For model selection using BIC you can have a look at stepAIC() from
package MASS and boot.stepAIC() from package bootStepAIC. For
instance,
library(bootStepAIC)
boot.stepAIC(glmFit1, data, B = 50, k = log(nrow(n)))
where `glmFit1' is the object represinting the fitted model, `data'
the data.f
R 2.6.0 has Reduce;
myvec <- c(2, 8, 24, 26, 51, 57, 58, 78, 219)
Reduce(function(myvec, p) setdiff(myvec, findSubsets2(p)), myvec, myvec)
On 9/16/07, Adrian Dusa <[EMAIL PROTECTED]> wrote:
>
> Dear list,
>
> I have a vector of numbers, let's say:
>
> myvec <- c(2, 8, 24, 26, 51, 57, 58, 78, 219
Hi
below you can find a function I wrote to mimic a Minitab R+R procedure. It
is intended for myself only so it is not commented. If you want to know
how it functions contact me off-list.
Regards
Petr
[EMAIL PROTECTED] napsal dne 17.09.2007 05:55:00:
> Dear List,
>
> Which is the most efici
Hi,
I have a data frame of 2 columns with the following types :
data$day char
data$value num
And I plot my data with :
plot(strptime(donnees$day,format="%Y-%m-%d %H:%M:%S"),donnees$value,
type="l")
And I'd just like to get the numerical value of the integration of this
graph.
I looked at ?integ
I have got a list named "filtered", I would like to construct alist named
"fdata" as following:
fdata <- cbind(matrix(unlist(filtered),ncol=28), myregime)
If I try names(filtered), it gives all the correct name for each vector, but
if I try names(fdata), it appears "filtered[[1]]"
Hi,
Either of the following should work (I assume there are 28 elements in your
list):
fdata <- cbind(as.matrix(as.data.frame(filtered)), myregime)
fdata <- cbind("colnames<-"(matrix(unlist(filtered),ncol=28),
names(filtered)), myregime)
--- livia <[EMAIL PROTECTED]> wrote:
>
> I hav
livia wrote:
> I have got a list named "filtered", I would like to construct alist named
> "fdata" as following:
>
> fdata <- cbind(matrix(unlist(filtered),ncol=28), myregime)
>
> If I try names(filtered), it gives all the correct name for each vector, but
> if I try names(fdata), it ap
On Monday 17 September 2007, you wrote:
> R 2.6.0 has Reduce;
>
> myvec <- c(2, 8, 24, 26, 51, 57, 58, 78, 219)
> Reduce(function(myvec, p) setdiff(myvec, findSubsets2(p)), myvec, myvec)
Thanks Gabor, at first I jumped off my chair but... for many input variables
it takes to reduce the vector. M
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Dear All,
I tried to aggregate the rows according to some factors in a data frame.
I got the
"Error in Summary.factor(..., na.rm = na.rm) :
sum not meaningful for factors"
message. This problem was once already discussed in 2003 on this list,
where the following solution was given: inclu
Hello,
I am using a number of large matrices in a project. I read a couple of the
matrices using the read.csv command. However in some instances, R does not
recognize the resulting matrices as consisting of numerical values (I
suspect R considers them as strings or factors)
for instance when I
On 9/17/07, Ptit_Bleu <[EMAIL PROTECTED]> wrote:
> I have a data frame of 2 columns with the following types :
> data$day char
> data$value num
>
> And I plot my data with :
> plot(strptime(donnees$day,format="%Y-%m-%d %H:%M:%S"),donnees$value,
> type="l")
>
> And I'd just like to get the numerical
I have two sets of data in data frames (different dimensions). Now, I
am able to make boxplots for one of these. I am using a formula, which
gives me three boxplots which is automatically placed at at = c(1:3),
since there are three groups. However, I would now like to add data
from the other dat
On 9/17/07, snapperball <[EMAIL PROTECTED]> wrote:
> I am using a number of large matrices in a project. I read a couple of the
> matrices using the read.csv command. However in some instances, R does not
> recognize the resulting matrices as consisting of numerical values (I
> suspect R considers
Hi All,
I would like to fill the area under a curve with a gradient of colors. Are
there any packages or trick I could use
Thanks
Stefan
Stefan Van Dongen
Antwerp
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing li
Thanks, Frank - it doesn't work though.
Your suggestion was:
Test=function(obj,labe)
{
label(obj)=labe
#at this point add the line:
obj
}
#...but just returning the object does not permanently change the label:
obj
That is why I wanted to use assign. But "assign" will not work with
attributes,
On 17-Sep-07 13:18:10, snapperball wrote:
>
> Hello,
>
> I am using a number of large matrices in a project. I read a
> couple of the matrices using the read.csv command. However
> in some instances, R does not recognize the resulting matrices
> as consisting of numerical values (I suspect R con
Hi,
When we install windows R 2.5.1 on a network drive ( the "P: ' drive,
actually a samba public share )
R runs well but the windows help is unavailable.
It complains about "Navigation to the webpage was cancelled"
Does anyone know how to fix that?
Thanks, Bill
_
Bill Szkotnicki wrote:
> Hi,
> When we install windows R 2.5.1 on a network drive ( the "P: ' drive,
> actually a samba public share )
> R runs well but the windows help is unavailable.
> It complains about "Navigation to the webpage was cancelled"
> Does anyone know how to fix that?
This has
Hi R Gurus
I'm using get.hist.quote to obtain monthly historical data.
This results in a zoo series.
I would like to convert the zoo series to a time series within a
function. How do I get the starting date for the ts from the zoo
series, please?
Thanks,
Edna Bell
as.ts(z) will convert zoo object z to a ts object. The get.hist.quote
retclass= argument can be used to directly output a ts object.
On 9/17/07, Edna Bell <[EMAIL PROTECTED]> wrote:
> Hi R Gurus
>
> I'm using get.hist.quote to obtain monthly historical data.
>
> This results in a zoo series.
>
>
Dear all,
I am using the heatmap representations of latticeExtra package and I
would be interested to draw color side bars representing the groups of a
factor of interest. From my understanding of :
> help(dendrogramGrob)
...
The 'add' argument can be used for additional annotation at the
If I type the line below at my Rprompt, it works fine. But, if I put the
same line in a file called systest.R and then source that file at
the prompt, nothing happens. IF I use R CMD BATCH, it also works in that
the system.time info is the .Rout file. Is there something I
can do so that this line a
Try this:
source("myfile.R", echo = TRUE)
On 9/17/07, Leeds, Mark (IED) <[EMAIL PROTECTED]> wrote:
> If I type the line below at my Rprompt, it works fine. But, if I put the
> same line in a file called systest.R and then source that file at
> the prompt, nothing happens. IF I use R CMD BATCH, it
> The predict.rpart() function from the rpart library allows for
> calculating the class probabilities for a given test case instead of a
> discrete class label.
> How are these class probabilities derived? Is it simply the proportion
> of the majority class to all cases in a leaf node?
Th
On 9/17/07, audrey <[EMAIL PROTECTED]> wrote:
> Dear all,
>
> I am using the heatmap representations of latticeExtra package and I
> would be interested to draw color side bars representing the groups of a
> factor of interest. From my understanding of :
>
> > help(dendrogramGrob)
> ...
> The
Steve Powell wrote:
>
> Thanks, Frank - it doesn't work though.
> Your suggestion was:
>
Test=function(obj,labe)
{
label(obj)=labe
#at this point add the line:
obj
}
> #...but just returning the object does not permanently change the label:
> obj
It does for me. Please re-run. -Fra
On 9/17/07, Ptit_Bleu <[EMAIL PROTECTED]> wrote:
> I have a data frame of 2 columns with the following types :
> data$day char
> data$value num
>
> And I plot my data with :
> plot(strptime(donnees$day,format="%Y-%m-%d %H:%M:%S"),donnees$value,
> type="l")
>
> And I'd just like to get the numeri
May I ask a related question to tack on to this thread.
One can also output a wmf plot to a file through the win.metafile() call.
But as the help file says, due to Windows limitations only one plot per file
is allowed and one must use parameterized filenames to produce multiple
plots, which I ofte
Rolf Turner-3 wrote:
>
>
> In the course of revising a paper I have had occasion to attempt to
> maximize a rather
> complicated log likelihood using the function nlm(). This is at the
> demand of a referee
> who claims that this will work better than my proposed use of a home-
> grown i
Hi Kim,
You could try:
substr("060907_17_3_5_1_1_2909.tif", start = 1, stop = 18)
?substr
cheers,
Paul
Kim Milferstedt schreef:
> Hello,
>
> I would like to remove the last 8 digists of character strings in a
> vector. Below I added a couple of elements from that vector.
>
> I have a problem de
test <- c("060907_17_3_5_1_1_2909.tif", "060907_17_3_5_2_1_2910.tif",
"060907_17_3_5_3_1_2911.tif")
sub('[[:digit:]][[:digit:]][[:digit:]][[:digit:]]\.tif', '', test)
or
test <- c("060907_17_3_5_1_1_2909.tif", "060907_17_3_5_2_1_2910.tif",
"060907_17_3_5_3_1_2911.tif")
sub('[[:digit:]]{4}\.ti
Hi everybody,
If I've a data frame like this:
dataframe a
X0 X2 X4 X6 X8 X10 X12 X14 X16
1957 0 0 0 0 0 0 0 0 0
1958 0 0 0 0 0 0 0 0 0
1959 831 0 0 0 0 0 0 0 0
1960 544 282 0 0 0 0 0 0 0
1961 446 365 0 0 0 0 0
Ciao,
do you mean the number of records?
something like
nrow(a)
I would also suggest ncol(a) instad of length, which would work for a matrix as
well.
[Italian]
E' quello che cercavi?
[/Italian]
Ciao
Stefano
On Mon, Sep 17, 2007 at 06:05:58PM +0200, Alfredo Alessandrini wrote:
Hi everybody
I believe you're looking for:
dim(a)
dim(a)[1] # Number of observations, in your example, 12
dim(a)[2] # Number of variables per observation, in your example, 9
--Jeff.
On Sep 17, 2007, at 12:05 PM, Alfredo Alessandrini wrote:
> Hi everybody,
>
> If I've a data frame like this:
>
> datafram
For the sake of absolute correctness:
> sub('[[:digit:]]{4}\.tif', '', test)
should be
sub('[[:digit:]]{4}\\.tif', '', test)
-- Jeff.
On Sep 17, 2007, at 11:59 AM, Jeffrey Robert Spies wrote:
> test <- c("060907_17_3_5_1_1_2909.tif", "060907_17_3_5_2_1_2910.tif",
> "060907_17_3_5_3_1_2911.tif
Dear all,
I'm trying to get the variance/covarince matrix after fitting a
quantile regression model (either linear or non linear), in order to get
the variance of my predictions and be able to calculate the median
squared error.
The commands working for the lm models (corr=T or vcov=T) do not se
Please note that the second expression below should be:
sub('[[:digit:]]{4}\\.tif', '', test)
The backslashes must be doubled: (from the ?regexpr Help file:
"Patterns are described here as they would be printed by cat: do remember
that backslashes need to be doubled when entering R character st
Hi all,
I understand that it is simple to create data with a specific
correlation (say, .5) using mvrnorm from the MASS library:
> library(MASS)
> set.seed(1)
>
> a=mvrnorm(
+ n=10
+ ,mu=rep(0,2)
+ ,Sigma=matrix(c(1,.5,.5,1),2,2)
+ ,empirical=T
+ )
> a
?loess
Charles Annis, P.E.
[EMAIL PROTECTED]
phone: 561-352-9699
eFax: 614-455-3265
http://www.StatisticalEngineering.com
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of zhijie zhang
Sent: Monday, September 17, 2007 1:19 PM
To: [EMAIL PROTECTED
A question for anyone using Tinn-R: I find that using the default color
scheme with the white background on my laptop hard on the ole' eyes. I
see the drop-down menus leading to the ability to change the colors of
individual components (numbers, commmands, strings, etc, and the
background for eac
Maybe this information (from the R's father) can be of some help.
http://www.stat.auckland.ac.nz/~ihaka/Graphics/index.html
Van Dongen Stefan wrote:
>
> Hi All,
>
> I would like to fill the area under a curve with a gradient of colors. Are
> there any packages or trick I could use
>
> Thank
Hi, everyone:
R is new to me. I am writing a nested loop to simulate data for t-test.
The following code is wrong. The subscript is out of bounds. Could anyone tell
me how to revise it? Thanks, Riddle Chin.
result<-matrix(ncol=5, nrow=1000)
colnames(result)<-c('N=20','N=40','N=60','N=8
Riddle Chin wrote:
>
> Hi, everyone:
> R is new to me. I am writing a nested loop to simulate data for
> t-test. The following code is wrong. The subscript is out of bounds. Could
> anyone tell me how to revise it? Thanks, Riddle Chin.
>
> result<-matrix(ncol=5, nrow=1000)
> colnames
On Tue, 2007-09-18 at 01:19 +0800, zhijie zhang wrote:
> Dear friends,
> In S-PLUS, we can use the following argument, but not in R.
> mode12 <- gam(score1 ~ lo(latitude) + lo(longitude))
> I searched the help in S-PLUS, it says lo() Allows the user to specify a
> Loess fit in a GAM formula, but
xlab=expression(bar(temp))
or
xlab=expression(bar(" temp"))
The overbar looks like it begins above "e" in the first case.
See demo(plotmath).
Jason Horn wrote:
>
> Can anyone tell me how to produce a macron (or overbar or overline)
> symbol on an R plot. I have an axis that is labeled "te
You need to say
summary(rq(),cov=TRUE)$cov
see
?summary.rq
for further details.
url:www.econ.uiuc.edu/~rogerRoger Koenker
email[EMAIL PROTECTED]Department of Economics
vox: 217-333-4558University of Illinois
fax: 217
On Mon, 17 Sep 2007, Charles Annis, P.E. wrote:
> ?loess
packages gam and mgcv both provide gam() functions in R: package gam is
very close to the S(-PLUS) implementation and would fit the model given
(in so far as we can tell from a non-reproducible example).
loess will allow a general smooth
You could use a loop and fill small polygons with colors.
x<-seq(-3, 3, .01)
y<-eval(expression(x^3-3*x))
plot(x,y, type="n", las=1)
n<-length(x)
# vertical bars
for(i in 1:n)
{
polygon(c(x[i], x[i], x[i+1], x[i+1]), c(min(y), y[i], y[i+1], min(y)),
border=0, col = rainbow(n)[i])
}
## or sp
On Fri, 14-Sep-2007 at 02:18PM -0400, jim holtman wrote:
|> This should do what you want.
|>
|> x<-c(26:52,1:25)
|> y<-rnorm(52)+1:52
|>
|> plot(seq_along(x), y, xaxt='n')
|> axis(1, at=seq_along(x), labels=x)
And if you have to economize on keystrokes,
seq(x) will achieve the same as seq_alon
Here is one way of doing it:
> v1
[1] 1 1 NA NA 1 NA NA NA NA 1 1 1 NA 1 NA 1 NA NA 1 NA
> v2
[1] NA 1 NA 1 1 1 1 1 NA 1 1 NA 1 1 NA NA NA 1 NA 1
> which(!(is.na(v1) | is.na(v2)))
[1] 2 5 10 11 14
>
On 9/17/07, dxc13 <[EMAIL PROTECTED]> wrote:
>
> useR's
>
> I am trying
Hi
I am trying to use various techniques (eg svm, logistic regression,
neural networks) to classify and predict the outcome of horse races.
Most of my predictive features are categorical - horse, jockey, trainer
- and I keep on running out of memory owing to the size of the vector.
Does any
But not necessarily performance. Look at the code for 'seq' and
'seq_along'. Time difference may be small, but keystrokes are done
only once.
On 9/17/07, Patrick Connolly <[EMAIL PROTECTED]> wrote:
> On Fri, 14-Sep-2007 at 02:18PM -0400, jim holtman wrote:
>
> |> This should do what you want.
>
Hi All,
Following from https://stat.ethz.ch/pipermail/r-help/1999-April/003834.html
this post where someone was asking for "a slick way of asking for the
results of doing a forward selection/backward elimination routine?" and
someone answered "Call step(), print the anova component of the resul
Is there a simple way to plot a histogram with colors?
For example, suppose I generate random points in the
N(2,1) distribution:
x <- rnorm(10, mean = 2, sd = 1)
Now I would like to plot the histogram:
hist(x)
but I would like to show the bars with x < 0 in red, and the
bars with x >=
On Mon, 2007-09-17 at 14:00 -0400, Jason Horn wrote:
> Can anyone tell me how to produce a macron (or overbar or overline)
> symbol on an R plot. I have an axis that is labeled "temp", but I
> need the overbar symbol over the entire word.
See ?plotmath and the examples therein.
Example:
p
"hadley wickham" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Many of the presentations and posters from UseR! 2007 are now available
> online:
> http://user2007.org/program/
The UseR 2006 conference info and presentations are part of
www.r-project.org, namely http://www.r-proj
hello,
i want to install the rimage package (0.5-7) into my R (2.5.1).
i installed the
"i686-apple-darwin8-g++-4.0.1 (GCC) 4.0.1 (Apple Computer, Inc. build
5367)"
from the macOS cd and created symbolic links to gcc and g++.
well if i try now to install the package in R the console says:
g++
Wensui Liu wrote:
>
> Dear Listers,
> I have a general statistical question. Are hurdle logit-poisson model
> and posson model nested?
>
You might have to give us a little more detail. On first glance, my
impression
is that the Poisson model is _not_ nested in the hurdle-Poisson, because t
ThatDeadDude wrote:
>
> I have been trying for hours now to perform an orthogonal contrast through
> an ANOVA in R.
>
> I have done a two-factor factorial experiment, each factor having three
> levels. I converted this dataset to a dataframe with one factor with nine
> treatments, as I cou
Hello,
I would like to remove the last 8 digists of character strings in a
vector. Below I added a couple of elements from that vector.
I have a problem defining a pattern to replace the digits using for
example "sub". Removing the ".tif" part works fine using
sub('.tif',"",x), but how do I ge
Dear friends,
In S-PLUS, we can use the following argument, but not in R.
mode12 <- gam(score1 ~ lo(latitude) + lo(longitude))
I searched the help in S-PLUS, it says lo() Allows the user to specify a
Loess fit in a GAM formula, but i didn't find the correponding function in
R.
Anybody knows how
?str
On 9/17/07, Alfredo Alessandrini <[EMAIL PROTECTED]> wrote:
> Hi everybody,
>
> If I've a data frame like this:
>
> dataframe a
>
> X0 X2 X4 X6 X8 X10 X12 X14 X16
> 1957 0 0 0 0 0 0 0 0 0
> 1958 0 0 0 0 0 0 0 0 0
> 1959 831 0 0 0 0 0 0
Not really but a better plot call would be
plot(x.hist,col=ifelse(x.hist$breaks<0,"red","green"))
Ross Darnell
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Alberto Monteiro
Sent: Tuesday, 18 September 2007 6:12 AM
To: [EMAIL PROTECTED]
Subject: [R]
Can anyone tell me how to produce a macron (or overbar or overline)
symbol on an R plot. I have an axis that is labeled "temp", but I
need the overbar symbol over the entire word.
Thanks,
Dr. Jason W. Horn
Research Associate
Boston University Department of Biology
5 Cumington Street Boston,
Colleagues,
I have an unusual problem; I am wondering whether anyone has dealt
with it and found a solution.
I have a script that needs to be encrypted. R will then be run on
the script. There are various means to decrypt the file, some of
which leave the decrypted code on the hard drive
Dear all,
Thanks to everyone who replied off list to my (rambling) question
earlier this year! I have put pointers to things I found useful over
here:
http://tinyurl.com/yvvvn9
Thought it might be helpful to share as now and again I receive
emails from people wondering if I ever made p
On Mon, 2007-09-17 at 15:56 -0700, Dennis Fisher wrote:
> Colleagues,
>
> I have an unusual problem; I am wondering whether anyone has dealt
> with it and found a solution.
>
> I have a script that needs to be encrypted. R will then be run on
> the script. There are various means to decrypt
useR's
I am trying to compare two vectors that have the same length. More
specifically, I am interested in comparing the corresponding positions of
each element in the vector.
Consider these two vectors of length 20:
v1 <- 224NA NA NA 10 NA NA NA NA NA NA NA NA NA NA
A couple of people have expressed an interest in having a look at the
problematic
code/package which led my cri de coeur posted yesterday.
I have therefore made the package accessible by putting it up on my
UNB web page:
http://www.math.unb.ca/~rolf
Click on ``Hidden generalized li
Hi Stephen,
How many variables do you have? How many of them are
categorical?
How many observations do you have?
Since I am not a racing expert, in how many races a
typical horse participates? How many years does it
usually span?
In the past I had a good experience with Random
Forest. There exis
*I would like to plot some semi-periodic signals as a function of the phase
expressed as a value in [0,2PI]*
*The problem is that the phase data is reported as the residual of the
division by 2PI.*
*For instance if the phase is 10.359 rd then:*
*15.359 / 6.283185 = 2*6.283185 + 2.79263*
*then onl
On 9/17/07, Alberto Monteiro <[EMAIL PROTECTED]> wrote:
> Is there a simple way to plot a histogram with colors?
>
> For example, suppose I generate random points in the
> N(2,1) distribution:
>
> x <- rnorm(10, mean = 2, sd = 1)
>
> Now I would like to plot the histogram:
>
> hist(x)
>
> b
On 9/17/07, Nair, Murlidharan T <[EMAIL PROTECTED]> wrote:
>
> I am calculating the median absolute deviation using mad function, and
> it tends to ignore the parameter constant=1, when I am calculating it
> for x=seq(1:5). Am I missing something here?
>
> x<-seq(1:5)
> mad(x)# gives [1] 1.4826
> m
I have read the gam() function in mgcv package, and find that it's
inappropriate for the additive model. So i didn't go further. I may
have solved it if i can search more info on gam.
Thanks a lot anyway, it has been solved with your help.
On 9/18/07, Prof Brian Ripley <[EMAIL PROTECTED]> wro
I am calculating the median absolute deviation using mad function, and
it tends to ignore the parameter constant=1, when I am calculating it
for x=seq(1:5). Am I missing something here?
x<-seq(1:5)
mad(x)# gives [1] 1.4826
mad(x, constant=1)# gives [1] 1
#Here is the long form
dev.from.median<-ab
Need more information. What is your operating system, how much memory
do you have, how big is your data, what operations are you failing on,
etc.
On 9/17/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Hi
>
> I am trying to use various techniques (eg svm, logistic regression,
> neural network
Hi all,
Thanks for the suggestions. I have not yet tried the apply ()
approach, but have tried to get the indexed version working, so far
with limited success. I realize that a transpose, as suggested,
would work, but want to avoid that for something simpler.
To repeat, the task is to perform
Below is one way to do this:
>
v1<-c(2,2,4,NA,NA,NA,10,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA)
>
v2<-c(NA,4,NA,NA,NA,NA,10,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA,NA,100,NA)
> length(v1)
[1] 20
> length(v2)
[1] 20
> intersect(which(!is.na(v1)),which(!is.na(v2)))
[1] 2 7
>
--- dxc13 <[EMAIL PROTECTED]> wro
Dear all:
Thank you very much for your help. Actually, I save the
plot(mfrow=c(2,3))as metafile, however, when I insert picture from the
file in word to import this plot picture, everything seems to be
shrinked. Is there anyone having good experience with import graph from
R to Word document?
Hi !
I have a shapefile that I can easily read into R using library(maptools). My
problem stems from some warning messages that come even though everything seems
to work fine.
library(maptools)
districts <- read.shape(filen = "a_ds", dbf.data = TRUE)
length(districts$Shapes)
so far so good. w
Admittedly, I don't have much experience with R. I have dowloaded and
installed some add-on packages (leaps, for one). When I try to run the
leaps function I get the following error:
Error: could not find function "leaps"
Any idea on what the problem could be? Thanks,
--
John R Pleis
__
I have found through experience to use win.metafile produce a .wmf file and
in word insert the picture as a file.
The trick is to do produce everything as it will appear in the word document.
Size is critical.
The width and height of the wmf file must be as it will appear in word eg
win.metafile
Hi R,
Again the problem in Bloomberg, I give the below code,
> con =
blpConnect(show.days="trading",na.action="previous.days",periodicity="da
ily")# connecting Bloomberg
> div <- blpGetData(con,"IBM US
Equity","EQY_DVD_HIST",start=as.chron(as.Date("01/01/2005",
"%m/%d/%Y")),end=as.chron(Sys
You need to print the result of an expression if used from source().
Autoprinting only occurs at the top level.
E.g.
% cat > systest.R
print(system.time(for(i in 1:100) mad(runif(1000
> source("systest.R")
user system elapsed
0.140.000.20
On Mon, 17 Sep 2007, Leeds, Mark (IE
On Tuesday 18 September 2007 07:23:17 [EMAIL PROTECTED] wrote:
jp > Admittedly, I don't have much experience with R. I have dowloaded and
jp > installed some add-on packages (leaps, for one). When I try to run the
jp > leaps function I get the following error:
jp >
jp > Error: could not find func
Hi David,
I tried the following and get the below error messages
con =
blpConnect(show.days="trading",na.action="previous.days",periodicity="da
ily")# connecting Bloomberg
> dat <- blpGetData(con,"US4009703799
Equity","PX_LAST",start=as.chron(as.Date("01/01/2005",
"%m/%d/%Y"),end=as.chron(Sy
On Mon, 17 Sep 2007, Dennis Fisher wrote:
> Colleagues,
>
> I have an unusual problem; I am wondering whether anyone has dealt
> with it and found a solution.
>
> I have a script that needs to be encrypted. R will then be run on
> the script. There are various means to decrypt the file, some of
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