Hi Jim,
Thanks for the hint, that makes sense and I'll arrange accordingly.
Best regards,
Abdoulaye
On Thu, Aug 13, 2020 at 8:38 AM Jim Lemon wrote:
> Hi Abdoulaye,
> It looks to me as though your offsets are in hours, not days. You can
> get a rough date like this:
>
> time<-c(1569072,1569096,
Hi Abdoulaye,
It looks to me as though your offsets are in hours, not days. You can
get a rough date like this:
time<-c(1569072,1569096,1569120,1569144,
1569168,1569192,1569216,1569240)
time_d<-as.Date("1800-01-01")+time/24
time_d
[1] "1979-01-01" "1979-01-02" "1979-01-03" "1979-01-04" "1979-01-0
nice
On Wed, Aug 12, 2020 at 6:18 PM Bert Gunter wrote:
> Extra packages are not needed.
>
> My question is: why change the character representation at all? See the
> format argument of ?as.Date.
>
> > as.Date("20010102",format="%Y%m%d")
> [1] "2001-01-02" ## the default format for the print me
Extra packages are not needed.
My question is: why change the character representation at all? See the
format argument of ?as.Date.
> as.Date("20010102",format="%Y%m%d")
[1] "2001-01-02" ## the default format for the print method for Date objects
Bert Gunter
"The trouble with having an open m
library(lubridate)
a <- "20200403"
lubridate::ymd(a)
# 2020-04-03
HTH,
Eric
On Wed, Aug 12, 2020 at 5:57 PM Stephen P. Molnar
wrote:
> i have written an R script which allow me to plot the number of Covid-10
> cases reported by he state of Ohio. In that se t of data the date format
> is in the
Hi Patrick,
On Fri, Mar 18, 2011 at 12:17 PM, Patrick Connolly
wrote:
> On Wed, 16-Mar-2011 at 07:58PM -0700, Joshua Wiley wrote:
> |> ## A small example is always nice
> |> dat <- ts(1:12, frequency = 12,
> |> start = c(1998, 1), end = c(2010, 12))
> |>
> |> ## Achim and Gabor's wonderful pack
On Wed, 16-Mar-2011 at 07:58PM -0700, Joshua Wiley wrote:
|> Hi Erin,
|>
|> I am not sure what a "seq.Date object" is. My first thought is that
|> you are talking about the date method for seq(), but there are
|> hundreds of packages I do not know. In any case, here is what I think
|> you want.
On Mar 16, 2011, at 10:22 PM, Erin Hodgess wrote:
Dear R People:
I have a monthly time series which runs from January 1998 to
December 2010.
When I use tsp I get the following:
tsp(ibm$ts)
[1] 1998.000 2010.917 12.000
Is there an easy way to convert this to a seq.Date object, please
On Wed, Mar 16, 2011 at 10:22 PM, Erin Hodgess wrote:
> Dear R People:
>
> I have a monthly time series which runs from January 1998 to December 2010.
>
> When I use tsp I get the following:
>
>> tsp(ibm$ts)
> [1] 1998.000 2010.917 12.000
>
>
> Is there an easy way to convert this to a seq.Date
Hi Erin,
I am not sure what a "seq.Date object" is. My first thought is that
you are talking about the date method for seq(), but there are
hundreds of packages I do not know. In any case, here is what I think
you want.
Josh
## A small example is always nice
dat <- ts(1:12, frequency = 12,
s
Good morning,
try this:
#your date format
datum<-c("100907","101008","101109")
#convert it (works with and without as.Date)
datum<-as.Date(strptime(datum,("%y%m%d")))
plot(datum,5:7)
I hope it works for you
Hajo
Am 09.11.2010 06:37, schrieb sachinthaka.abeyward...@allianz.com.au:
> Hi All,
>
>
Hi,
I think you just need to add the format = argument. Does this help?
> x <- factor("01-11-2007")
> as.character(x)
[1] "01-11-2007"
> as.Date(as.character(x), format = "%d-%m-%Y")
[1] "2007-11-01"
Cheers,
Josh
On Fri, Sep 3, 2010 at 2:11 PM, André de Boer wrote:
>
> Hello,
>
> I have a da
On Wed, Aug 4, 2010 at 8:33 PM, Steven Kang wrote:
> Hi all,
>
> I am trying to convert all the dates (all days that are not Friday) in data
> frame into dates to next Friday.
>
> The following works but the result is returned as vector rather than the
> original class.
>
> It would be greatly app
a Wiley
> To: Felipe Carrillo
> Cc: r-h...@stat.math.ethz.ch
> Sent: Thu, June 10, 2010 1:18:27 PM
> Subject: Re: [R] Date conversion
>
> Hello Felipe,
Is this what you want?
format(as.Date("3/10/10",
> format="%m/%d/%y"), "%B %d, %Y")
Josh
O
Hello Felipe,
Is this what you want?
format(as.Date("3/10/10", format="%m/%d/%y"), "%B %d, %Y")
Josh
On Thu, Jun 10, 2010 at 8:29 AM, Felipe Carrillo
wrote:
> Hi:
> Can't find a way to convert from shortDate to LongDate format. I got:
> 3/10/10 that I want to convert to March 10, 2010. I am us
Thanks - that works
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Use %y indeed of "%Y".
On Wed, Mar 17, 2010 at 12:00 PM, ManInMoon wrote:
>
> I am parsing dates as follows:
>
>> z[1:10,1:3]
> V1 V2 V3
> 1 0 03/02/09 22:20:51.274
> 2 100 03/02/09 22:28:18.801
> 3 200 03/02/09 22:33:33.762
> 4 300 03/02/09 22:40:21.826
> 5 400 03/02/09
Sorry
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PLEASE
as.Date('17/02/2005','%d/%m/%Y')
[1] "2005-02-17"
(Read the documentation more carefully to distinguish between %y and
%Y; I guess you tried lots of combinations but never tried the
correct one, so just be more careful at matching what your data is
with the format string you create.)
-D
Hi
This is on WinXP with regional settings as EST (we are now on DST but I run
EST) R2.9.2
x <- structure(1254351600, class = c("POSIXt", "POSIXct"), tzone = "")
> x
[1] "2009-10-01 09:00:00 EST"
> as.POSIXlt(x)
[1] "2009-10-01 09:00:00 EST"
> as.Date(x, formate="%Y-%m-%d" )
[1] "2009-09-30"
Hi Uwe,
You are correct - that was a type O (52) and thanks for you your suggestion
that works..
Pele wrote:
>
>
>
> Hi R users,
>
> I have a factor variable called date as shown below: Can anyone share the
> best / most efficient way to extract year and week (e.g. year = 2006,
> week = 52
Hi,
There are possibly several ways to do this. My approach would be:
dates <- strptime(as.character(DATE), "%d%b%Y")
year <- dates$year + 1900
week <- floor(dates$yday/365 * 52)
HTH,
--sundar
On Thu, Mar 5, 2009 at 8:58 AM, Pele wrote:
>
> Hi R users,
>
> I have a factor variable called date
Pele wrote:
Hi R users,
I have a factor variable called date as shown below: Can anyone share the
best / most efficient way to extract year and week (e.g. year = 2006, week
= 52 for first record, etc..)? My data set has 1 million records.
DATE
11DEC2006
11SEP2006
01APR2007
02DEC2
Dr. Alireza Zolfaghari wrote:
> Hi List,
> If I have a date format as:
> d <- "2001/1/1"
> I can easily convert it to number by using as.Date(d).
Yes. If it means "January the 1st" and not "1st of January", that is...
> But if I have d<-"1/1/2001", it does not work. Does anyone know how I can
>
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