On Mar 15, 2012, at 4:38 PM, G See wrote:
my.df <- data.frame(IDX=1:42, x=rnorm(1:42))
my.df[my.df$IDX %in% c(17, 42), ]
IDX x
17 17 -0.5110095
42 42 -1.0686427
subset(my.df, IDX %in% c(17,42) )
(I find subset to give clearer code than: df[which(df$colname cond>) , ], plus it c
On Thu, Mar 15, 2012 at 03:47:24PM -0500, G See wrote:
> On second thought, I must not understand your question because your
> code works fine for me.
>
> > my.df[ which(my.df$IDX == c(17, 42)), ]
>IDX x
> 17 17 -0.5110095
> 42 42 -1.0686427
Hi.
This seems to work due to the fact
On second thought, I must not understand your question because your
code works fine for me.
> my.df[ which(my.df$IDX == c(17, 42)), ]
IDX x
17 17 -0.5110095
42 42 -1.0686427
> my.df[my.df$IDX == c(17, 42), ]
IDX x
17 17 -0.5110095
42 42 -1.0686427
Can you provide samp
> my.df <- data.frame(IDX=1:42, x=rnorm(1:42))
> my.df[my.df$IDX %in% c(17, 42), ]
IDX x
17 17 -0.5110095
42 42 -1.0686427
Garrett
On Thu, Mar 15, 2012 at 3:25 PM, Ed Siefker wrote:
> I would like to subset by dataframe by matching all rows that have any value
> from a list of valu
I would like to subset by dataframe by matching all rows that have any value
from a list of values. I can get it to work if I have exactly one value,
I'm not
sure how to do it with a list of values though.
This works and gives me exactly one line:
my.df[ which( mydf$IDX==17)), ]
I would like to
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