ter. But I appreciate the
explanation and the solutions.
-Original Message-
From: PIKAL Petr
Sent: Monday, October 11, 2021 5:15 AM
To: Jiefei Wang ; Derickson, Ryan, VHA NCOD
Cc: r-help@r-project.org
Subject: [EXTERNAL] RE: [R] unexpected behavior in apply
Hi
it is not surpr
On Mon, 11 Oct 2021 09:15:27 +
PIKAL Petr wrote:
>
> data.frame is not matrix or array (even if it rather resembles one)
>
> So if you put a cake into oven you cannot expect getting fried
> potatoes from it.
Another fortune nomination!
cheers,
Rolf
--
Honorary Research Fellow
Depar
SE
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of Jiefei Wang
> Sent: Friday, October 8, 2021 8:22 PM
> To: Derickson, Ryan, VHA NCOD
> Cc: r-help@r-project.org
> Subject: Re: [R] unexpected behavior in apply
>
> Ok, it turns out that this is doc
Ok, it turns out that this is documented, even though it looks surprising.
First of all, the apply function will try to convert any object with
the dim attribute to a matrix(my intuition agrees with you that there
should be no conversion), so the first step of the apply function is
> as.matrix.da
Hello,
The issue comes that 'apply' tries to coerce its argument to a matrix. This
means that all your columns will become character class, and the result
will not be what you wanted. I would suggest something more like:
sapply(d, function(x) all(x[!is.na(x)] <= 3))
or
vapply(d, function(x) a
Hi,
I guess this can tell you what happens behind the scene
> d<-data.frame(d1 = letters[1:3],
+ d2 = c(1,2,3),
+ d3 = c(NA,NA,6))
> apply(d, 2, FUN=function(x)x)
d1 d2 d3
[1,] "a" "1" NA
[2,] "b" "2" NA
[3,] "c" "3" " 6"
> "a"<=3
[1] FALSE
> "2"<=3
[1] TRUE
>
Hello,
I'm seeing unexpected behavior when using apply() compared to a for loop when a
character vector is part of the data subjected to the apply statement. Below, I
check whether all non-missing values are <= 3. If I include a character column,
apply incorrectly returns TRUE for d3. If I onl
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