How do I make a picture that is a horizontal strip? I tried
> plot(x=c(1,2,3,4),y=c(1,1,1,1)) #works but screen image is square.
> pdf("ratio.pdf",height=1,width=6)
> plot(x=c(1,2,3,4),y=c(1,1,1,1))
I got the following error message:
Error in plot.new() : figure margins too large
Is it possible
Dear all,
I'm looking for an alternative way to replicate the "2," string for an
x number of times, and end up with one string containing "2," x times.
I can partly achieve this using replicate().
> y <- rep("2,", times=3)
> y
[1] "2," "2," "2,"
The output that I am looking for is, however, "2,2,
On Tue, 2 Dec 2008, hadley wickham wrote:
The underlying issue is actually not in transform() but in data.frame():
aq <- airquality[sample(1:153,6),]
data.frame(aq, list(a=1,b=2))
Error in data.frame(aq, list(a = 1, b = 2)) :
arguments imply differing number of rows: 6, 1
data.frame(aq, lis
On Tue, 2 Dec 2008, Jarle Brinchmann wrote:
Yes I think so if the errors were normally distributed. Unfortunately
I'm far from that but the combination of sem & its bootstrap is a good
way to deal with it in the normal case.
I must admit as a non-statistician I'm a not 100% sure what the
differ
have a look at ?paste(), e.g.,
paste(rep(2, 3), collapse = ",")
and if you need a comma at the end, then you can again use paste(),
paste(paste(rep(2, 3), collapse = ","), ",", sep = "")
I hope it helps.
Best,
Dimitris
Liviu Andronic wrote:
Dear all,
I'm looking for an alternative way to
Thanks a lot
Envoyé de mon iPhone
Le 3 déc. 08 à 00:39, "jim holtman" <[EMAIL PROTECTED]> a écrit :
If you want to do the addition, 'unclass' the variable:
alpha2+4
[1] "2008-12-25"
alpha2 + unclass(alpha1)
[1] "2009-02-15"
On Tue, Dec 2, 2008 at 4:10 PM, Christophe Dutang
<[EMAIL
On Tue, 2 Dec 2008, David Epstein wrote:
How do I make a picture that is a horizontal strip? I tried
plot(x=c(1,2,3,4),y=c(1,1,1,1)) #works but screen image is square.
pdf("ratio.pdf",height=1,width=6)
plot(x=c(1,2,3,4),y=c(1,1,1,1))
I got the following error message:
Error in plot.new() : f
Hi,
I hope somebody can help me on how to use the hypergeometric function. I did
read through the R documentation on hypergeometric but not really sure what it
means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
On Tue, 2 Dec 2008, Peter Dalgaard wrote:
Prof Brian Ripley wrote:
As the help page says
If some of the values are not vectors of the appropriate length,
you deserve whatever you get!
Yes (did I write that?). It is a bit annoying with things that almost work,
though.
[snip]
I
On Tue, Dec 02, 2008 at 02:28:18PM -0800, David Epstein wrote:
> Is there a good and concise way of making simultaneous plots that are
> identical, but directed to different devices?
>
> I'm writing an R-script that produces a pdf file. I would really like to
> check visually whether the pdf file
Hi,
I am casting a dataframe from long to wide format. The same codes that works
for a smaller dataframe would take a long time (more than two hours and still
running) for a longer dataframe of 2495227 rows and ten different predictors.
How to make it more efficient ?
wer <- data.frame(Nam
Hello group!
I use R 2.8.0 . I've just found out that par(mfrow =) *resets* par
('cex'), not reduces it as documented. To reproduce:
par(cex = 0.5)
par(mfrow = c(2, 2))
print(par('cex'))
It outputs 0.83, not 0.415 as expected.
Particularly such a behavior makes plot.acf effectively ignore par
(
Hi,
I hope somebody can help me on how to use the hypergeometric function.
I did read through the R documentation on hypergeometric but not really
sure what it means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
On Wed, 3 Dec 2008, Philipp Pagel wrote:
On Tue, Dec 02, 2008 at 02:28:18PM -0800, David Epstein wrote:
Is there a good and concise way of making simultaneous plots that are
identical, but directed to different devices?
I'm writing an R-script that produces a pdf file. I would really like to
c
Prof Brian Ripley wrote:
On Tue, 2 Dec 2008, Peter Dalgaard wrote:
Prof Brian Ripley wrote:
As the help page says
If some of the values are not vectors of the appropriate length,
you deserve whatever you get!
Yes (did I write that?). It is a bit annoying with things that almost
w
Peter Dalgaard wrote:
>
> BTW, we have a deparser bug:
>
> > transform
> function ("_data", ...)
> UseMethod("transform")
>
>
> > function ("_data", ...)
> Error: unexpected string constant in "function ("_data""
>
>
> > f <- function (`_data`, ...) {}
> > attr(f,"source")<-NULL
> > f
> funct
Try timing this to see if its any faster:
> lev <- levels(wer$Predictor)
> out <- outer(wer$Predictor, lev, "==")
> colnames(out) <- lev
> aggregate(out, wer[1:2], sum)
Name Type A B
11a 1 0
22b 1 0
33c 1 0
44d 1 1
55e 1 1
On Tue, Dec 2, 2008 at 11:52 PM
Hi there,
I've installed R somewhen in German but I'd like to have it in English. The
installation of a new version does not change the language setting though I
think I've chosen "English" in the installation process (this choice was
available, right?).
Can anybody give me a hint?
(Error-Me
Hello R users (and Hadley),
facet_wrap and facet_grid function are both very usefull. But they are
perhaps a bit redundant.
I probably don't see the advantage of two separate functions, but what do
you think of this suggestion : add 'nrow' and 'ncol arguments to facet_grid.
These arguments would
Is there a R package available that facilitates estimation of
Buchinsky's two step procedure in order to correct for sample selection
in a quantile regression setting? Thanks in advance for any help.
Reference:
Moshe Bushinsky (2001) Quantile regression with sample selection:
estimating wom
Hei,
in the FAQ on R for Windows it says:
3.4 I selected English for installation but R runs in Chinese.
Precisely, you selected English for installation! The language of the installer
has nothing to do with the language used to run R: this is completely standard
Windows practice (and necess
Perhaps you are on Windows: the answer is in the rw-FAQ
http://cran.r-project.org/bin/windows/base/rw-FAQ.html#I-selected-English-for-installation-but-R-runs-in-Chinese
If you have another platform either set LANGUAGE=en or (for MacOS X) ask
on the appropriate list.
On Wed, 3 Dec 2008, Antje
Hello Annette,
that explains everything... Thank you! I just thought having an English version
of Windows would be enough but indeed my Regional and Language-Setting are set
to German...
Ciao,
Antje
Annette Heisswolf schrieb:
Hei,
in the FAQ on R for Windows it says:
3.4 I selected Engl
Wacek Kusnierczyk wrote:
It should deparse with backticks, not the old-style quotes (did that
ever work?).
isn't it the same issue as in this simple case:
`FALSE` = 0
ls()
# "FALSE", not `FALSE`
vQ
No. ls() always returns a character vector.
--
O__ Peter Dalgaard Øst
sorry for being a little bit imprecise, Chuck interpreted my question
as desired.
Armin
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and pr
Prof Brian Ripley wrote:
>
> How about dev.copy2pdf ?
>
I put the following into a script:
quartz(...)
#many graphics commands
dev.copy2pdf(pdf,file="ratio1.pdf")
and then sourced the script. I got the error message
Error in pdfFonts(family) :
invalid arguments in 'pdfFonts' (must be
Dear John,
i did follow the Rcmdr instructions for macosx, having no results
though.
I am soon upgrading to 10.5 and hope i'll encounter no problems.
The silly thing however was that i had installed every file needed
for rcmdr to run but apparently had no results.
Is there maybe some key po
The dhyper etc deal with the hypergeometric _distribution_ while what
you appear to want have is the hypergeometric special function (the
connection is that the regular hypergeometric function is the
generating function for the hypergeometric distribution if I recall
correctly).
Anyway, what you
Many thanks for your kind responses.
That's a simple change and will make transform.data.frame behave more
consistently with cbind.data.frame and data.frame.
Related to above, I find rather inconsistent following behavior:
aq <- airquality[sample(1:153,6),]
data.frame(aq, list(a=1,b=
Hi,
I am a student in archaeology with some interest in statistics and R.
Recently I've obtained the permission to distribute in the public domain
a small dataset (named "spearheads" with 40 obs. of 14 variables) that
was used in an introductory statistics book for archaeologists
(published in 19
The hypergeo package should be able to deal with this,
although the function you specify below looks like a degenerate case
(if I understand it correctly) so the convergence rate
is likely to be slow.
Let me know how you get on
best wishes
Robin (author of hypergeo)
Jarle Brinchmann wrote:
R Gurus,I have a vector of nearly 90,000 characters from which I have to
extract the index of the characters which are repeated. So suppose if
x<-c("a","a","b","a","b","c","d") then my output would be a vector having
the index where the values are repeated i.e (1,2,3,4,5). I have been able to
isola
On 12/3/2008 6:32 AM, SOUVIK BANDYOPADHYAY wrote:
> R Gurus,I have a vector of nearly 90,000 characters from which I have to
> extract the index of the characters which are repeated. So suppose if
> x<-c("a","a","b","a","b","c","d") then my output would be a vector having
> the index where the valu
On Wed, 3 Dec 2008, David Epstein wrote:
Prof Brian Ripley wrote:
How about dev.copy2pdf ?
I put the following into a script:
quartz(...)
#many graphics commands
dev.copy2pdf(pdf,file="ratio1.pdf")
Just
dev.copy2pdf(file="ratio1.pdf")
and then sourced the script. I got the er
On Wed, 3 Dec 2008, Stefano Costa wrote:
Hi,
I am a student in archaeology with some interest in statistics and R.
Recently I've obtained the permission to distribute in the public domain
a small dataset (named "spearheads" with 40 obs. of 14 variables) that
was used in an introductory statist
Hi Stephen,
It looks like a bug in facet_wrap which seems to mix up the factor
labels (by sorting only the labels but not the plots?).
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Resear
Hi,
I have two matrices as follow:
matrix A =
a=matrix(c(c("abc","abc","bcd","bcd","bce","bce"),c("a1","d2","d1","d2","a1","a2")),6,2)
and matrix B which contains pair of values :
b=matrix(c(c("a1","a2"),c("a1","d2")),2,2)
In short, I wish to find out pairs of values in matrix a[,2] having
sam
Hi,
I have two matrices as follow:
matrix A =
a=matrix(c(c("abc","abc","bcd","bcd","bce","bce"),c("a1","d2","d1","d2","a1","a2")),6,2)
and matrix B which contains pair of values :
b=matrix(c(c("a1","a1"),c("a2","d2")),2,2)
In short, I wish to find out pairs of values in matrix a[,2] having
s
Thanks all. All solutions are usable. These two I received off-list:
> toString(paste(rep("2",3), sep=","))
[1] "2, 2, 2"
and
> paste(rep("2,",3),collapse="")
Liviu
On Wed, Dec 3, 2008 at 9:14 AM, Dimitris Rizopoulos
<[EMAIL PROTECTED]> wrote:
> have a look at ?paste(), e.g.,
>
> paste(rep(2, 3
Hi David,
> facet_wrap and facet_grid function are both very usefull. But they are
> perhaps a bit redundant.
I disagree ;) Conceptually they are rather different: facet_wrap is
essentially a 1d layout, while facet_grid is a 2d layout. This has
implications for how you specify the faceting, how
Yes, that's a known bug. It's fixed in the next version which I'm
hoping to release early next week.
Regards,
Hadley
On Wed, Dec 3, 2008 at 6:12 AM, ONKELINX, Thierry
<[EMAIL PROTECTED]> wrote:
> Hi Stephen,
>
> It looks like a bug in facet_wrap which seems to mix up the factor
> labels (by sorti
Is this what you want:
> a
[,1] [,2]
[1,] "abc" "a1"
[2,] "abc" "d2"
[3,] "bcd" "d1"
[4,] "bcd" "d2"
[5,] "bce" "a1"
[6,] "bce" "a2"
> b
[,1] [,2]
[1,] "a1" "a2"
[2,] "a1" "d2"
> x <- lapply(split(seq(nrow(a)), a[,1]), function(.indx){
+ do.call(rbind, lapply(seq(nrow(b)), function(
Hi Daren,
Unfortunately, the current version of reshape isn't very efficient.
I'm working on a new version which should be 10-20x times faster for
the operation that you're performing, but this won't be ready for a
while and in the meantime you might want to try an alternative
approach, like the o
Hi,
Can someone help me how to create a table for Min, Max, Mean, Deviance.
I have input data like this:
Person Age Child
1 517 2
2 517 0
3 517 1
4 5202
5 520 3
6 710 1
7 721
On Wed, Dec 3, 2008 at 2:06 AM, Prof Brian Ripley <[EMAIL PROTECTED]> wrote:
> On Tue, 2 Dec 2008, hadley wickham wrote:
>
>>> The underlying issue is actually not in transform() but in data.frame():
>>>
aq <- airquality[sample(1:153,6),]
data.frame(aq, list(a=1,b=2))
>>>
>>> Error in dat
Dear Ben,
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On
> Behalf Of Ben
> Sent: December-03-08 5:56 AM
> To: John Fox
> Cc: r-help@r-project.org; Chiara Malaguti
> Subject: Re: [R] Problem with tcl/tk and Rcmdr - urgent help required
>
> Dear John,
> i did fo
Dear R Community,
I am currently student at the Vienna University of Technology writing my
Diploma thesis on causality in time series and doing some analyses of
time series in R. I have the following questions:
(1) Is there a function in R to estimate the PARTIAL spectral coherence
of a mult
yes, I think this is the bug that will be fixed in the next release :
http://github.com/hadley/ggplot2/tree/master/NEWS
2008/12/3 ONKELINX, Thierry <[EMAIL PROTECTED]>
> Hi Stephen,
>
> It looks like a bug in facet_wrap which seems to mix up the factor
> labels (by sorting only the labels but not
Hello Alexander,
for (3) see the CRAN-package "vars".
Best,
Bernhard
>
>Dear R Community,
>
>I am currently student at the Vienna University of Technology
>writing my
>Diploma thesis on causality in time series and doing some analyses of
>time series in R. I have the following questions:
>
>
is there anyway for some parts of the function output to not be returned,
even if the output has been used to calculate a further part of the
function? i have tried invisible() to no avail.
Thanks Emma
--
View this message in context:
http://www.nabble.com/Function-output-difficulties-tp2081311
? merge
complexkid wrote:
>
> Hi,
> I have two matrices as follow:
> matrix A =
>
> a=matrix(c(c("abc","abc","bcd","bcd","bce","bce"),c("a1","d2","d1","d2","a1","a2")),6,2)
>
> and matrix B which contains pair of values :
> b=matrix(c(c("a1","a2"),c("a1","d2")),2,2)
>
> In short, I wish t
Look at the squishplot function in the TeachingDemos package, that may do what
you want.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
801.408.8111
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> project.org
Please assist, how do you find the weighted standard deviation?
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
2008/12/3 hadley wickham <[EMAIL PROTECTED]>
> Hi David,
>
> > facet_wrap and facet_grid function are both very usefull. But they are
> > perhaps a bit redundant.
>
> I disagree ;)
I was sure :-)
> Conceptually they are rather different: facet_wrap is
> essentially a 1d layout, while facet_gri
Dear R-experts,
I am running R version 2.7.1 on Windows Vista. I have a small dataset which
consists of “chick ID”, “year (0, 1)”, “hatching order [HO, defined as first,
second and third-hatched chick]”, and the binary outcome of interest “death (0,
1)”. So a subset of my dataset looks like th
Thanks for this reply, However I am interested to know why I need to modify
my function to a=1?
Regards,
Gabor Grothendieck wrote:
>
> Assume a = 1. If not set b = b/a, etc.
> Now use (1) uniroot
>
>> f <- function(x) b + c/(1+x) + d/(1+x)^2 - 1 - x
>> uniroot(f, 0:1)
> $root
> [1] 0.8392679
Dear Humphrey,
Take a look at ?wtd.mean in Hmisc.
HTH,
Jorge
On Wed, Dec 3, 2008 at 5:43 AM, Humphrey Kaunda <[EMAIL PROTECTED]> wrote:
> Please assist, how do you find the weighted standard deviation?
>
> __
> R-help@r-project.org mailing list
> htt
I'm working on a contourplot( ) graph, the subject of several previous
posts to this list. The contours express probabilities from 0 - 1, but the
key that is automatically generated by contourplot pads the probability
scale with values that are impossible (i.e, range goes from -0.2 to 1.2),
whi
Try length(yourvariablename) for all variables in the model. The first error
message indicates that the vectors you are using are not of the same length
(i.e. they do not contain the same number of observations).
The modeling question: Chickens are nested in nest (haha), but you don't
have a nest
What is odd is that it seems to run ok if we call "+.Date" directly:
> "+.Date"(alpha1, alpha2)
[1] "2009-02-15"
On Tue, Dec 2, 2008 at 4:10 PM, Christophe Dutang <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I'm dealing with dates in R (2.7.2), but some basic operations raise a
> warning.
>
> Incompa
You don't. This was just to make the presentation simpler.
On Wed, Dec 3, 2008 at 12:32 PM, RON70 <[EMAIL PROTECTED]> wrote:
>
> Thanks for this reply, However I am interested to know why I need to modify
> my function to a=1?
>
> Regards,
>
>
> Gabor Grothendieck wrote:
>>
>> Assume a = 1. If n
On Wed, 2008-12-03 at 13:18 -0500, Gabor Grothendieck wrote:
> What is odd is that it seems to run ok if we call "+.Date" directly:
>
> > "+.Date"(alpha1, alpha2)
> [1] "2009-02-15"
It also works if you flip the ordering:
> alpha2 + alpha1
[1] "2009-02-15"
Warning message:
Incompatible methods (
On 03-Dec-08 13:41:53, emj83 wrote:
> is there anyway for some parts of the function output to not be
> returned, even if the output has been used to calculate a further
> part of the function? i have tried invisible() to no avail.
>
> Thanks Emma
It's not clear what you mean by "some parts of th
On Wed, Dec 3, 2008 at 1:57 PM, Gavin Simpson <[EMAIL PROTECTED]> wrote:
> On Wed, 2008-12-03 at 13:18 -0500, Gabor Grothendieck wrote:
>> What is odd is that it seems to run ok if we call "+.Date" directly:
>>
>> > "+.Date"(alpha1, alpha2)
>> [1] "2009-02-15"
>
> It also works if you flip the orde
dear all,
I'm building new dataframes from bigger one's using e.g. columns F76, F83,
F90:
JJ<-data.frame( c( as.character(rep( gender,3))) , c( F76,6- F83, F90) )
Looking into JJ one has:
c.as.character.rep.gender..8...
c.6...F73..F78..F79..F82..6...F84..F94..F106..F109
1
Dear R users,
I have issues regarding latex() from Hmisc and numSummary() from
Rcmdr. Here's an example:
> library(Rcmdr)
> data(Angell, package="car")
> numSummary(Angell[,"hetero"], statistics=c("mean", "sd", "quantiles"),
> quantiles=c( 0,.25,.5,.75,1 ))
> .numSummary <- popOutput()
> latex(as.
Dear R-users,
The strsplit function does not exist in S-plus and I would like to use it. How
could I reproduce the function in Splus or access to its source code?
Thank you in advance,
Sebastien
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On Wed, 2008-12-03 at 14:13 -0500, Gabor Grothendieck wrote:
> >
> > Why it works is not odd if you look at the help for ?`+.Date`, which
> > shows that for this method (correct term?) we need 'date' + 'x', where
> > 'date' is an object of class Date and 'x' is numeric.
>
> In fact what it says i
On Wed, Dec 3, 2008 at 9:13 AM, Seth W Bigelow <[EMAIL PROTECTED]> wrote:
> I'm working on a contourplot( ) graph, the subject of several previous
> posts to this list. The contours express probabilities from 0 - 1, but the
> key that is automatically generated by contourplot pads the probability
>
See the help page. You name the arguments, e.g.
JJ <- data.frame( gender= c( as.character(rep( gender,3))) ,
J.value -c( F76 ,6-F83, F90) )
The help says
Arguments:
...: these arguments are of either the form 'value' or 'tag =
value'. Component names are crea
On Wed, 3 Dec 2008, [EMAIL PROTECTED] wrote:
Dear R-users,
The strsplit function does not exist in S-plus and I would like to use it. How
could I reproduce the function in Splus or access to its source code?
With difficulty, as it is almost entirely implemented in C code (in
src/main/charact
Dear Brian (and original poster),
My apologies -- I didn't notice the original posting.
By coincidence, I have a version of strsplit() that I've used to
illustrate recursion:
Strsplit <- function(x, split){
if (length(x) > 1) {
return(lapply(x, Strsplit, split)) # vectorization
Hello,
I did a function (sec_conop) whose arguments are syndic,
well and wellconop.
sec_conop(syndic='01syndic.txt',well='well-1.csv',wellconop='well-1.dat');closeAllConnections()
This function takes “well” and “syndic”, matching between
them and then it does some transformations. The result i
Hi,
I am trying to read a SAS version 9.1.3 SAS dataset into R (to preserve
the SAS labels), but am unable to do so (I have read in a CSV version).
I first created a transport file using the SAS code:
libname ces2 'D:\CES Analysis\Data';
filename transp 'D:\CES Analysis\Data\fadata.xpt';
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED]
> Sent: Wednesday, December 03, 2008 1:40 PM
> To: r-help@r-project.org
> Cc: [EMAIL PROTECTED]
> Subject: [R] reading version 9 SAS datasets in R
>
> Hi,
>
>
>
> I am trying to r
[EMAIL PROTECTED] wrote:
Hi,
I am trying to read a SAS version 9.1.3 SAS dataset into R (to preserve
the SAS labels), but am unable to do so (I have read in a CSV version).
I first created a transport file using the SAS code:
libname ces2 'D:\CES Analysis\Data';
filename transp 'D:\CES
Folks,
I have a query around weighting in Random Forest (RF). I know that several
earlier emails in this group have raised this issue, but I did not find an
answer to my query.
I am working on a dataset (dataset1) that consists of 4 million records that
can be reduced to a dataset (dataset2) of a
Frank E Harrell Jr wrote:
[EMAIL PROTECTED] wrote:
Hi,
I am trying to read a SAS version 9.1.3 SAS dataset into R (to preserve
the SAS labels), but am unable to do so (I have read in a CSV version).
I first created a transport file using the SAS code:
libname ces2 'D:\CES Analysis\Data
Hello,
can anybody help me out saving random numbers? What I am doing is to
generate a series of random numbers and keep it as a zoo object.
z <- 1000
rn1 <- as.zoo(rnorm(z))
The random numbers will be analyzed and described in a LaTeX document,
so I have to keep them static somehow. The fa
on 12/03/2008 06:10 PM Bastian Offermann wrote:
> Hello,
>
> can anybody help me out saving random numbers? What I am doing is to
> generate a series of random numbers and keep it as a zoo object.
>
> z <- 1000
>
> rn1 <- as.zoo(rnorm(z))
>
> The random numbers will be analyzed and described in
I would like to give out the equation for calculating the maximum likelihood.
Below is the code, but I still have problems with it. After I read the
code, I found there are two cases for "w(weights)". If "w" is not zero,
then the equation is given as "val <- 0.5 * (sum(log(w)) - N * (log(2 * pi
Hi Dana
> -Original Message-
> From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]
> On Behalf Of Dana77
> Sent: Wednesday, December 03, 2008 3:24 PM
> To: r-help@r-project.org
> Subject: [R] Help with reading code
>
>
> I would like to give out the equation for calculating the maximum
> l
aha!, thanks for this.
Avram
On Dec 2, 2008, at 5:38 PM, Ray Brownrigg wrote:
On Wed, 03 Dec 2008, Ray Brownrigg wrote:
The easiest way would be:
map('world', regions="UK", xlim=c(-10, 5), ylim=c(48, 60))
But of course:
map('world', regions=c("UK", "Ireland"), xlim=c(-10, 5), ylim=c(48,
Hi Stavros
httpRequest is good. You might also look at the RCurl package
for access to more protocols and slightly higher level facilities
for dealing with HTTP (and other) requests.
Also, you might look at SSOAP as a related technology.
I'll be interested to see what you come up with, so
Dear all,
How can I plot the data below with scatter plot
so that the next to the marker it contain the label for "species"
__DATA__
class true_hits false_hits species
big 2350180 lion
big 375 20 dog
big 635 97 cow
big78 4 horse
bi
Hi there,
I can't seem to wrap my head around the differences between discrimination
and calibration. I think that I learn best by examples. Could someone
provide me with detailed explanations using examples of when a model could
do both well, both poorly, and one well and the other poorly?
Tha
Hi,
When I use logistic regression, each variable has a p value associated with
it. Do I only include the variables that have a statistically significant p
value (<0.05), or are there situations when I should include variables when
their p values are high? I had heard that if a variable has a hi
Hi List,
I am unable to read in a 7.8Gb ascii grid using readAsciiGrid {maptools} - R
runs out of memory. I have 4Gb ram and 4Gb swap, so things are getting tight.
I am wondering if anyone has alternative options (preferably with example) that
enable to read in large grids, do some calculation
Dear R community
Does anyone know of some methods already programmed up open source in
R for the post hoc methods in anova.
I have some microarray data generated from different drug treatments 8
in particular, and a subset of 90 genes which i would like to
analyseusing the above method.
Thank y
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