> On Oct 19, 2016, at 9:41 AM, Jeff Newmiller wrote:
>
> When I replace length with nchar, it works fine for me without mapply.
>
> substr( rep( s, nchar(s) ), 1, seq.int( nchar(s) ) )
I failed to make the second `nchar` -> `length` substitution. It now works for
me as well.
--
David
> --
When I replace length with nchar, it works fine for me without mapply.
substr( rep( s, nchar(s) ), 1, seq.int( nchar(s) ) )
--
Sent from my phone. Please excuse my brevity.
On October 19, 2016 9:36:25 AM PDT, David Winsemius
wrote:
>
>> On Oct 19, 2016, at 8:44 AM, Jeff Newmiller
> wrote:
>>
> On Oct 19, 2016, at 8:44 AM, Jeff Newmiller wrote:
>
> These don't look like "suffixes" to me, but whatever.
>
> s <- "abc"
> substr( rep( s, length(s) ), 1, seq.int( length(s) ) )
I suspect that `nchar` was meant instead of `length` but it still failed. How
about:
lets <- paste0(letters,
These don't look like "suffixes" to me, but whatever.
s <- "abc"
substr( rep( s, length(s) ), 1, seq.int( length(s) ) )
--
Sent from my phone. Please excuse my brevity.
On October 19, 2016 8:01:10 AM PDT, Witold E Wolski wrote:
>Is there a build in function, which creates n suffixes of length
purrr::map(paste0(letters, collapse=""), ~purrr::map2_chr(.,
1:nchar(.), ~substr(.x, 1, .y)))[[1]]
seems to crank really fast at least on my system
what did you try that was slow?
On Wed, Oct 19, 2016 at 11:01 AM, Witold E Wolski wrote:
> Is there a build in function, which creates n suffixes o
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