Hi,
I checked the same with strptime. It is the rounding issue.
Try this:
dat1<-data.frame(datetime=c("2012-06-15 16:32:39.0025 CEST","2012-06-15
16:32:39.0086 CEST"))
op<-options(digits.secs=4)
dat1$datetime<- strptime(dat1$datetime, "%Y-%m-%d %H:%M:%OS")
formatC(as.numeric(difftime(dat1[
On Jun 15, 2012, at 20:33 , Rui Barradas wrote:
> Hello,
>
> A classic of floating-point accuracy is
>
> > 3/5 - 3/5
> [1] 0
> > 3/5 - (2/5 + 1/5)
> [1] -1.110223e-16
> > 3/5 - 2/5 - 1/5
> [1] -5.551115e-17
>
> Rui Barradas
>
Yes. There are only about 16 significant digits in (64 bit) floati
Hello,
A classic of floating-point accuracy is
> 3/5 - 3/5
[1] 0
> 3/5 - (2/5 + 1/5)
[1] -1.110223e-16
> 3/5 - 2/5 - 1/5
[1] -5.551115e-17
Rui Barradas
Em 15-06-2012 18:18, David Winsemius escreveu:
On Jun 15, 2012, at 12:49 PM, Julia wrote:
Hello,
I wanted to compute the time differenze
On Jun 15, 2012, at 12:49 PM, Julia wrote:
Hello,
I wanted to compute the time differenze between to times:
first =as.POSIXct( "2012-06-15 16:32:39.0025 CEST")
second = as.POSIXct("2012-06-15 16:32:39.0086 CEST")
second - first
The result is
Time difference of 0.006099939 secs
instead of j
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