On Oct 13, 2008, at 5:36 AM, Dieter Menne wrote:
Prof Brian Ripley stats.ox.ac.uk> writes:
Yes: DF[is.na(match(row.names(DF), exclude_me)), ]
Assuming everything is possible in R: would it be possible to make
the below
work without breaking existing code?
a <- data.frame(x=1:10)
rowna
On Mon, 13 Oct 2008, Dieter Menne wrote:
Prof Brian Ripley stats.ox.ac.uk> writes:
Yes: DF[is.na(match(row.names(DF), exclude_me)), ]
Assuming everything is possible in R: would it be possible to make the below
work without breaking existing code?
It would be possible, but not I think des
Prof Brian Ripley stats.ox.ac.uk> writes:
> Yes: DF[is.na(match(row.names(DF), exclude_me)), ]
Assuming everything is possible in R: would it be possible to make the below
work without breaking existing code?
a <- data.frame(x=1:10)
rownames(a) = letters[1:10]
exclude = c("a","c")
a[is.na(matc
On Sat, 11 Oct 2008, Alexy Khrabrov wrote:
Is there a way to select a subset of a dataframe consisting of all those rows
with rownames *except* from a subset of rownames to be excluded? Example:
Yes: DF[is.na(match(row.names(DF), exclude_me)), ]
a <- data.frame(x=1:10,y=10:1)
a <- a[order
Is there a way to select a subset of a dataframe consisting of all
those rows with rownames *except* from a subset of rownames to be
excluded? Example:
> a <- data.frame(x=1:10,y=10:1)
> a <- a[order(a$y),] # to make rownames differ visually
> a[8,]
x y
3 3 8
> a["8",]
x y
8 8 3
> a[-
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