCMC (optionally with specified priors). My goal is
as follow:
* take ANY R-function returning a likelihood-value (this function may
itself call external programmes or other code!
I am trying to use computer modern fonts in postscript files for a latex
document. Ultimately I want to automate this through sweave. I've read the
documentation ans have tried the following code to use lattice to produce a
graph using computer modern:
library(lattice)
library(grid)
testPlot=(
Good morning everybody,
i'm trying to use the IFS function to estimate a distribution function.
But i want to estimate my distribution function at some fixed points. Is it
possible ? I see in the R help that we can choose the number of points but i
don't see anything which allows me to define the
I have a data frame (hf) that is all set up and the dates are working
fine - however I need to extract the months and hours (2 separate
columns) as numbers - however they are coming out as characters.
I have tried both the following:
hf50$hour= hf50$date
hf50$hour=format(hf50["hour"],"%H")
a
Hi list,
is it possible convert the xtabs result
xtabs(breaks~tension+wool,data=warpbreaks)
wool
tension A B
L 401 254
M 216 259
H 221 169
to a simple matrix?
A B
L 401 254
M 216 259
H 221 169
Thanks a lot! Gianandrea
--
View this m
I have a data frame (hf) that is all set up and the dates are working
fine - however I need to extract the months and hours (2 separate
columns) as numbers - however they are coming out as characters.
I have tried both the following:
hf50$hour <- hf50$date
hf50$hour <- format(hf50["hour"],"%H"
Try:
openplotmat()
pos <- coordinates(c(2,4),hor=FALSE)
Parr<- treearrow(from=pos[1:2,],to=pos[3:6,],arr.side=1:2,path="V")
text(Parr,"hello")
dr. Karline Soetaert
NIOO - CEME
PO box 140
4400 AC Yerseke
the Netherlands
Phone: ++ 31 113 577487
fax: ++ 31 113 573616
e-mail: k.soeta...@nioo.knaw
On Thu, Jul 2, 2009 at 4:34 AM, Rolf Turner wrote:
>
> On 2/07/2009, at 12:20 PM, Hsiu-Khuern Tang wrote:
>
> Is this expected behavior?
>>
>> z <- 1:5
>>> z[1] <<- 0
>>>
>> Error in z[1] <<- 0 : object "z" not found
>>
>> The documentation seems to suggest that z will be found in the global
>>
Wouldn't grass-users, or maybe R-sig-geo be a more appropriate list? Given
points in geographical coordinates, use project() or spTransform() in rgdal.
The former will not do datum transformation, the latter will. NAD83 is a US
datum specification based on WGS84, UTM is a projection but is useless
Hi
r-help-boun...@r-project.org napsal dne 02.07.2009 12:40:05:
> I have a data frame (hf) that is all set up and the dates are working
> fine - however I need to extract the months and hours (2 separate
> columns) as numbers - however they are coming out as characters.
>
> I have tried both t
On 01/07/2009 8:20 PM, Hsiu-Khuern Tang wrote:
Is this expected behavior?
z <- 1:5
z[1] <<- 0
Error in z[1] <<- 0 : object "z" not found
The documentation seems to suggest that z will be found in the global
environment and modified accordingly.
z <<- 0 works as documented, it's the indexing
On 02-Jul-09 09:06:44, Mr Derik wrote:
> I am trying to use computer modern fonts in postscript files
> for a latex document. Ultimately I want to automate this through
> sweave. I've read the documentation ans have tried the following
> code to use lattice to produce a graph using computer modern:
On 01/07/2009 9:10 PM, Carl Witthoft wrote:
> More generally, you can always write a loop. They aren't necesssrily
fast
> or elegant, but they're pretty general. For example, to calculate
the max
> of the previous 50 observations (or fewer near the start of a
vector), you
> could do
>
On 01/07/2009 9:34 PM, Rolf Turner wrote:
On 2/07/2009, at 12:20 PM, Hsiu-Khuern Tang wrote:
Is this expected behavior?
z <- 1:5
z[1] <<- 0
Error in z[1] <<- 0 : object "z" not found
The documentation seems to suggest that z will be found in the global
environment and modified accordingly.
Carsten Dormann wrote:
>
> Dear R-users (and developers),
>
> I am looking for an efficient framework to carry out parameter
> estimations based on MCMC (optionally with specified priors). My goal is
> as follow:
> * take ANY R-function returning a likelihood-value (this function may
> itse
glaporta wrote:
Hi list,
is it possible convert the xtabs result
xtabs(breaks~tension+wool,data=warpbreaks)
wool
tension A B
L 401 254
M 216 259
H 221 169
to a simple matrix?
A B
L 401 254
M 216 259
H 221 169
In principle it alr
Iason Christodoulou wrote:
Dear kind R-experts.
with miximum likelihood method i found the following estimations for my
parameters
vector:
mu
H
A1
A2
.
.
.
A10
D1
D2
.
.
.
D10
but i want to add sum to zero constraints. sum(a1:a10)=0 and sum(d1:d10)=0
how i will do this?
Don't estimate
On 02/07/2009 5:10 AM, Warren Young wrote:
Michael wrote:
I saw my friend has a R Console window which has automatic syntax
reminder when he types in the first a few letters of R command. And
he's using R under MAC. Is that a MAC thing, or I could do the same on
my PC Windows?
Yes, the Mac GUI
I think you want to use 'ifelse':
social$CitizenType<-ifelse(social$CitizenType==""
||social$PrimaryLanguage=="English","US Citizen" )
On Wed, Jul 1, 2009 at 5:45 PM, Chris Anderson wrote:
> I have a variable that identifies citizen type but some of my rows are blank.
> I want to replace the bla
Should be (I think): (default condition and the use of "|" instead of "||")
social$CitizenType<-if(social$CitizenType=="" |
social$PrimaryLanguage=="English","US Citizen", social$CitizenType )
On Thu, Jul 2, 2009 at 7:19 AM, jim holtman wrote:
> I think you want to use 'ifelse':
>
> social$Citize
Hi
Tim Chatterton napsal dne 02.07.2009 13:19:46:
> > Actually it is a character and you need to convert it to numbers by
as.numeric
>
> This is the bit I have problems with - I can easily get it out as
characters
> but I cannot work out how to use as.numeric (and had actually given up
as
On Jul 1, 2009, at 4:43 PM, Jonathan Greenberg wrote:
By the way, you'll probably have to reinstall some or all of your
packages (and dependencies) if you are using R64.app, probably
downgrading them in the process.
--j
This really ought to be on the r-sig-mac list. I am copying that lis
hi folks,
if i have an xts object as follows:
library(xts)
> dd <- as.POSIXct(strptime(c("2009-06-01 08:00:00", "2009-06-01
08:30:00","2009-06-01 09:00:00","2009-06-02 08:00:00", "2009-06-03
08:00:00", "2009-06-03 08:30:00"),"%Y-%m-%d %H:%M:%S"))
> a <- xts(1:6,dd)
> a
[[alternativ
Robert,
It is a windows thing:
Try:
par(mfrow=c(2,2))
for(i in 1:4)plot(i)
par(mfrow=c(1,1))
and then scroll/resize.
Karline
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PLEASE do read the posting guide http://ww
Duncan,
Thank you for the "TAB for command suggestion" tip!
Tal
On Thu, Jul 2, 2009 at 2:17 PM, Duncan Murdoch wrote:
> On 02/07/2009 5:10 AM, Warren Young wrote:
>
>> Michael wrote:
>>
>>> I saw my friend has a R Console window which has automatic syntax
>>> reminder when he types in the fi
I suppose I should rephrase my question. What are good choices
available for writing user-interactive programs with R, preferably
over the command line. Most of my R scripts have not required user
interaction so this is a first for me.
On Wed, Jul 1, 2009 at 10:47 PM, Stephen J. Barr wrote:
> Hell
There is some material here (but not up to date):
http://www.sciviews.org/_rgui/
and a separate list here:
https://stat.ethz.ch/mailman/listinfo/r-sig-gui
On Thu, Jul 2, 2009 at 7:57 AM, Stephen J. Barr wrote:
> I suppose I should rephrase my question. What are good choices
> available for writing
I am not at all familiar with that distribution but the obvious
solution would appear to be:
?integrate
> BetaprimeDensity <- function(x) x^(shape1-1) * (1+x)^(-shape1-
shape2) / beta(shape1,shape2)
> shape1 <- 1
> shape2 <-1
> integrate(BetaprimeDensity, 0 , 1)
0.5 with absolute error < 5.6
First of all try str(socia) and see what the structure of the data is. R seems
to be interpreting that character string as a format If I am reading the error
message correctly.
--- On Wed, 7/1/09, Chris Anderson wrote:
> From: Chris Anderson
> Subject: [R] recoding charactor variables wit
On 7/2/2009 6:44 AM, Kenn Konstabel wrote:
On Thu, Jul 2, 2009 at 4:34 AM, Rolf Turner wrote:
On 2/07/2009, at 12:20 PM, Hsiu-Khuern Tang wrote:
Is this expected behavior?
z <- 1:5
z[1] <<- 0
Error in z[1] <<- 0 : object "z" not found
The documentation seems to suggest that z will be
Thank you for your reply. Your suggestion for sending this to another
list is probably the right one. I have just had so much wonderful
help on this one I thought I would try this one first. I am very new
to GIS and have a couple of years of experience with R. I will
probably join the sig-geo g
Hadley, Sunil, and list,
This is not quite doing what I wanted it to do (as far as I can tell). I
perhaps did not explain it thoroughly. It seems to be sampling one value
for each day leaving ~200 observations. I need for it randomly chose one hab
value for each bird if there is more than one val
On Thu, Jul 2, 2009 at 8:15 AM, James Martin wrote:
> Hadley, Sunil, and list,
>
> This is not quite doing what I wanted it to do (as far as I can tell). I
> perhaps did not explain it thoroughly. It seems to be sampling one value
> for each day leaving ~200 observations. I need for it randomly ch
On Wed, Jul 1, 2009 at 12:35 PM, miguel bernal
wrote:
>
> and debugging. I think there is a package to visualize the links between
> functions in a package, but I don't know its name (if anybody knows it, I
> will love to know it).
>
See the 'foodweb' function in the mvbutils package.
Kevin
Duncan Murdoch wrote:
<<- doesn't need to find z. It will replace it if found, or create a
new one if not. (Personally I would have limited that to the first
case, i.e. it should fail if it doesn't find z.)
Possibly. It's a holdover from S, where <<- assigns to the global
environment unc
I have a matrix such as this,
[,1] [,2] [,3]
[1,]112
[2,]255
and a larger matrix such as this,
a b
[1,] 1 5
[2,] 2 5
[3,] 4 9
[4,] 5 8
[5,] 7 8
[6,] 7 10
[7,] 9 10
what I want to do is check the number of times the columns in the first
matrix appear as r
Hi,
I drew a plot with R of my data and now I would like to display the
median values of each group
above the respective datapoint in the plot. I already search for ages,
but maybe I am just blind.
I am sure that this has to be an option somewhere...
I appreciate any kind of input!
Best,
C
Hi Guys,
It is very simple question, but I can't find the answer! Please help me.
I use R and such simple function as length() doesn't work. The result is
always 1 even if my data are more then 1 observations!
Do I have to load any additional library?
> length(Ret_1)
[1] 1
> length
function (x)
Hi,
Could you please help me?
I am trying to load an csv-file in R, but it works wrong!
My data is
0,0127
-0,0016
0,0113
0,0037
-0,0025
> Ret<-read.csv("Ret.csv")
> Ret
X0 X0127
1 016
2 0 113
3 037
4 025
Thank you in advance!
--
Best regards,
Andy
[[alte
Hi,
Thanks to Henrique and Prof. Spector for their kind reply. Indeed, the mean
function does work, but the result I want is an average data vector, not an
scalar, which is the output of mean(). This is, given these two data frames
(each data frame has 500 rows):
Time Pressure
0.0 100
1.0
Hi Andriy Fetsun,
How about include a "subject title" on the subject of the email like "length
funcion not work".
By the say, send us the result of str(your_object).
Bests
milton
brazil=toronto
On Thu, Jul 2, 2009 at 9:01 AM, Andriy Fetsun wrote:
> Hi Guys,
>
> It is very simple question, but
If A and B are first and second matrix respectively then try:
rowSums(inner(A, t(B), identical))
where the generalized inner product, inner, is defined in this post:
http://tolstoy.newcastle.edu.au/R/e4/help/08/08/19562.html
On Thu, Jul 2, 2009 at 8:27 AM, dreamworx wrote:
>
> I have a matrix s
If ?text does not answer the question, then you should post an example
that illustrates the problem.
--
DW
On Jul 2, 2009, at 8:46 AM, Christian Eisen wrote:
Hi,
I drew a plot with R of my data and now I would like to display the
median values of each group
above the respective datapoint i
On Jul 2, 2009, at 9:01 AM, Andriy Fetsun wrote:
Hi Guys,
It is very simple question, but I can't find the answer! Please help
me.
I use R and such simple function as length() doesn't work. The
result is
always 1 even if my data are more then 1 observations!
Do I have to load any addit
Thank you very much, the function i was looking for is the one Kevin points
out, "foodweb". I think that function, together with the whole
package "mvbutils" (which is somehow quite difficult to search for in CRAN!)
is one of the best productivity tools in R (if not the best!)
On Thursday 02 J
On Jul 2, 2009, at 6:47 AM, Andriy Fetsun wrote:
Hi,
Could you please help me?
I am trying to load an csv-file in R, but it works wrong!
My data is
0,0127
-0,0016
0,0113
0,0037
-0,0025
Ret<-read.csv("Ret.csv")
Ret
X0 X0127
1 016
2 0 113
3 037
4 025
?read.csv
Use scan:
scan("Ret.csv", dec = ",")
On Thu, Jul 2, 2009 at 7:47 AM, Andriy Fetsun wrote:
> Hi,
>
> Could you please help me?
>
> I am trying to load an csv-file in R, but it works wrong!
>
> My data is
>
>
> 0,0127
>
> -0,0016
>
> 0,0113
>
> 0,0037
>
> -0,0025
>
>
> > Ret<-read.csv("Ret.csv"
Hi,
I'm trying to read several Excel sheets from an Excel file into a
list. I'm using
read.xls from package 'gdata'. I would like to know how I can
check the number of sheets before the loop (in the example below) so
that I could adjust the loop counter? Any suggestions?
DF.list <- list()
for (i
Hi,
I drew a plot with R of my data and now I would like to display the
median values of each group
above the respective datapoint in the plot. I already search for
ages, but maybe I am just blind.
I am sure that this has to be an option somewhere...
Perhaps we could provide better input
ddply(df, c("date", "id"), function(df) df[sample(nrow(df), 1), ])
Thanks to Hadley and Sunil. The above code solves my problem.
jm
On Mon, Jun 29, 2009 at 9:11 AM, James Martin wrote:
> All,
>
> I have data that looks like below. For each id there may be more than one
> value per day. I want
Well, what's Ret_1 ? It's hard to answer your question without that crucial
bit of information.
Try
str(Ret_1)
and let us know what it says.
My first guess is that Ret_1 is a list, e.g.:
> testdata <- list(f1=c(1,2,3,4))
> length(testdata)
[1] 1
> length(testdata[[1]])
[1] 4
> str(testdata)
List
Andriy Fetsun wrote:
Hi,
Could you please help me?
I am trying to load an csv-file in R, but it works wrong!
See ?read.csv and about decimal different characters.
Uwe Ligges
My data is
0,0127
-0,0016
0,0113
0,0037
-0,0025
Ret<-read.csv("Ret.csv")
Ret
X0 X0127
1 016
2
As an R beginner, I feel brain dead today as I can not find the answer
to a relatively simple question.
Given a array of string values, for example lets say "mary", "bob",
"danny", "sue", and "jane".
I am trying to determine how to perform a logical test to determine if
a variable is an e
On 7/2/2009 9:46 AM, Peter Dalgaard wrote:
Duncan Murdoch wrote:
<<- doesn't need to find z. It will replace it if found, or create a
new one if not. (Personally I would have limited that to the first
case, i.e. it should fail if it doesn't find z.)
Possibly. It's a holdover from S, wher
Try this:
c("mary", "sue") %in% c("mary", "bob", "danny", "sue","jane")
On Thu, Jul 2, 2009 at 11:13 AM, Neil Tiffin wrote:
> As an R beginner, I feel brain dead today as I can not find the answer to a
> relatively simple question.
>
> Given a array of string values, for example lets say "mary"
Peter,
Try this:
apply(do.call(merge, c(loadfiles, by = "Time"))[2:3], 1, mean)
On Thu, Jul 2, 2009 at 10:39 AM, Peter Perez wrote:
>
> Hi,
>
> Thanks to Henrique and Prof. Spector for their kind reply. Indeed, the mean
> function does work, but the result I want is an average data vector, not
On Jul 2, 2009, at 9:13 AM, Neil Tiffin wrote:
As an R beginner, I feel brain dead today as I can not find the
answer to a relatively simple question.
Given a array of string values, for example lets say "mary", "bob",
"danny", "sue", and "jane".
I am trying to determine how to perform a
On Jul 2, 2009, at 7:27 AM, dreamworx wrote:
I have a matrix such as this,
[,1] [,2] [,3]
[1,]112
[2,]255
and a larger matrix such as this,
a b
[1,] 1 5
[2,] 2 5
[3,] 4 9
[4,] 5 8
[5,] 7 8
[6,] 7 10
[7,] 9 10
what I want to do is check the number of tim
Worked like a champ.
Thank you.
Neil
On Jul 2, 2009, at 9:20 AM, Henrique Dallazuanna wrote:
> Try this:
>
> c("mary", "sue") %in% c("mary", "bob", "danny", "sue","jane")
>
> On Thu, Jul 2, 2009 at 11:13 AM, Neil Tiffin
> wrote:
> As an R beginner, I feel brain dead today as I can not find t
Hi,
I am trying to load an csv-file in R, but it works wrong!
My data is
0,0127
-0,0016
0,0113
0,0037
-0,0025
Ret<-read.csv("Ret.csv")
Ret
X0 X0127
1 016
2 0 113
3 037
4 025
This looks correct to me. The read.csv function assumes the first line
in the file is a
On Thu, Jun 18, 2009 at 12:08 PM, Dirk Eddelbuettel wrote:
>
> On 18 June 2009 at 09:36, Bert Gunter wrote:
> | -- or Chapter 4 in S PROGRAMMING? (you'll need to determine if it's "reader
> | friendly")
>
> +1
>
> It helped me a lot too back in the day. But I am wondering if there are good
> curre
Andriy,
It does exactly what you want it to do. So if the result is not what you
expected, then you are supplying R with a wrong command.
If you would have read the helpfile of read.csv you would have noticed
the sep and dec argument would be very useful in this case.
Thierry
-
Hi,
So far my plotting needs have been sort of ignored as I got
acquainted with R this week, but now that I have the basics in place
for the program I wanted to write it's time for me to start learning
about how to make output that better suits my needs. I think I have
two sort of charts I need
On 2 July 2009 at 09:13, Neil Tiffin wrote:
| Given a array of string values, for example lets say "mary", "bob",
| "danny", "sue", and "jane".
|
| I am trying to determine how to perform a logical test to determine if
| a variable is an exact match for one of the string values in the array
Madan,
I "did" tell you in my previous email about what you should do. Did you try
my suggestions? Did any of them work for you? If not, please send me the
details of what you tried and what the results were.
Ravi.
Dear Martin,
I have been playing a lot with the glkerns() function in the "lokern"
package for "automatic" smoothing of time-series data. This kernel
smoothing approach of Gasser and Mueller seems to perform quite well for
estimating the function and its derivatives (first and second derivatives
Putting your two queries together [see revised Subject ... ]:
[R] (no subject)^1:
Could you please help me?
I am trying to load an csv-file in R, but it works wrong!
My data is
0,0127
-0,0016
0,0113
0,0037
-0,0025
>
> Ret
X0 X0127
1 016
2 0 113
3 0
Here is another approach :
rowmatch.count <- function(a,b) {
f <- function(...) paste(..., sep=":")
a2 <- do.call("f", as.data.frame(a))
b2 <- do.call("f", as.data.frame(b))
c(table(c(a2,unique(b2)))[b2] - 1)
}
# example
a <- matrix(c(1,2,1,5,2,5), 2, 3)
b <- matrix(c(1,2,4,5,7
-- (The Windows GUI does have syntax completion
using TAB, but not the hints.)
I never knew that! Where is this documented? -- i.e. where are all the
features of the Windows GUI documented (as there may well be others I don't
know about).
-- Bert Gunter
Genentech Nonclinical Statistics
___
Try this:
library(RDCOMClient)
xl <- COMCreate("Excel.Application")
xl$Workbooks()$Open("teste.xls")$Sheets()$Count()
On Thu, Jul 2, 2009 at 11:22 AM, Lauri Nikkinen wrote:
> Hi,
>
> I'm trying to read several Excel sheets from an Excel file into a
> list. I'm using
> read.xls from package 'g
Hi,
On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
Hi,
So far my plotting needs have been sort of ignored as I got
acquainted with R this week, but now that I have the basics in place
for the program I wanted to write it's time for me to start learning
about how to make output that better s
Try
hf$hour <- as.POSIXlt(hf$date)$hour
hf$month <- as.POSIXlt(hf$date)$mon+1
To see why, use the man pages to study the structure of POSIXlt objects. Try:
tmp <- strptime("20/2/06 11:16:16.683", "%d/%m/%y %H:%M:%OS")
unclass(tmp)
For example:
tmp <- strptime("20/2/06 11:16:16.6
On 7/2/09, Steve Lianoglou wrote:
> Hi,
>
> On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
>
>
> > Hi,
> > So far my plotting needs have been sort of ignored as I got
> > acquainted with R this week, but now that I have the basics in place
> > for the program I wanted to write it's time for me
I have recently discovered the "playwith" library, which is great for
creating complex lattice objects.
If you start with a simple lattice plot then modify it using playwith, you
can export the code to produce the spiffed up plot.
I noticed this function at the bottom of the xyplot documentation i
On Jul 2, 2009, at 11:26 AM, Mark Knecht wrote:
On 7/2/09, Steve Lianoglou wrote:
Hi,
On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
Hi,
So far my plotting needs have been sort of ignored as I got
acquainted with R this week, but now that I have the basics in place
for the program I want
If you are on Windows and have Excel on the same machine
then the code here:
http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7736.html
will return the number of worksheets as well as a vector of
the worksheet names.
It seems that the email has somehow caused some of the
lines to wrap so you will
Is there a command as "mat.or.vec(nr,nc)" to create an array that I must
calculate with more cicle?
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PLEASE do read the posting
On 7/2/2009 10:53 AM, Bert Gunter wrote:
-- (The Windows GUI does have syntax completion
using TAB, but not the hints.)
I never knew that! Where is this documented? -- i.e. where are all the
features of the Windows GUI documented (as there may well be others I don't
know about).
The CHA
On 7/2/09, Mark Knecht wrote:
> On 7/2/09, Steve Lianoglou wrote:
> >
> > In particular, the graph below looks *somehow* similar to the chart you
> > link to.
> >
> > http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=109
>
> What a great site! Thanks!
>
> The chart you point
On 2 July 2009 at 11:14, Steve Lianoglou wrote:
| On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
| > 2) The closest example of the second would be a multi-study chart sort
| > of like is typical in a lot of stock charting programs. Here's (I
| > hope) a simple example:
| >
| > http://stockcharts.
Dear R users,
I 'm working on a dataset consisting of 4 different dataframes with
tree, leaf, fruit and seed measurements made on 300 trees, coming from
10 provenances (30 trees per provenance, 10 leaves/fruits/seeds per
tree). Provenances are fixed effects (they were not randomly chosen),
but
plot.zoo and xyplot.zoo in the zoo package both produce
multipanel plots with one panel per series (or optionally
all on one panel or a mixture).
library(zoo)
example(plot.zoo)
example(xyplot.zoo)
and see the three zoo vignettes.
The quantmod package has charting specifically oriented to
securit
Hi,
On Jul 2, 2009, at 11:26 AM, Mark Knecht wrote:
On 7/2/09, Steve Lianoglou wrote:
[snip]
One thing you could do is to peruse the R Graph Gallery to see what
people
can do:
http://addictedtor.free.fr/graphiques/
In particular, the graph below looks *somehow* similar to the chart
you
On 7/1/09, seeliger.c...@epamail.epa.gov wrote:
> > ... I saw my friend has a R Console window which has automatic syntax
> > reminder when he types in the first a few letters of R command. ...
>
> You might be thinking of JGR (Jaguar) at
> http://jgr.markushelbig.org/JGR.html . This editor als
On 7/2/09, Dirk Eddelbuettel wrote:
>
> On 2 July 2009 at 11:14, Steve Lianoglou wrote:
> | On Jul 2, 2009, at 10:39 AM, Mark Knecht wrote:
>
> | > 2) The closest example of the second would be a multi-study chart sort
> | > of like is typical in a lot of stock charting programs. Here's (I
> |
Hi,
On Jul 2, 2009, at 11:13 AM, barbara.r...@uniroma1.it wrote:
Is there a command as "mat.or.vec(nr,nc)" to create an array that I
must calculate with more cicle?
I'm not sure your question is very clear: what do you mean by
"calculate with more cicle"?
Could you give an example of wh
Hello! Just want to get some suggestions on which R package is good
for analyzing time course microarray data. Thank you so much for your
input!
Sincerely,
Allen
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ht
i want to estimate parameters with maximum likelihood method with contraints
(contant numbers).
for example
sum(Ai)=0 and sum(Bi)=0
i have done it without the constraints but i realised that i have to use the
contraints.
Without constraints(just a part-not complete):
skellamreg_LL=function(pa
A second possibility (not as automated but very simple to do)
is to read the first sheet with verbose = TRUE:
DF <- read.xls("test.xls", sheet = 1, verbose = TRUE)
and it will display the number of sheets in a message.
You can then read them in in a loop.
On Thu, Jul 2, 2009 at 11:05 AM, Gabor
Hi,
I am working with -poLCA- which uses the package -scatterplot3d- in
order to work. However, I work on a restricted server that is not
online. The R-version installed there is 2.6. However, running
library(poLCA) after installing the most recent -scatterplot3d- on the
server leaves me with R te
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