Hi friends,
Is there a function to select intercept coefficients only ?
When I use "coeficients" it shows me all the coefficients, but I only want a
specific coefficients.
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On something the size of your data it took about 30 seconds to
determine the number of unique teachers per student.
> x <- cbind(sample(326397, 800967, TRUE), sample(20, 800967, TRUE))
> # split the data so you have the number of teachers per student
> system.time(t.s <- split(x[,2], x[,1]))
us
choonhong ang wrote:
Hi friends,
Is there a function to select intercept coefficients only ?
When I use "coeficients" it shows me all the coefficients, but I only want a
specific coefficients.
What about indexing, e.g. as in:
coefficients(some_lm_object)["(Intercept)"]
Uwe Ligges
I want to find the last record for each person_id in a data frame
(from a SQL database) ordered by date. Is there a better way than
this for loop?
for (i in 2:length(history[,1])) {
if (history[i, "person_id"] == history[i - 1, "person_id"])
history[i, "order"] = history[i - 1, "order"]
But SAS/IML is not part of base SAS, it costs extra, so there is a good chance
that a user that has SAS will not be able to run code that uses SAS/IML.
I have known of SAS programmers who know IML well that still write
matrix/vector tools using macros or proc transpose so that a user without IML
Thanks Greg - that makes sense... that the test of the main effect of A is
uninteresting if the AxB interaction is in the model
- but isn't that exactly what appears in the usual anova(fullmodel) output?
A test of the main effect of A, a test of the main effect of B, and then a
test of the interac
tlevine wrote:
>
> The NOAA has very promising tabular forecasts
> (http://forecast.weather.gov/MapClick.php?CityName=Ithaca&state=NY&site=BGM&textField1=42.4422&textField2=-76.5002&e=0&FcstType=digital),
> but I can't figure out how to import them.
>
Sometimes you can just use gsub to get htm
Dear Andrew,
Here is one way:
# Some data
set.seed(1)
mydata<-data.frame(person_id=rep(1:10,10),x=rnorm(100))
mydata
# last register for person_id
with(mydata,tapply(x,person_id,function(x) tail(x,1)))
# test for person_id=1
mydata[mydata$person_id==1,] # see the last number in column 2
HTH,
Yes, the output from a summary of lm does include the uninteresting test.
Partly at least due to a legacy from when we used to compute a lot of these
things by hand. Certain layouts and sequences of calculations were developed
to make the hand calculations easier. When we first started having
BKMooney gmail.com> writes:
>
>
> Also, when I tried to use nls, I get an error:
> nls(ypts ~ exp(xpts))
> Error in getInitial.default(func, data, mCall = as.list(match.call(func, :
> no 'getInitial' method found for "function" objects
>
> If someone could please point out what I am doin
Dear R-users
Has anybody implemented a function/package that will compute an individual's
risk of an event in the presence of competing risks, adjusted for the
individual's covariates?
The only thing that seems to come close is the cuminc function from cmprsk
package, but I would like to adju
I want to produce a dataframe with integer columns for elements of
string pairs:
pairs <- c("10 21","23 45")
pairs.split <- lapply(pairs,function(x)strsplit(x," "))
pdf <- as.data.frame(pairs.split)
names(pdf) <- c("p","q")
-- at this point things look good, except the columns are factors, as
"...from an SQL database."How? Structure of the result?
You say "ordered by date" but then you don't reference any date
variable? And your code creates an "order" column, but that would not
appear necessary for the stated purpose and you don't output the last
"order" within a "person_i
Dear R users,
I am completelly lost with the following:
I have the following vectors a, b ,c, d and e
+ a
[1] 279.3413 268.0450 266.3062 433.8438 305.4650 317.4712 288.3413
374.6950
>
> b
[1] 170.4500 254.5675 219.5762 232.3425 200.2738 238.2637 210.6062
262.4825 345.2387 269.3763
[11] 190
R-FAQ 7.10
:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-to-numeric_003f
--
David Winsemius
On Feb 27, 2009, at 2:56 PM, Alexy Khrabrov wrote:
I want to produce a dataframe with integer columns for elements of
string pairs:
pairs <- c("10 21","23 45")
pairs.split
have a look at R FAQ 7.10, e.g., try
as.numeric(levels(pdf$p))[as.integer(pdf$p)]
Best,
Dimitris
Alexy Khrabrov wrote:
I want to produce a dataframe with integer columns for elements of
string pairs:
pairs <- c("10 21","23 45")
pairs.split <- lapply(pairs,function(x)strsplit(x," "))
pdf <-
Hi,
you could do one of the following,
1) combine a, b, c, d, e in a list and use ?lapply
my.list <- list(a,b,c,d,e)
lapply(my.list, foo)
where foo() is a function to be applied to each individual element
2) alternatively, see ?get to retrieve the value of a variable from
its name. Your
Dear Andrew:
Here is another way assuming you have an order column in your history data
as well as a person_id. Again, your variable
of interest is x:
# Some data
set.seed(1)
history<-data.frame(
person_id=rep(1:10,each=10),
record=rep(sample(10),10),
x=rnorm(100)
Andrew, it makes it easier to help if you supply a typical
input and expected output along with your code. I tried
your code with the following input:
> history
person_id date
1 Mary1
2 Mary2
3Sue3
4 Alex4
5Joe5
6 Alex6
7 Ale
Hi Stefan,
Thanks so much. This will help me i am sure. These past 2 days i was away on a
trip so please excuse my delayed answer.
Monica
> From: stefan.ev...@uos.de
> To: pisican...@hotmail.com
> Subject: Re: [R] statistical significance of accuracy increase in
> classification
> Date
Thanks. I will surely try this as well.
Monica
> Date: Thu, 26 Feb 2009 08:14:31 -0500
> Subject: Re: [R] statistical significance of accuracy increase in
> classification
> From: mxk...@gmail.com
> To: pisican...@hotmail.com
> CC: r-help@r-project.org
>
> > Do you know about any good refe
On Fri, Feb 27, 2009 at 2:10 PM, William Dunlap wrote:
> Andrew, it makes it easier to help if you supply a typical
> input and expected output along with your code. I tried
> your code with the following input:
I'll be careful to avoid these mistakes. Also, I should not have used
a reserved wo
Check out the crr() function in the same package:
library(cmprsk)
?crr
Ravi.
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicine and Gerontology
School of Medicine
Johns Hopkins University
Ph. (410) 502-2
Hi Andrew,
Just remember that something was bad with the code I sent you (the same you
referred to in [1]).
This version runs with no problems:
# Some data
history_ <-
data.frame(person_id=c(1,2,2),date_=c("2009-01-01","2009-02-03","2009-02-02"),x=c(0.01,0.05,0.06))
colnames(history_) <- c("perso
I have a large 3 dimensional array of size (243,246,768)
The first dimension is Rows, second is columns and the third is Time.
So for each row and column, I want to calculate the mean of time steps
1:8, 2:9, 3:10 and so on and assign the values to a new array. For this
I am using the following s
John Sorkin wrote:
Frank,
A programming language's efficience is a function of several items, including what you are trying to program. Without using SAS proc IML, I have found that it is more efficient to code algorithms (e.g. a least squares linear regression) using R than SAS; we all know that
Hi listers,
I check it out at the messages... But I didn't find how do I use the while
with 2 conditions...
while (a>1 ? b>1){
a<-2
b<-2
}
Should I use what...
Thanks in advance,
Marcio
--
View this message in context:
http://www.nabble.com/While-with-2-conditions-tp22252945p22252945.html
S
On 27-Feb-09 19:37:50, MarcioRibeiro wrote:
>
> Hi listers,
> I check it out at the messages... But I didn't find how do I use
> the while with 2 conditions...
> while (a>1 ? b>1){
> a<-2
> b<-2
> }
> Should I use what...
> Thanks in advance,
> Marcio
while((a>1)&(b>1)){
a<-2
b<-2
}
is t
On 27/02/2009 6:15 PM, Vemuri, Aparna wrote:
I have a large 3 dimensional array of size (243,246,768)
The first dimension is Rows, second is columns and the third is Time.
So for each row and column, I want to calculate the mean of time steps
1:8, 2:9, 3:10 and so on and assign the values to
I am running an R script with Tinn-R (2.2.0.1) and I get the error message
Error in source(.trPaths[4], echo = TRUE, max.deparse.length = 150) :
object ".trPaths" not found
Any solutions?
Thank you.
Kevin
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On Fri, Feb 27, 2009 at 8:53 AM, Frank E Harrell Jr
wrote:
> Ajay ohri wrote:
>>
>> Sometimes for the sake of simplicity, SAS coding is created like that. One
>> can use the concatenate function and drag and drop in an simple excel sheet
>> for creating elaborate SAS code like the one mentioned an
On Feb 27, 2009, at 7:49 PM, Duncan Murdoch wrote:
On 27/02/2009 6:15 PM, Vemuri, Aparna wrote:
I have a large 3 dimensional array of size (243,246,768)
The first dimension is Rows, second is columns and the third is
Time. So for each row and column, I want to calculate the mean of
time st
Hi,
is it possible to execute a script with R and go into interactive mode
with the same session?
e.g.
R < myscript.R
>objects()
Creating a .Rprofile is not an option for me.
Thank you
Michael
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