Albert,
the output you show contains a column header, v1, and a row index, 1.
In order to access this information, you can for example use x[1,1].
read.table reads a table and thus expects rows and columns.
kind regards,
Ulrich
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On 05.07.2011, at 14:07, albert cos
On Tue, Jul 05, 2011 at 04:53:32PM +0200, albert coster wrote:
I'm taking this back to the list so others can follow up.
> Yes, the file is consists of one string (sequence) per line.
>
> The files format is following:
>
> Sequence
> NNATTAAAGGGC
OK - in that case (and as you want a
albert coster wrote:
>
> Dear all,
>
> I have a file with some sequence (seq.txt). I am writting following code
> and
> getting error! Can please help me?
>
>
> seqfile<-read.table(file="seq.txt")
> Warning message:
> In read.table(file = "seq.txt") :
> incomplete final line found by readTa
On Tue, Jul 05, 2011 at 02:06:02PM +0200, albert coster wrote:
> seqfile
> V1
> 1 NNATTAAAGGGC
>
> I want only NNATTAAAGGGC .
If I understand correctly, your file simply contains one string
(sequence) per line. In that case you may want to use scan() instead
seqfile
V1
1 NNATTAAAGGGC
I want only NNATTAAAGGGC .
Thanks
Albert
On Tue, Jul 5, 2011 at 1:58 PM, Ben Bolker wrote:
> albert coster gmail.com> writes:
>
> >
> > Dear all,
> >
> > I have a file with some sequence (seq.txt). I am writting following code
albert coster gmail.com> writes:
>
> Dear all,
>
> I have a file with some sequence (seq.txt). I am writting following code and
> getting error! Can please help me?
>
> seqfile<-read.table(file="seq.txt")
> Warning message:
> In read.table(file = "seq.txt") :
> incomplete final line found b
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