Dear Sir
I have a technical problem on an ordinal probit regression with IV. In the
first stage, my dependent variable is dummy variable. I predict this
endogenous variable,and the predict value is continuous. However, my model
in the second stage is DID model, that is this endogenous variable must
Hi.
I was used to draw 2D plot to show distribution of my samples. It was very
powerful in small samples.
Recently , I handle a lot of type of samples as more 15.
so, I want to use more dimention.
I was used that I conduct plsda function and draw biplot, such as,
p1=plsda(mw, sp)
biplot(p1)
Here is a good website that will help you if you are struggling.
http://www.mayin.org/ajayshah/KB/R/index.html
Cheers
Malcolm
[[alternative HTML version deleted]]
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Hi all,
I have a relative large amount (several thousand rows, but a small
amount of unique objects) of data in a format like this:
1 text_string
1 text_string
1 text_string
2 text_string
2 text_string
3 text_string
3 text_string
3 text_string
3
Hi,
I am looking for a R package to draw 3d plot. But not in a static way like
scatterplot3d or stuff like that. I would like to make rotate the plot, to
zoom/unzoom etc..., actually to render the graph 'dynamic'... (for the
biologist and bioinformatician, a R package which permitts to reprodu
Dear Tena,
As I am a WinXP user I have no expercience with Linux. I would suggest
you try the plot on a pdf device. pdf does support transparancy (at
least on windows and for pdf version >= 1.4).
HTH,
Thierry
ir.
Hi,
I have a question regarding how to get some partial information
from the output of rpart, which could be used as the first argument to
predict. For example, in my code, I try to learn a stump tree (decision
tree of depth 2):
"fit <- rpart(y~bx, weights = w/mean(w), control = cntrl)
Hi,
You want something like this?
library (pls)
data(yarn)
library (scatterplot3d)
yarn.pls <- plsr(density ~ NIR, 6, data = yarn, validation = "CV")
palette (rainbow(length(yarn$density)))
scatterplot3d
(yarn.pls$scores[,1:3],pch=16,color=1:length(yarn$density),cex.symbols=2)
?scatterplot3d
Hi,
I am new to R. I have two questions about plotting in R:
1. How to plot several lines in a figure? Suppose I have several sets of
points (xi,yi), where xi and yi are equal-length vector. plot(x1,y1) will
give a line connecting these points. Another plot(x2,y2) will erase what
plot before and
On 08/05/2009 2:27 AM, Yihui Xie wrote:
Homework?...
Looks like it, and also what we call "academic misconduct" here. It
would be enough to get a student expelled...
Duncan Murdoch
Regards,
Yihui
--
Yihui Xie
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Home
Hi, I try to ask here, because I hope someone will help me understand this
problem-
I have fittet a glm in R with the results
> glm1 <-
> glm(log(claims)~log(sum)*as.factor(grp),family=gaussian(link="identity"))
> summary(glm1)
Call:
glm(formula = log(claims) ~ log(sum) * as.factor(grp), family
ayaku1...@gmail.com wrote:
There are six assignments in total. It won't take you long if you were
familiar with R. For those who are interested, please send me an email
with your profile (your experience with R, how long and how often have
you been using it.) I will be paying through paypal. Th
Hi,
I have the following vectors:
v1 <- rep( LETTERS[ 1:4 ], each = 5)
v2 <- c( letters[ 1:10 ], letters[ 1:10 ] )
Notice that:
> tapply( B, A, I )
$A
[1] "a" "b" "c" "d" "e"
$B
[1] "f" "g" "h" "i" "j"
$C
[1] "a" "b" "c" "d" "e"
$D
[1] "f" "g" "h" "i" "j"
Here we can see there are two
> 1. How to plot several lines in a figure? Suppose I have several sets of
> points (xi,yi), where xi and yi are equal-length vector. plot(x1,y1)
will
> give a line connecting these points. Another plot(x2,y2) will erase what
> plot before and plot the new line. Can I have these lines all drawn in
Dear list members,
After looking in the www, I found this subject has been in discussion
previously on the mailing list, although I could not solve it. I also
found two wikis, but similarly, could not reach a conclusion.
I need to re-produce my figures with 1200 dpi, in tiff format, for a
jo
if (typeof YAHOO == "undefined") {
var YAHOO = {};
}
YAHOO.Shortcuts = YAHOO.Shortcuts || {};
YAHOO.Shortcuts.hasSensitiveText = false;
YAHOO.Shortcuts.sensitivityType = [];
YAHOO.Shortcuts.doUlt = false;
YAHOO.Shortcuts.location = "
Dear R-users,
To test the effect of training (a time-varying qualitative
covariate) on the transition to management rate by means
of event history models, I would like to split my data by
the training date.
Excerpt of my data:
StatusN Duration DummyOtherEp TimingOtherTraining
1 0
Hi Martial,
The rgl package is quite nice for this sort of thing:
# this is the example in ?plot3d
library(rgl)
open3d()
x <- sort(rnorm(1000))
y <- rnorm(1000)
z <- rnorm(1000) + atan2(x,y)
plot3d(x, y, z, col=rainbow(1000))
HTH,
Tony Breyal
On 8 May, 09:25, Martial Sankar wrote:
> Hi,
>
>
Dear Administrator,
I am using linux (suse 10.2). While attempting rfImpute, I am getting the
following error message:
> Members <- rfImpute(Status ~ ., data = Members)
Error in .C("classRF", x = x, xdim = as.integer(c(p, n)), y =
as.integer(y), :
C symbol name "classRF" not in DLL for packag
tognox wrote:
Hi,
I would need some help in solving a problem with my R.
Whenever I try to type " ?paste " or in general any command for the html
help in R, I receive this error message. The strange thing is that I have
never had this kind of problem in the past with R, and now I really don't
u
Is this what you want:
> x <- data.frame(n=sample(10, n, TRUE), text=sample(LETTERS, n, TRUE))
> table(x$text, x$n)
1 2 3 4 5 6 7 8 9 10
A 6 5 2 0 8 1 5 3 6 4
B 2 2 5 2 2 7 5 4 4 5
C 7 4 6 4 3 6 3 6 5 4
D 9 5 1 6 3 1 3 2 6 3
E 2 6
Marta M. Rufino wrote:
Dear list members,
After looking in the www, I found this subject has been in discussion
previously on the mailing list, although I could not solve it. I also
found two wikis, but similarly, could not reach a conclusion.
I need to re-produce my figures with 1200 dpi,
Shame on you!
Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147
Find the values that are missing a comma and add it:
> dat <- c("Tue, 15 Nov 2005 09:44:50 EST",
+ "15 Nov 2005 09:10:00 +0100",
+ "Tue, 15 Nov 2005 09:44:50 EST",
+ "Tue, 15 Nov 2005 16:29:57 +",
+ "Wed, 16 Nov 2005 07:00:45 EST",
+ "Wed, 16 Nov 2005 05
Interesting. Now the fifth homework question you have posted here. As was
stated before (by several members) this is not a homework forum.
Patrick
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of mathallan
Sent: Friday, May 08, 2
--- begin included message --
Hi,
I have a question regarding how to get some partial information
from the output of rpart, which could be used as the first argument to
predict. For example, in my code, I try to learn a stump tree (decision
tree of depth 2):
"fit <- rpart(y~bx, weights
Try re-starting R, load the randomForest package, and then run
example(rfImpute) and see if that works. Can you post your
sessionInfo() output?
Andy
From: cosmos science
>
> Dear Administrator,
>
> I am using linux (suse 10.2). While attempting rfImpute, I am
> getting the
> following error
> There are six assignments in total. It won't take you long if you were
> familiar with R. For those who are interested, please send me an email
> with your profile (your experience with R, how long and how often have
> you been using it.) I will be paying through paypal. Thanks!
Now see, you mad
at least he/she is resourceful! (but also very naughty)
- Original Message -
From:
To:
Cc: ;
Sent: Friday, May 08, 2009 12:48 PM
Subject: Re: [R] I'm offering $300 for someone who know R-programming to
dothe assignments for me.
Shame on you!
Steve Friedman Ph. D.
Spatial Stat
Hi,
ich have a List of measured valuepairs (w, AmpNorm) and a formula
f(w, a, b) = AmpNorm
i used nls to find the two coefficiants a and b:
ctfit.nls <- nls(AmpNorm ~ 1/(1 + (w * a - b /w)^2) ...)
R> ctfit.nls returns
Nonlinear regression model
model: AmpNorm ~ 1/(1 + (w * a - b /w)^2)
Dear colleagues,
Thank you for the reply.
Einer:
I tried to so, but I had an error:
"Error in system(paste(gsexe, "-help"), intern = TRUE, invisible = TRUE)
: gswin32c.exe not found"
I think would need "|ghostscript|" (in the help file:
"You will need |ghostscript|: the full path to the executa
Hi,
fp is a data frame like this
,[ fp ]
|Frequenz AmpNorm
| 1 3322 0.0379490639
| 2 3061 0.0476033058
| 3 2833 0.0592954124
| 4 2242 0.1275510204
`
i want to find the "Frequenz" where "AmpNorm" is max.
I use this line as workaround:
PeakFreqHz = subset(fp,
You are trying to test the equality of a matrix to a scalar, which
will produce a logical vector. You are also using && in an apparent
attempt to conjoin a complex object which will probably not give you
the results you expect in that context either since it would only
return a single TRUE
Thank you so much!
It seems that fit$splits[1,] does not contain the feature ID:
"> fit$splits[1,]
count ncat improve index adj
124.000 -1.000 0.3437644 13.500 0.000 "
However help(rpart.object) says:
" splits: a matrix describing the splits.
The venom from everyone is to be expected here ayaku. While
scientific listservs are a bad place to ask for people to do your
homework, they are great for getting advice and soliciting tutors. R
is a great program and a lot of fun to learn. Why not put your money
to better use and hire a local t
try this:
with(fp, Frequenz[which.max(AmpNorm)])
baptiste
On 8 May 2009, at 14:49, Jonas Stein wrote:
Hi,
fp is a data frame like this
,[ fp ]
|Frequenz AmpNorm
| 1 3322 0.0379490639
| 2 3061 0.0476033058
| 3 2833 0.0592954124
| 4 2242 0.1275510204
`
i
Hi,
you could use which.max().
> fp$Frequenz[which.max(fp$AmpNorm)]
I found the reference in the max() help.
Lasse
Am Freitag, den 08.05.2009, 14:49 +0200 schrieb Jonas Stein:
> Hi,
>
> fp is a data frame like this
>
> ,[ fp ]
> |Frequenz AmpNorm
> | 1 3322 0.0379490639
> | 2
> fp is a data frame like this
>
> ,[ fp ]
> |Frequenz AmpNorm
> | 1 3322 0.0379490639
> | 2 3061 0.0476033058
> | 3 2833 0.0592954124
> | 4 2242 0.1275510204
> `
>
> i want to find the "Frequenz" where "AmpNorm" is max.
Use which.max.
fp <- data.frame(Freqe
On Fri, May 08, 2009 at 01:45:22PM +0100, Marta M. Rufino wrote:
> "Error in system(paste(gsexe, "-help"), intern = TRUE, invisible = TRUE)
> : gswin32c.exe not found"
> I think would need "|ghostscript|" (in the help file:
>
> "You will need |ghostscript|: the full path to the executable can be
Thanks for the tip. That lead me to find this paper:
http://www.ualberta.ca/~baayen/publications/baayenDavidsonBates.pdf
which looks like it will answer my problem. Depending on how we
actually decide to execute the test it might turn out to be nested
like those other examples, but it's nice to
Dear Jonas,
Try this:
with(fp, Frequenz[ which.max(AmpNorm) ] )
HTH,
Jorge
On Fri, May 8, 2009 at 8:49 AM, Jonas Stein wrote:
> Hi,
>
> fp is a data frame like this
>
> ,[ fp ]
> |Frequenz AmpNorm
> | 1 3322 0.0379490639
> | 2 3061 0.0476033058
> | 3 2833 0.059295
Hello,
I am new to this list and rather new to graphics with R.
I would like to make a chart like Gantt chart, something like that:
require (plotrix)
Ymd.format<-"%Y/%m/%d"
gantt.info<-list(labels=c("Male 1","Male 1","Male 1", "Male 2", "Male 2"),
starts=as.POSIXct(strptime(c("2004/01/01","2004/0
Thanks!
I am now also trying to plot several ROCs in the same figure using ROCR
package. The following code:
"pred1 <- prediction(yest1,ytest)
perf1 <- performance( pred1, "tpr", "fpr" )
plot( perf1 )
pred2 <- prediction(yest2,ytest)
perf2 <- performance( pred2, "tpr", "fpr" )
lines( perf2 )"
wi
Taking a quick gander at RServe — interesting.
I think that some of the magic RSPerl is doing in munging R data types
into Perl constructs is the tricky part of the exercise. While I like
the close binding to R itself that RSPerl uses, going through an
intermediary like RServe might prove easier
again, the bioconductor list is appropriate. You'll want to be sure to
update your packages using the instructions at
http://bioconductor.org/docs/install/
and be sure to provide the output of
sessionInfo()
to make any actual problems easier to track down.
Martin
George Chen writes:
> H
George Chen writes:
> Hi All,
>
> I have microarray data that does not come in a CEL file. Currently it is in
> the form of columns = individual samples and rows = individual probes. There
> are about 79 columns and it is in a tab delimited text file. Is there a way
> to convert this file i
Dear users,
another question concerning graphics for publications. My favourite journal
wants .eps-graphics,
and from older postings i adapted the following code:
postscript(file="Figure1.eps", title="Figure 1", width=11.5, height=8,
paper="a4",onefile=FALSE)
However, when checking the proper
Can anyone help me on how to get the nodes and weights of the adaptive
quadrature
using R.
Best wishes
Boikanyo.
-
The University of Glasgow, charity number SC004401
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-he
well..why shame? He doesn't say it's a homework really.
On May 8, 4:48 am, steve_fried...@nps.gov wrote:
> Shame on you!
>
> Steve Friedman Ph. D.
> Spatial Statistical Analyst
> Everglades and Dry Tortugas National Park
> 950 N Krome Ave (3rd Floor)
> Homestead, Florida 33034
>
> steve_fried...@n
Hi,
I`m trying to put my superscript type in bold style. Could somebody help me?
My text is inside a barplot.
#!/bin/Rbarplot(x, ylab=expression(paste("org.", cm^-2)))
# so I tried this way,
*barplot(x, ylab=expression(bold(paste("org.", cm^-2* # but my
superscript maintain its shape in re
Dear list,
Apparently, there is no function like sscanf in R.
I have a string, "Condition: 311", and I would like
to read out the number and store it to a numeric
variable. Is there an easy way to do this?
Best wishes,
Matthias
--
__
R-help@r-project
To have several performance curves on a single plot, use the
"add=TRUE" option, e.g. as follows:
plot(perf1)
plot(perf2, add=TRUE, col='red')
Please read the help to ?plot.performance. It also tells you how you
can adjust all graphical parameters for the individual curves.
This slide deck contain
Tung86 wrote:
> well..why shame? He doesn't say it's a homework really.
>
indeed; while it might of course have been a serious offer, i can't get
rid of the feeling that what we see could also be a deliberate -- and
quite successful -- provocation, and that the author might be now having
lots
I bet at least a few people offered their services! It might be an
undercover sting operation to weed out the unethical amongst us :-)
- Original Message -
From: "Wacek Kusnierczyk"
To: "Tung86"
Cc: "R help"
Sent: Friday, May 08, 2009 3:18 PM
Subject: Re: [R] I'm offering $300 for
Hi Henning,
maybe you just lost the extension (.eps) of the file when "converting"
it with ghostview. But R postscript(..,onefile=FALSE) produces actually
an eps compatible file.
An (encapsulated) postscript file is a vector based file format, so
there isn't such a thing as a "resulution", sin
Wacek raises a very valid perspective. I have previously not responded to
these requests, and I've seen a bunch. I have thought they were a waste of
my time to respond to. In the future I think I'll simpy disregard these
requests, because I simply can not "crystal ball" the true needs of the
or
I would have expected that Sarkar's response to a similar question
about dotplot offered yesterday ought to have a good chance of
answering this question. Search on dotplot:
"labeling coordinates for each point"
--
David Winsemius
On May 8, 2009, at 1:13 AM, kulwinder banipal wrote:
I am
On Fri, 2009-05-08 at 15:47 +0200, Henning Wildhagen wrote:
> Dear users,
>
> another question concerning graphics for publications. My favourite journal
> wants .eps-graphics,
> and from older postings i adapted the following code:
>
> postscript(file="Figure1.eps", title="Figure 1", width=11.5
On Thursday, May 07, 2009 7:45 PM, David Freedman wrote:
> ...how about:
> d=data[order(data$ID,-data$Type),]
> d[!duplicated(d$ID),]
Does the "-data$Type" argument to the order function work?
--
David
-
David Huffer, Ph.D.
On Fri, May 8, 2009 at 12:19 AM, ayaku1...@gmail.com
wrote:
> There are six assignments in total. It won't take you long if you were
> familiar with R. For those who are interested, please send me an email
> with your profile (your experience with R, how long and how often have
> you been using it
You can always use regular expressions:
> x <- "Condition: 311"
> as.integer(sub(".*?(\\d +).*", "\\1 ", x,
perl=TRUE))
[1] 311
>
On Fri, May 8, 2009 at 10:16 AM, Matthias Gondan wrote:
> Dear list,
>
> Apparently, there is no function like sscanf in R.
>
> I have a string, "Condition: 311", an
Hi there,
I'm not certain if this is the correct list where to post this question, or if
it ought to be on the R developper one... I am trying to use the RGoogleDocs
package to import into R the spreadsheets on my Google docs account. I
downloaded the latest package (0.2.0) and installed it. I
>>> lehe 08/05/2009 09:58:40 >>>
>1. How to plot several lines in a figure?
See ?lines
>2. How to open another figure window?
see ?windows
***
This email and any attachments are confidential. Any use...{{dropped:8}}
_
Hi Tony,
Am Freitag, den 08.05.2009, 14:06 +0100 schrieb Tony Breyal:
> Hi mate,
>
> i think you mistakenly emailed this message only to me rather than the
> whole list.
>
> Tony.
Thank you for forwarding my mail to the list. I post to seldom to
r-help. And I am used from other mailing list
Hello,
I'm attempting to alter the location of text in my axis labels in
lattice plots and have been unsuccessful so far. For example, the
y-axis labels are always right-justified, but I would like them to be
horizontally centered.
Here's an example:
library(lattice);
# create fake data
Found an answer here, don't know if anyone's implemented it for R though.
www.iop.org/EJ/article/0022-3735/22/4/002/jev22i4p215.pdf
James
Gerard M. Keogh wrote:
> James,
>
> look up "errors in variables" models or "instrumental variable" models in
> econometrics.
>
> The statistics alternative
Hi all,
I'm searching for a little clarification on partial mantel tests
(ecodist package)
I've a distance matrix (x,y), and several others containing
environmental/chemical variables.
Based on the help file, and the package instructions I've managed to
implement the tests as;
var1 ~ en
Hi,
I need to make a plot of data from multiple epochs, and so I'd need to
introduce a couple of breaks in the x-axis not to have too many empty space in
my plot.
I discovered a function in the package "plotrix" which makes breaks in axis,
but it is not what I was actually looking for, becaus
On Fri, May 8, 2009 at 4:06 PM, Mitchell Maltenfort wrote:
> And the crazy thing is that if he went to Amazon and ordered 2 R books
> with one-day shipping, he could do it himself and probably spend half
> as much.
And the crazier thing is that if homework cheats "lurked moar" then
they could p
Hi David,
On Fri, May 8, 2009 at 10:27 AM, wrote:
> My questions are as follows;
>
> 1) can "raw" data be used to construct the dissimilarity matricies? or
> should they be standardized? different variables have different measurment
> scales, my inclination is to standardize, but I don't know i
If plotrix does not help, you need to be mroe specific and give an
example as the posting guide asks you to do anyway.
Uwe Ligges
BARRES-DE-ALMEIDA U. wrote:
Hi,
I need to make a plot of data from multiple epochs, and so I'd need to
introduce a couple of breaks in the x-axis not to have to
mcnda...@mncn.csic.es wrote:
Hi guys,
I already have put this question some time ago however replies were not
straight to the problem. Even so thanks a lot for the answers!
I reformulate the problem.
I have a script file with the following commands:
for (i in 1:300)
- open session --> loa
Dear all,
I am trying to calculate barriers with the monmonier algorithm
(adegenet).
mon1 <- monmonier(mycoordinates, mydistancamatrix, network$cn, ...)
The network beforehand looked alright. However, I always get the error:
"cn is not a nb object". I am not really sure what this means, probably
Marta M. Rufino wrote:
Dear colleagues,
Thank you for the reply.
Einer:
I tried to so, but I had an error:
"Error in system(paste(gsexe, "-help"), intern = TRUE, invisible = TRUE)
: gswin32c.exe not found"
I think would need "|ghostscript|" (in the help file:
"You will need |ghostscript|:
For question 2, dev.new (in more recent versions) will start a new instance of
the default device (which are the ones listed below), but in a cross-platform
way (so you don't need to remember all 3, and code will work on the other
platforms).
A link to dev.new should probably be included in the
Some options:
The rgl package
The Rggobi package (along with the ggobi program)
The rotate.cloud function in the TeachingDemos package (or tkexamp in the same
package for a way to GUIize your favorite plot)
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s
On Fri, May 8, 2009 at 7:07 AM, Boikanyo Makubate
wrote:
> Can anyone help me on how to get the nodes and weights of the adaptive
> quadrature
> using R.
You need to be more specific about which quadrature formula. I'm
guessing that you probably have Gauss-Hermite quadrature in mind
because it
Thank you Deepayan! It works perfectly.
Best,
Tony
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Deepayan Sarkar
Sent: Thursday, May 07, 2009 12:20 PM
To: Qifei Zhu
Cc: r-help@r-project.org
Subject: Re: [R] dotplot: labeling coor
Marta
You have to install ghostscript and update your R to the latest version.
Here is a test function I used when trying this out a while ago. You could
plot different parts of your figure using a similar approach. The bitmap
option of my function dropped colors from the lattice panels. However
Beyond what Doug said, if you have a specific R function that does
adaptive quadrature, you could read the code for that function. You can
get that without comments by typing the function name at a commands
prompt. To get the source code with comments, you can download the
appropriate so
Hello,
I am trying to use the plm package for panel econometrics. I am just
trying to get started and load my data. It seems from most of the
sample documentation that I need to use the pdata.frame function to
get my data loaded. However, even after installing the "plm" package,
my R installation
Simon Pickett wrote:
> I bet at least a few people offered their services! It might be an
> undercover sting operation to weed out the unethical amongst us :-)
>
... written by some of the r core developers?
vQ
__
R-help@r-project.org mailing list
http
If I wanted to fit a logit model and account for clustering of observations, I
would do something like:
library(Design)
f <- lrm(Y1 ~ X1 + X2, x=TRUE, y=TRUE, data=d)
g <- robcov(f, d$st.year)
What would I do if I wanted to do the same thing with a probit model?
?robcov says the input model mus
Hi list,
Would someone please give me a hint how to extract the between and within
subject StdDev from "lme" fit? Below is the output from the fit, but I couldn't
find the number 0.3927714 anywhere in the fitted object. Thanks in advance for
your help!
Random effects:
Formula: ~1 | group
Robert Schneider wrote:
Hi there,
I'm not certain if this is the correct list where to post this question, or if it ought to be on the R developper one... I am trying to use the RGoogleDocs package to import into R the spreadsheets on my Google docs account. I downloaded the latest package (0.
Auston wrote:
Hi list,
Would someone please give me a hint how to extract the between and within
subject StdDev from "lme" fit? Below is the output from the fit, but I couldn't
find the number 0.3927714 anywhere in the fitted object. Thanks in advance for
your help!
Random effects:
Formula: ~
I'm having trouble to install RGtk2 (from source) on Mac OS 10.4.11 (R
2.9.0). The GTK libraries (2.12.11) were installed into /sw/lib via
fink. Even if I set the GTK_LIBS to that path, the installation program
doesn't seem to find it (see below). libglade is there too but not found.
If I inst
Hi,
I'm trying to get Rmysql to work o windows server 2008 64-bit.
I have the latest build of mysql installed (mysql-5.1.34-winx64).
When trying to load Rmysql, I got a warning that Rmysql is linking to an
old-ish mysql build (5.0.67).
I could do some basic stuff (the connection works) but it bre
On Thu, May 7, 2009 at 10:13 PM, kulwinder banipal wrote:
>
> I am trying to display data ion top of colored rectangle on the same
> levelplot. While using superpose the shape and symbol for levelplot changes
> to small circle. I am unable to figure what exactly I am doing wrong... It
> may be
Dear Luc,
Thank you so much for your help! The VarCorr() did the trick. Many thanks!
Best,
Auston
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guid
Please use R-sig-mac for Mac OS X questions, as the posting guide asks.
But there is a binary of Gtk2 on r.research.att.com that matches the
binary RGtk2 package on CRAN, and that worked for me earlier today.
Mixing fink (or darwinports) with the binary R distribution is warned
against in the
Also works as expected on the MacOSX 64 bit binary for R 2.8.1
(patched).
On May 5, 2009, at 4:06 PM, jim holtman wrote:
Seems to work fine for me on R 2.9.0:
as.POSIXct("2009/03/26 01:00:00 AM" , format="%Y/%m/%d %I:%M:%S %p" )
[1] "2009-03-26 01:00:00 GMT"
as.POSIXct("2009/03/26 01:00:0
Hi,
It seems that if I make a change to the .Rprofile file in my working
directory, it is not immediately reflected when the session is
restarted. (I am using statET and rJava)
Is that something I should expect?
Thanks,
#T
__
R-help@r-project.org mai
On Fri, May 8, 2009 at 8:08 AM, Paul Boutros wrote:
> Hello,
>
> I'm attempting to alter the location of text in my axis labels in lattice
> plots and have been unsuccessful so far. For example, the y-axis labels are
> always right-justified, but I would like them to be horizontally centered.
>
>
Took a bit of inspecting, looking at hidden functions, but this seems
to do it:
library(lattice)
a <- c(1:10, 5:10)
b <- cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
c <- shingle(a, b)
summary(c, showValues=FALSE)
apply(as.matrix(levels(c)), 1, function(x) length(c[ c>= x[[1]][1] & c
<=
Dear R users,
People who uses vim in Linux/Unix may be interested in checking the
plugin for R that I'm developing:
http://www.vim.org/scripts/script.php?script_id=2628
The plugin includes omni completion for R objects, code indentation
and communication with R running in a terminal emulator (
On Fri, May 8, 2009 at 1:30 PM, David Winsemius wrote:
>
> Took a bit of inspecting, looking at hidden functions, but this seems to do
> it:
>
> library(lattice)
> a <- c(1:10, 5:10)
> b <- cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
> c <- shingle(a, b)
> summary(c, showValues=FALSE)
>
> apply
sorry about the mistake - the -data$Type doesn't work: the '-' sign isn't
valid for factors. I *thought* I had checked this before submitting a
response !
HufferD wrote:
>
> On Thursday, May 07, 2009 7:45 PM, David Freedman wrote:
>
> > ...how about:
> > d=data[order(data$ID,-data$Type),]
I am new to R (ex SAS user) , and I cannot merge two data frames without
getting duplicated rows in the results. How to avoid this happening without
using the unique() function?
1. First data frame is called "tmv" with 6 variables and 239 rows:
> tmv[1:10,]
temps nomprenom sex
On May 8, 2009, at 4:55 PM, Deepayan Sarkar wrote:
On Fri, May 8, 2009 at 1:30 PM, David Winsemius > wrote:
Took a bit of inspecting, looking at hidden functions, but this
seems to do
it:
library(lattice)
a <- c(1:10, 5:10)
b <- cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
c <- shingle(a,
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