Thats a good start but I am looking for more. Specifically (from previous
post):
4x4 matrix (based on the maximum number of factor levels in 'o') for each
'id' as a list.
Each matrix would have v in the diagonal and r*s*s in the off-diagonal
(e.g.,
.5*2.0814*.1095 = 0.1139), where
r is constant (
I missed; using the Hadley Wickham plyr package >library (plyr)> dlply(dat,
.(id))
$`1`
id o r v s
1 1 1 0.5 -1.7131858 -2.0548666
2 1 2 0.5 0.6582979 0.9688939
3 1 3 0.5 -0.6861830 2.4213072
4 1 4 0.5 1.4134171 -0.4540244$`2`
id o r v s
5 2 1
If i understood correctly this may help you > dlply(dat, .(id))
$`1`
id o r v s
1 1 1 0.5 -1.7131858 -2.0548666
2 1 2 0.5 0.6582979 0.9688939
3 1 3 0.5 -0.6861830 2.4213072
4 1 4 0.5 1.4134171 -0.4540244$`2`
id o r v s
5 2 1 0.5 0.2771839 1.06
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