Carlson
Sent: Thursday, June 13, 2013 9:00 AM
To: 'Shane Carey'; r-help@r-project.org
Subject: Re: [R] Remove levels
Works fine for me. Too bad you didn't include actual data:
> set.seed(42)
> DATA <- data.frame(UnitName_1=factor(sample(c("lake", "pond&q
95 97 47 54 86 14 88 8 99 35 ...
levels(DATA[,1])
#[1] "pond" "river"
A.K.
- Original Message -
From: David Carlson
To: 'Shane Carey' ; r-help@r-project.org
Cc:
Sent: Thursday, June 13, 2013 10:00 AM
Subject: Re: [R] Remove levels
Works fine for me.
Hi,
Without more information I guess your problem is that the level name
still exists in the factor whereas it doesn't appear anymore in the
factor. If so, try droplevels.
Alain Guillet
On 13/06/13 14:02, Shane Carey wrote:
> I have a dataframe consisting of factors in one column. Im trying t
Works fine for me. Too bad you didn't include actual data:
> set.seed(42)
> DATA <- data.frame(UnitName_1=factor(sample(c("lake", "pond",
"river"),
+ 15, replace=TRUE)), Var=sample.int(100, 15))
> DATA
UnitName_1 Var
1 river 95
2 river 97
3lake 12
4 river 4
Please read the Posting Guide, which among other things points out that you
should be posting in plain text format, not HTML (which tends to corrupt
example R code).
Then please explain why your problem is not addressed by the below referenced
section of the R Inferno. You may need to read [1]
Nope, but thanks
On Thu, Jun 13, 2013 at 1:11 PM, Albin Blaschka <
albin.blasc...@standortsanalyse.net> wrote:
>
>
> Am 13.06.2013 14:02, schrieb Shane Carey:
>
> I have a dataframe consisting of factors in one column. Im trying to
>> remove
>> certain levels using the following code:
>> toBeRe
Am 13.06.2013 14:02, schrieb Shane Carey:
I have a dataframe consisting of factors in one column. Im trying to remove
certain levels using the following code:
toBeRemoved1<-which(DATA$UnitName_1=="lake")
DATA<-DATA[-toBeRemoved1,]
However it will not remove the level "lake"
Hello!
Is this a
Adrian Dusa wrote:
Adrian Dusa gmail.com> writes:
[...snip...]
f[which(f %in% names(table(f))[table(f) >= 2]), drop=TRUE]
[1] a a
Levels: a
Or, more simple:
f[f %in% names(table(f))[table(f) >= 2], drop=TRUE]
[1] a a
Levels: a
Adrian
Also see the combine.levels function in the Hmisc pa
Adrian Dusa gmail.com> writes:
> > [...snip...]
> > f[which(f %in% names(table(f))[table(f) >= 2]), drop=TRUE]
> [1] a a
> Levels: a
Or, more simple:
> f[f %in% names(table(f))[table(f) >= 2], drop=TRUE]
[1] a a
Levels: a
Adrian
__
R-help@r-project.o
Yuan Jian yahoo.com> writes:
> [...snip...]
>
> I want to remove level b because level b has less than 2.
> > f
> [1] a a
> Levels: a
> f[which(f %in% names(table(f))[table(f) >= 2]), drop=TRUE]
[1] a a
Levels: a
HTH,
Adrian
__
R-help@r-project.or
Hi Yuan,
It is not ellegant, but may work for you..
f<-as.factor(c("a","b","a"))
f.freq<-data.frame(table(f))
f.freq
lower.freq<-2
f.freq.subset<-subset(f.freq,f.freq$Freq>=lower.freq)
f.freq.subset
f.selected<-f[f %in% f.freq.subset$f]
f.selected<-factor(f.selected)
f.selected
Best wishes,
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