On Jan 23, 2011, at 6:00 PM, Thomas Stewart wrote:
Here is a hack, crude solution to get the digits:
Digits <- function(a){
out <- rep(NA,nchar(a))
for(i in 1:nchar(a)) out[i] <- substr(a,i,i)
return(as.numeric(out))
}
Digits(183429)
str1 <- c(12345, 34567, 45678)
sapply(strsplit(as.charact
On Jan 23, 2011, at 6:00 PM, Thomas Stewart wrote:
Here is a hack, crude solution to get the digits:
Digits <- function(a){
out <- rep(NA,nchar(a))
for(i in 1:nchar(a)) out[i] <- substr(a,i,i)
return(as.numeric(out))
}
Digits(183429)
str1 <- c(12345, 34567, 45678)
sapply(strsplit(as.char
Here is a hack, crude solution to get the digits:
Digits <- function(a){
out <- rep(NA,nchar(a))
for(i in 1:nchar(a)) out[i] <- substr(a,i,i)
return(as.numeric(out))
}
Digits(183429)
If all you want is the last three numbers, consider another hack solution:
Last3Digits <- function(a) a
Do you want to store each digit as a separate character, or if you
want to compare the last three digits with other numbers, then use the
"%%" operator.
> x <- 12345
> x %% 1000
[1] 345
On Sun, Jan 23, 2011 at 1:39 PM, Quan Zhou wrote:
> Hi Everyone,
> A quick question how to store a number lik
On Jan 23, 2011, at 1:39 PM, Quan Zhou wrote:
Hi Everyone,
A quick question how to store a number like 12345 to a vector or
array with
size(1,5), like 1, 2, 3, 4, 5
?strsplit
?unlist
So I can compare if the last three digits of this number is the same
with
some other numbers.
Davi
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