Hello everyone,
I'm trying to plot 3600 points and my idea is if this value is higher than 0.35
then this point must appear in green colour, if it's smaller than -0.35 then
values must appear in red and if values are between -0.35 and 0.35 they must be
in yellow. I'm thinking and I'm trying man
Berwin A Turlach wrote:
> On Sat, 01 Nov 2008 22:57:38 +0100
> Wacek Kusnierczyk <[EMAIL PROTECTED]> wrote:
>
>
>
>> is.integer(1) # FALSE
>> is.integer(1:1) # TRUE
>>
>> is not particularly appealing as a design, though it can be defended
>> along the line that : uses 1 as the increase step, th
Hello;
I am a R newbie and would like to know correct and efficient method for
doing string replacement.
I have a large data set, where I want to replace character "M", "b",
and "K" (currency in Million, Billion and K) to millions. That is
209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/
can any one help me to now , what is the result of this code ?
#start
edw<-function(mm,n){
v2<-v3<-0
d<-dim(mm)
dd<-d[1]*d[2]
p1<-2*n/(dd*(dd-n))
p2<-(n*(n-1)*(dd-n)+2*n*(dd-d[1]-d[2]-n+2))/(dd-d[1]-d[2]+1)*(dd-n)
v1<-((dd-n-1)/(n+1))*sum(mm^2)
On Sun, 2008-11-02 at 07:58 +, Carlos Morales wrote:
> Hello everyone,
>
> I'm trying to plot 3600 points and my idea is if this value is higher than
> 0.35 then this point must appear in green colour, if it's smaller than -0.35
> then values must appear in red and if values are between -0.3
Carlos Morales wrote:
Hello everyone,
I'm trying to plot 3600 points and my idea is if this value is higher than 0.35 then this point must appear in green colour, if it's smaller than -0.35 then values must appear in red and if values are between -0.35 and 0.35 they must be in yellow. I'm thin
Your gsub example is almost exactly what gsubfn in the gsubfn package
does. gsubfn like gsub except the replacement string is a function:
> library(gsubfn)
> gsubfn("(.*)B$", ~ as.numeric(x) * 10e6, d, ignore.case = TRUE)
[1] "120.0M""11.01m""2.097e+09" "100.00k" "50"
Also there are ex
Dear all,
I am getting a error while using lapply to generate plots. The variable
".name" is used to identify each plot in the "main" variable. The method
worked once but afterwards seems to throw up an error when used in a
different case. The input ...
dataOut <- lapply(names(dataIn), FUN =
func
On Sun, Nov 2, 2008 at 11:22 AM, Christian Ritz <[EMAIL PROTECTED]> wrote:
> Hi Göran,
>
> the R package NADA is specifically designed for left-censored data:
>
> http://www.statistik.uni-dortmund.de/useR-2008/slides/Helsel+Lee.pdf
>
>
> The function cenreg() in NADA is a front end to survreg().
N
Dear all,
I am getting a error while using lapply to generate plots. The variable
".name" is used to identify each plot in the "main" variable. The method
worked once but afterwards seems to throw up an error when used in a
different case. The input ...
dataOut <- lapply(names(dataIn), FUN = func
On Sun, 2 Nov 2008, ZhaoWei wrote:
Great, "--vanilla" works!
Can you please tell me what this parameter means?
And, it works with the execuatble(/usr/lib/R/bin/exec/R). I'm wondering
is it possible to do the same with the shell script(/usr/bin/R), anyway
when you type "R" in command line, it mea
Dear R useRs,
yesterday i updated my system from ubuntu 8.04 to 8.10. I use emacs-
snapshot, this is emacs 23.0.60.1 and ess 5.3.8. Before the update i
had when starting emacs with an R file an ess-toolbar with little
icons to start R or to evaluate a line or a region of my R file, but
no this too
I suggest you issue the following command:
?pnorm
which will get you to a manual page that will give you information
about the following commands:
dnorm(x, mean=0, sd=1, log = FALSE)
pnorm(q, mean=0, sd=1, lower.tail = TRUE, log.p = FALSE)
qnorm(p, mean=0, sd=1, lower.tail = TRUE, log.p = FALSE
Hi,
i found ur request on a R forum. Did you find anything about it? I need
some help with qgarch and egarch models. Any help is appreciated.
Best,
Marco
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Hi Göran,
the R package NADA is specifically designed for left-censored data:
http://www.statistik.uni-dortmund.de/useR-2008/slides/Helsel+Lee.pdf
The function cenreg() in NADA is a front end to survreg().
Christian
Göran Broström wrote:
> On Fri, Oct 31, 2008 at 2:27 PM, Terry Therneau <[E
Hi Carlos,
I'd strongly urge to reconsider your colour choices - 7-10% of males
are red-green colour blind and it will be difficult for them to tell
the difference between the high and low values.
Hadley
On Sat, Nov 1, 2008 at 11:58 PM, Carlos Morales
<[EMAIL PROTECTED]> wrote:
> Hello everyone,
Hi,
I tried the suggestion of Terry, as he stated it, it works perfectly but if I
have
>>> x <- rweibull(500, shape = 2, scale = 1)
>>> d <- rep(c(TRUE,FALSE),each=250) # 50% left censoring, at different times
>>> left(x, d)
the scale comes as 0.7 and shape 1.5
Any one knows a solution?
Thanks
Heb
There was an error in your regexp which I did not correct. Here it is
again corrected to better illustrate the solution:
> gsubfn("(.*)B", ~ as.numeric(x) * 10e6, d, ignore.case = TRUE)
[1] "120.0M""11.01m""2.097e+09" "100.00k" "50"
On Sun, Nov 2, 2008 at 7:55 AM, Gabor Grothendieck
<[E
Brostram wrote
> The survreg function cannot fit left-censored data (correct me if I am wrong).
in response to my suggestion to use that routine.
You are wrong. Try reading the help file for survreg, or the references given
there.
The survreg function does not fit left-truncated data, however.
Ehs gmail.com> writes:
>
> can any one help me to now , what is the result of this code ?
>
> #start
> edw<-function(mm,n){
> v2<-v3<-0
> d<-dim(mm)
several lines removed
> }
> #end
Following generic world-wide-wisdom, it is 42.
Dieter
__
Carlos Morales wrote:
> Hello everyone,
>
> I'm trying to plot 3600 points and my idea is if this value is higher
than 0.35 then this point must appear in green colour, if it's smaller
than -0.35 then values must appear in red and if values are between
-0.35 and 0.35 they must be in yellow. I'
Dear Lists,
I got the chance to review Bob Muenchen's book - R for SAS and SPSS users.
While my detailed review is online at www.decisionstats.com, the book is a
welcome addition in R Textbooks for beginners and an especially nice one for
people who have experience in SAS and /or SPSS languages.
A
Greetings all,
I have three files that I would like to merge. The first is a student
level file that contains the student ID, their school ID, and their
country ID.
The second is the school file that contains the school ID and country ID.
The third is the country file with a country ID.
I
Hello -
David Kaplan wrote:
Greetings all,
I have three files that I would like to merge. The first is a student
level file that contains the student ID, their school ID, and their
country ID.
The second is the school file that contains the school ID and country ID.
The third is the count
On Sun, Nov 2, 2008 at 3:57 PM, Therneau, Terry M., Ph.D.
<[EMAIL PROTECTED]> wrote:
> Brostram wrote
>> The survreg function cannot fit left-censored data (correct me if I am
>> wrong).
> in response to my suggestion to use that routine.
>
> You are wrong. Try reading the help file for survreg,
Read them into data frames and then use the R sqldf package:
http://sqldf.googlecode.com
On Sun, Nov 2, 2008 at 12:04 PM, David Kaplan
<[EMAIL PROTECTED]> wrote:
> Greetings all,
>
> I have three files that I would like to merge. The first is a student level
> file that contains the student ID,
On Tuesday 28 October 2008 02:25:55 am Ehs wrote:
> can any one help me to now , what is the result of this code ?
>
> v<-(v1+v2+v3)/dd^2
> }
> #end
Apparently "v", whatever that might be. However, without a little more
information, your question is rather pointless. edw( ) i
I think this will work. Thanks. But, is there a command to merge on a
string variable. All I have is the country 3 letter designation.
Thanks again,
David
===
David Kaplan, Ph.D.
Professor
Department of Educational Psychol
this is a short time fourier transform? Why not use wavelet
transforms that are compactly supported? The wavelet transform
(morlet for instance) has a well know relationship between time and
scale, and doesn't rely on stationarity of the signal where as the
fourier transform does. My signal proc
Gabor,
Why not just this:
expos <- list( B="e9", M="e6", m="e6", k="e3" )
as.numeric( gsubfn("[[:alpha:]]", expos, d ) )
HTH,
Chuck
p.s. I am not sure why B goes with e6 or K with e-02 (below), but
Krishna can adjust the values accordingly.
On Sun, 2 Nov 2008, Gabor Gro
I did provide a link to that solution already but also wanted to
show how to do it in the same way that the code in the question
was written.
On Sun, Nov 2, 2008 at 4:56 PM, Charles C. Berry <[EMAIL PROTECTED]> wrote:
>
>
>
> Gabor,
>
> Why not just this:
>
>expos <- list( B="e9", M="e6",
Hi,
I found some problems dealing with panel data. However, it seems the
problem is maximum likelihood function.
I cannot find a function to compute maximum likelihood estimator for
panel data as well as to test data with likelihood ratio test.
May anyone knows something about that?
Thanks,
M
I am writing a report using Sweave with specific R output incorporated into
the text using the Sexpr{} command. I have run into two specific issues:
1) If the result inside the Sexpr{} command is an integer less than 10 I
would like to print the “word” for that number – e.g., “seven” for 7.
2)
What happened? TIA.
In version 2.7.x:
> (x <- array(1:4, c(2,2)))
[,1] [,2]
[1,]13
[2,]24
> as.array(x)
[,1] [,2]
[1,]13
[2,]24
In version 2.8.0:
> (x <- array(1:4, c(2,2)))
[,1] [,2]
[1,]13
[2,]24
> as.array(x)
Error: evaluati
On 3/11/2008, at 2:11 PM, David Stoffer wrote:
What happened? TIA.
In version 2.7.x:
(x <- array(1:4, c(2,2)))
[,1] [,2]
[1,]13
[2,]24
as.array(x)
[,1] [,2]
[1,]13
[2,]24
In version 2.8.0:
(x <- array(1:4, c(2,2)))
[,1] [,2]
[1,]1
Agradeceré me ayuden con la consulta:
Cómo convertir un objeto data frame en una tabla csv que pueda a su vez ser
convertida en un objeto geodata
De antemano, gracias por la atención,
--
Ricardo Bandin Llanos
[EMAIL PROTECTED]
Estudiante - Magíster Cs. m. Pesquerías
Universidad de Concepción, R
Get it done. Big thank, Brian and Martin!
From: Prof Brian Ripley <[EMAIL PROTECTED]>
Subject: Re: [R] Problem of running R console from Java on linux box
Date: Sun, 2 Nov 2008 11:07:24 + (GMT)
> On Sun, 2 Nov 2008, ZhaoWei wrote:
>
> > Great, "--vanilla" works!
> > Can you please tell me w
Check out ?write.csv
2008/11/2 Ricardo Bandin <[EMAIL PROTECTED]>:
> Agradeceré me ayuden con la consulta:
>
> Cómo convertir un objeto data frame en una tabla csv que pueda a su vez ser
> convertida en un objeto geodata
>
> De antemano, gracias por la atención,
>
> --
> Ricardo Bandin Llanos
> [E
hi ricardo: you're english is fine. i'll cc the list because i
haven't done that and i don't know what a geodata object is but my
guess is that you can use write.table. you can see the details of that
function by doing ?write.table.
On Sun, Nov 2, 2008 at 9:02 PM, Ricardo Bandin wrote:
My fault, I used Runtime.getRuntime.exec("/usr/bin/R --vanilla"), and was
prompted with "/usr/bin/R --vanilla not found". This morning I tried command
with String array, it works.
And, you said "vanilla" is a non-interactive mode, so if I have several R
scripts to run, I have to evaluate them one
Ok- it works now after flushing my objects. The package Oarray doesn't seem
to work under version 2.8.0. I emailed Jonathan about it and he said he
won't get to updating it until next year. In the meantime, I was trying to
produce a seat-of-the-pants workaround and I probably redefined "as.arra
Hi all:
I'm trying to create some side by side dynamic graphics on the same page but I
am running into some problems. I am able to create side by side figures only if
I import them into my PDF. see the example bellow:
\documentclass[12pt]{article}
\usepackage{color,cite,graphicx}% to put in axod
--- Begin Message ---
Hi Ricardo:
I don't understand your question, not because it is in spanish,
but because I will like to know what are you pretending to do.
data.frame is an R object.
csv is a external ascii format for database tables.
geodata is an internal geoR object (a list).
The usual
Dear cateGOry experts,
hyperGTest documentation states that YEAST cannot be used as 'annotation'
when evaluating gene ontology representation status for a given set of
'geneIds'.
Because I am using a custom print I believe I need to create my own data
package to use as the annotation file for 'ann
On Tue, 28 Oct 2008, Agnolucci, Paolo wrote:
Hi
sorry if this is really basic but I am just starting on R.
Can anyone point me at how to write R objects into Excel 2007 files. I
have seen how to set up a connection to a file through
odbcConnectExcel2007(xls.file, readOnly = FALSE, ...) but
Felipe Carrillo yahoo.com> writes:
> I'm trying to create some side by side dynamic graphics on the same page but
Thanks for the example; there was a minor typo so that it did not run "plot(}",
and a major problem that could have caused serious problem (happens to me quite
often due to copy and
dogle northland.edu> writes:
> I am writing a report using Sweave with specific R output incorporated into
> the text using the Sexpr{} command. I have run into two specific issues:
>
> 1) If the result inside the Sexpr{} command is an integer less than 10 I
> would like to print the “word” fo
I have a list that starts out like:
r <- list()
r[[3]] <- list(count=1, orderlist=data.frame(count=1, sku="A"))
So r[3] yeilds:
[[1]]
[[1]]$count
[1] 1
[[1]]$orderlist
count sku
1 1 A
So far so good. Now I want to detect the fact that there is no etry in 1,2, and
4.
> r[1]
[[1]]
NULL
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