On Fri, 21 Apr 2017, peter dalgaard wrote:
Also, as far as I know just for historical consistency, the test
statistic in R is the rank sum of the first group MINUS its minimum
possible value: W = 110.5 - sum(1:13) = 19.5
Ah, yes, I meant to add that remark. And coin::wilcox_test always comput
Also, as far as I know just for historical consistency, the test statistic in R
is the rank sum of the first group MINUS its minimum possible value: W = 110.5
- sum(1:13) = 19.5
-pd
> On 21 Apr 2017, at 14:54 , Achim Zeileis wrote:
>
> On Fri, 21 Apr 2017, Tripoli Massimiliano wrote:
>
>> De
Try setting the 'correct' argument to FALSE (similar to CORRECT=NO
option in the SAS documentation).
The p-values are then identical, although the W values are different.
Additionally I cannot understand why you get a warning from R that it
cannot compute exact p-values because of ties, while
On Fri, 21 Apr 2017, Tripoli Massimiliano wrote:
Dear R users,
Why the result of Wilcoxon sum rank test by R is different from sas
https://support.sas.com/documentation/cdl/en/statug/63033/HTML/default/viewer.htm#statug_npar1way_sect022.htm
The code is next:
sampleA <- c(1.94, 1.94, 2.92, 2.9
Hello there
Was looking up a similar problem yesterday and came across the gMWT package
(Generalized Mann-Whitney Type Tests). It addresses your problem, although I
am still trying to figure out how it works.
Kind regards,
David
--
View this message in context:
http://r.789695.n4.nabble.com/
On 2012-09-20 21:07, Thomas Lumley wrote:
On Fri, Sep 21, 2012 at 6:43 AM, avinash barnwal
wrote:
Hi,
http://en.wikipedia.org/wiki/Wilcoxon_signed-rank_test
We can clearly see that null hypothesis is median different or not.
One way of proving non difference is P(X>Y) = P(X
Avinash. No.
F
On Fri, Sep 21, 2012 at 6:43 AM, avinash barnwal
wrote:
> Hi,
>
> http://en.wikipedia.org/wiki/Wilcoxon_signed-rank_test
>
> We can clearly see that null hypothesis is median different or not.
> One way of proving non difference is P(X>Y) = P(X ordered.
Avinash. No.
Firstly, the Wikipedia link
Hi,
http://en.wikipedia.org/wiki/Wilcoxon_signed-rank_test
We can clearly see that null hypothesis is median different or not.
One way of proving non difference is P(X>Y) = P(X wrote:
>
> On Sep 20, 2012, at 02:43 , Thomas Lumley wrote:
>
>> On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Anib
On Sep 20, 2012, at 02:43 , Thomas Lumley wrote:
> On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Aniba
> wrote:
>> Hello All,
>>
>> I am writing to ask your opinion on how to interpret this case. I have two
>> vectors "a" and "b" that I am trying to compare.
>>
>> The wilcoxon test is gi
Hi,
In Wilcoxon test , we look for medians rather than the means. Ratio of
medians should be more coherent with P value.
On Thu, Sep 20, 2012 at 6:30 PM, Ben Bolker wrote:
> Mohamed Radhouane Aniba gmail.com> writes:
>
> >
> >
> > Thank you Thomas,
> >
> > So you think a t-test is more adequat
Mohamed Radhouane Aniba gmail.com> writes:
>
>
> Thank you Thomas,
>
> So you think a t-test is more adequate to use in this case ?
>
> Rad
No, because a t-test makes even stronger parametric assumptions.
You were given more specific advice on stackoverflow
http://stackoverflow.com/questi
Thank you Thomas,
So you think a t-test is more adequate to use in this case ?
Rad
On Sep 19, 2012, at 8:43 PM, Thomas Lumley wrote:
> On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Aniba
> wrote:
>> Hello All,
>>
>> I am writing to ask your opinion on how to interpret this case. I hav
On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Aniba
wrote:
> Hello All,
>
> I am writing to ask your opinion on how to interpret this case. I have two
> vectors "a" and "b" that I am trying to compare.
>
> The wilcoxon test is giving me a pvalue of 5.139217e-303 of a over b with the
> alter
On Aug 8, 2012, at 18:16 , BELLAY Juliette wrote:
> Dear list,
>
> I am facing a problem in my statistical analyses on R.
> My experiments are about plants, I record there growth after each cutting
> (every 3 weeks).
> 'BC' is for the plant, and '1' to '5' is the time of cutting and recording.
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Jun Shen
> Sent: Thursday, February 16, 2012 10:16 AM
> To: R-help
> Subject: [R] Wilcoxon test p value with one decimal place
>
> Dear list,
>
> Let's say I have data
>
> a=c
On 16-Feb-2012 Bert Gunter wrote:
> On Thu, Feb 16, 2012 at 10:15 AM, Jun Shen wrote:
>> Dear list,
>>
>> Let's say I have data
>>
>> _a=c(37.961,38.214,57.68)
>> _b=c(77.56,61.875,67.683)
>>
>>
>>
>> the wilcoxon test only gives me a p value with one decimal place. Is this
>> normal?
>
> No, it
On Thu, Feb 16, 2012 at 10:15 AM, Jun Shen wrote:
> Dear list,
>
> Let's say I have data
>
> a=c(37.961,38.214,57.68)
> b=c(77.56,61.875,67.683)
>
> wilcox.test(a,b)
>
> the wilcoxon test only gives me a p value with one decimal place. Is this
> normal?
No, it's discrete :-)
(Actually, that's
Thank you, David Winsemius and Dennis Murphy!
I want to compare pairs one by one.
2010/8/17 Iurie Malai :
> Dear R users,
>
> I have a dataset with two variables: $esan - a grouping factor with 8
> levels and $reus. I'd like to do wilcox.test on this dataset as
> sugested Weiwei here:
> https://
Hi:
As the help page for wilcox.test() states (?wilcox.test), the test is meant
for one or two groups. Since you have eight groups in your data, the help
page for wilcox.test() suggests using kruskal.test() instead, where the
latter function applies the Kruskal-Wallis test if your intention is to
On Aug 17, 2010, at 2:48 AM, Iurie Malai wrote:
Dear R users,
I have a dataset with two variables: $esan - a grouping factor with 8
levels and $reus. I'd like to do wilcox.test on this dataset as
sugested Weiwei here:
https://stat.ethz.ch/pipermail/r-help/2007-July/136627.html. I tried
to adap
Maybe, this will be better:
W <- as.matrix(lapply(Dataset[2:11], function(x) wilcox.test(x ~ GrFac,
alternative="two.sided", data=Dataset)$statistic))
P <- as.matrix(lapply(Dataset[2:11], function(x) wilcox.test(x ~ GrFac,
alternative="two.sided", data=Dataset)$p.value))
out <- rbind(as.numeric(W)
Sorry, Joris, now is wonderful! Thank you!
Now, this is the code:
W <- as.matrix(lapply(Dataset[2:11], function(x) wilcox.test(x ~ GrFac,
alternative="two.sided", data=Dataset)$statistic))
P <- as.matrix(lapply(Dataset[2:11], function(x) wilcox.test(x ~ GrFac,
alternative="two.sided", data=Datase
Can't reproduce those with your code and your dataset.
I also noticed some other unwanted behaviour by using as.numeric : it
changes the formatting again. You won't get rid of the "" as that
indicates it's a character, and you won't be able to format the
numbers as the columns in a dataframe or in
Thank you, Joris!
I received two identical warnings:
[14] WARNING: Warning in if (nchar(cmd) <= width) return(cmd) :
the condition has length > 1 and only the first element will be used
[15] WARNING: Warning in if (nchar(cmd) <= width) return(cmd) :
the condition has length > 1 and only the f
# not tested
out <- rbind(as.numeric(Wnew),as.numeric(P))
rownames(out) <- c("Wnew","P")
Cheers
On Sat, Jun 5, 2010 at 11:18 PM, Iurie Malai wrote:
> Hi!
>
> I searched some time ago a way to get the Wilcoxon test results as a table
> more or less formatted. Nobody told me any solution and I fou
On 2/1/2009 8:32 PM, Laura Lucia Prieto Godino wrote:
> Hi!
> I need to run a wilcoxon (Mann-whitly, in fact) test with bonferroni
> correction, as I am running 10 consecutive wilcoxon test not
> independent, and I know that bonferroni will partially correct for this
> problem, but I have no idea h
26 matches
Mail list logo
