Thanks for all the replies.
The merge solution is what I was groping toward but the factor solution is much
cleaner since I do know in advance what the possible categories are.
François
On Aug 14, 2012, at 2:39 , PIKAL Petr wrote:
> Hi
>
> If your x and y are factors it seems to be easy, jus
Hi
If your x and y are factors it seems to be easy, just add all levels in both.
x.f<-factor(x, levels=1:5)
y.f<-factor(y, levels=1:5)
table(x.f)+table(y.f)
x.f
1 2 3 4 5
1 2 2 2 1
If you just have output from table(x) without possibility to add levels you can
go with merge
> mm <- merge(a
Hello,
My earlier solution has a problem. If you have billions of counts over
~150 categories, it will recreate the full vectors every time you add a
new category, thus causing potential memory issues. Another, much more
complicated, way but using only the tables info is as follows.
twotabl
If you know all of the categories in advance, you can convert x and y to
factors and then sum the tables:
> x<-1:4
> y<-2:5
> x <- factor(x , levels=1:5) # list all possible categories
> y <- factor(y , levels=1:5)
> table(x)
x
1 2 3 4 5
1 1 1 1 0
> table(y)
y
1 2 3 4 5
0 1 1 1 1
> table(c(x,
Hello,
This one will do it.
x <- 1:4
y <- 2:5
t1 <- table(x)
t2 <- table(y)
(xy <- c(rep(names(t1), t1), rep(names(t2), t2)))
table(xy)
Hope this helps,
Rui Barradas
Em 13-08-2012 19:25, Francois Pepin escreveu:
Hi everyone,
Is there an easy way to combine the counts from table()?
Let's
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