Skew as they are, your data certainly don't look normal. Try lognormal.
The chi-square test gives good results when all counts are 5 or more,
hence the warning.
At 12:25 AM 11/12/2010, Andrew Halford wrote:
Hi All,
I have a dataset consisting of abundance counts of a fish and I want to test
You can compute the conditional probability that your variable equals k given
that it is non-zero. For example, if X has poisson distribution with parameter
lambda then
P(X=k/X!=0) = P(X=k)/(1-P(X=0)) = (exp(-lambda)/(1-exp(-lambda))*lambda^k/k!
Now you can find lambda for which the sum of square
Hi Edna,
You could use lapply or sapply to perform the multiple goodness of fit
tests at the same time.
Chunhao
Quoting Edna Bell <[EMAIL PROTECTED]>:
Dear R Gurus;
Is there an automated process for goodness of fit tests, please?
I know there is prop.test for one at a time, but I was wo
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