Hi,
set.seed(15)
dat1<-data.frame(col1=rnorm(6),col2=rep(1:2,each=3),col3=rep(letters[1:3],2),col4=runif(6),col5=rep(LETTERS[3:5],2))
dat1[,sapply(dat1,class)!="factor"]
# col1 col2 col4
#1 0.2588229 1 0.5090904
#2 1.8311207 1 0.7066286
#3 -0.3396186 1 0.8623137
#4 0.8971982
Thanks to all who responded!
I've taken those responses, and found out what works:
myNumericColumns<-mydataframe[sapply(mydataframe, is.numeric)]
produces a subset of columns with just the numeric vectors.
Sincerely,
Barry
[[alternative HTML version deleted]]
__
Hello,
You should provide us with a data example, like the posting guide says.
Anyway, see the following example.
# make up some data
dat <- data.frame(X = 1:4, Y = rnorm(4), Z = letters[1:4])
str(dat)
# this returns the numeric/integer columns
dat[sapply(dat, is.numeric)]
Hope this helps,
Ru
http://stackoverflow.com/questions/5863097/selecting-only-numeric-columns-from-a-data-frame
John Kane
Kingston ON Canada
> -Original Message-
> From: bdecicco2...@yahoo.com
> Sent: Sat, 16 Feb 2013 10:15:35 -0800 (PST)
> To: r-help@r-project.org
> Subject: [R] Extracting Numeric Columns
Barry =
Suppose your data frame is called "mydat". Then something like
mydat[,sapply(mydat,class) %in% c('numeric','integer')]
might do what you want.
- Phil
On Sat, 16 Feb 2013, Barry DeCicco wrote:
Hello,
I've got a data frame wi
On Feb 16, 2013, at 12:15 PM, Barry DeCicco wrote:
> Hello,
>
> I've got a data frame with a mix of numeric, integer and factor columns.
> I'd like to pull out (or just operate only on) the numeric/integer columns.
> Every thing I've found in searches is about how to subset by rows,
> or how to
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