didn't get Henriques message in
my mailbox immediately for some reason -
-Ralph
___
Date: Wed, 13 Aug 2008 14:23:33 -0500
From: [EMAIL PROTECTED]
Subject: RE: [R] subsetting matrix according to columns with character
index
To: [EMAIL PROTECTED]
CC: r-help@r-pr
t; Subject: RE: [R] subsetting matrix according to columns with character
> index To: [EMAIL PROTECTED]
> it must be a dataframe so, if it was DF, then, assuming i understand
> what you want then either of the following should work:
> DFsub<-DF[DF$z == 1 & DF$z == 2,]
> or
>
a what to do?
-Ralph
> Date: Wed, 13 Aug 2008 13:05:25 -0500 From: [EMAIL PROTECTED]
> Subject: RE: [R] subsetting matrix according to columns with character
> index To: [EMAIL PROTECTED]
> it must be a dataframe so, if it was DF, then, assuming i understand
> what you want then
n a and c combination.
Any idea what to do?
-Ralph
> Date: Wed, 13 Aug 2008 13:05:25 -0500
> From: [EMAIL PROTECTED]
> Subject: RE: [R] subsetting matrix according to columns with character index
> To: [EMAIL PROTECTED]
>
> it must be a dataframe so, if it was DF, then, assuming i
Try this:
x
V1 V2 V3
1 a1 c1 1
2 a1 c1 2
3 a2 c1 1
4 a1 c2 1
5 a1 c2 2
lis <- split(x, list(x$V1, x$V2), drop = TRUE)
do.call(rbind, unname(lis[sapply(lis, function(x)all(1:2 %in% x[,3]))]))
On Wed, Aug 13, 2008 at 3:00 PM, Ralph S. <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I have a long m
Hi,
I have a long matrix of the following form which I would like to subset
according to the third column:
[x y z]:
a1 c1 1
a1 c1 2
a2 c1 1
a1 c2 1
a1 c2 2
. . .
The first two columns a characters ai and cj.
I would like to keep all the rows where there are two entries for z, 1 and 2.
Tha
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