Thanks for the help guys! For my purpose I think that rharlow2's answer, i.e.
the `rowSums' function is the most appropriate since it also takes care of
the NAs.
Best,
Vassilis
--
View this message in context:
http://r.789695.n4.nabble.com/weighed-mean-of-a-data-frame-row-by-row-tp3177421p31
Em 6/1/2011 11:33, Vassilis escreveu:
Dear list,
This must be an easy one. I have a data frame like this one:
test.df <- data.frame(x1=c(2,3,5), x2=c(5, 3, 4), w=c(0.8, 0.3, 0.5))
and I want to construct a weighted mean of the first two columns using the
third column for weighting; i.e.
y[1]
Hi Vassilis,
Try
test.df$y <- with(test.df, x1*w + x2*(1-w))
test.df
HTH,
Jorge
On Thu, Jan 6, 2011 at 8:33 AM, Vassilis <> wrote:
>
> Dear list,
>
> This must be an easy one. I have a data frame like this one:
>
> test.df <- data.frame(x1=c(2,3,5), x2=c(5, 3, 4), w=c(0.8, 0.3, 0.5))
>
> and
Dear list,
This must be an easy one. I have a data frame like this one:
test.df <- data.frame(x1=c(2,3,5), x2=c(5, 3, 4), w=c(0.8, 0.3, 0.5))
and I want to construct a weighted mean of the first two columns using the
third column for weighting; i.e.
y[1] = x1[1]*w[1] + x2[1]*(1-w[1])
y[2] = .
4 matches
Mail list logo