Re: [R] svm models in a loop

On Oct 12, 2008, at 2:26 AM, Prof Brian Ripley wrote: You need to use substitute() on the call. Something like sapply(1:5,function(i) eval(substitute(svm(person_oid ~ ., data=zrr[1:N,]), list(N=100*i)) ) Thanks! On Sun, 12 Oct 2008, Alexy Khrabrov wrote: I want to train sv

Re: [R] svm models in a loop

You need to use substitute() on the call. Something like sapply(1:5,function(i) eval(substitute(svm(person_oid ~ ., data=zrr[1:N,]), list(N=100*i)) ) On Sun, 12 Oct 2008, Alexy Khrabrov wrote: I want to train svm models on increasingly large training data subsets of some zrr as f

[R] svm models in a loop

I want to train svm models on increasingly large training data subsets of some zrr as follows: > m <- sapply(1:5,function(i) svm(person_oid~.,data=zrr[1:100*i,]))# (*) However, when I inspect m[1], it literally shows > m[1] [[1]] svm(formula = person_oid ~ ., data = zrr[1:N, ]) -- as