Regarding : "... I don't know
what the 4th to last page would be called (could add another ante-, or
in R just use tail(book,4))..."
According to wordsmith.org (sign up it's free, note I have no affiliation to
that site) the word is "preantepenultimate".
Check it out:
http://wordsmith.org/words
Greg,
For some authors the 4th page from the back should be the first page.
Not so for you, however.
Clint
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360)
Philippe,
replies inline
On Sat, Feb 22, 2014 at 12:29 AM, Philippe Grosjean
wrote:
> Greg,
>
> I really like that TeachingDemos::SnowsPenultimateNormalityTest()...
If you like that function then you may appreciate
TeachingDemos::SnowsCorrectlySizedButOtherwiseUselessTestOfAnything,
which I sus
Second.
Rui Barradas
Em 21-02-2014 23:44, Rolf Turner escreveu:
On 22/02/14 11:53, Greg Snow wrote:
Why are you testing your data for normality? For large sample sizes
the normality tests often give a meaningful answer to a meaningless
question (for small samples they give a meaningless a
Hello,
Inline
Em 21-02-2014 23:13, Rolf Turner escreveu:
On 22/02/14 11:04, Rui Barradas wrote:
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m <- mean(HP_TrinityK25$V2)
Greg,
I really like that TeachingDemos::SnowsPenultimateNormalityTest()… even the
tortuous way to always return a p-value == 0:
# the following function works for current implementations of R
# to my knowledge, eventually it may need to be expanded
is.rational <- function(x){
rep( TRUE, leng
Second!!
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
H. Gilbert Welch
On Fri, Feb 21, 2014 at 3:44 PM, Rolf Turner wrote:
> On 22/02/14 11:53, Greg Snow wrote:
>
>
>
>
On 22/02/14 11:53, Greg Snow wrote:
Why are you testing your data for normality? For large sample sizes
the normality tests often give a meaningful answer to a meaningless
question (for small samples they give a meaningless answer to a
meaningful question).
Fortune!!!
cheers,
Rolf
___
On 22/02/14 11:04, Rui Barradas wrote:
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m <- mean(HP_TrinityK25$V2)
s <- sd(HP_TrinityK25$V2)
ks.test(HP_TrinityK25$V2, "pnorm"
Rui,
Note this quote from the last paragraph of the Details section of ?ks.test:
"If a single-sample test is used, the parameters specified in '...'
must be pre-specified and not estimated from the data."
Which is the exact opposite of your example.
Gonzalo,
Why are you testing your dat
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m <- mean(HP_TrinityK25$V2)
s <- sd(HP_TrinityK25$V2)
ks.test(HP_TrinityK25$V2, "pnorm", m, s)
Hope this helps,
Rui Barra
Dear R users,
Please help with with this maybe basic question. I am trying to see if my
data is normal but is a large file and the test does not work.
I keep getting the message : "Error in shapiro.test(x = HP_TrinityK25$V2)
: sample size must be between 3 and 5000"
thanks!
shapiro.test(x=HP_Tri
On Jun 26, 2012, at 16:43 , r...@uni-potsdam.de wrote:
> Hey,
> today I wanted to use the shapiro.test() on data containing 3 numerical
> values per group.
> It is the first time that an NA was given back for some of the groups.
> In the follwing an example of code and output is shown:
>
>
>>
Actually, your sample size is 3. Sorry for that.
Ozgur
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htt
See
?shapiro.test
...the number of non-missing values must be between 3 and 5000.
By the way, how reasonable testing normality of 3 values?
Best
ozgur
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Sent from the R help mailing list archive a
Hey,
today I wanted to use the shapiro.test() on data containing 3
numerical values per group.
It is the first time that an NA was given back for some of the groups.
In the follwing an example of code and output is shown:
shapiro.test(c(0.000637806, 0.00175561, 0.001196708))
Shapir
ealthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Stefan Scheurer
> Sent: Wednesday, May 26, 2010 1:37 PM
> To: r-help@r-project.org
> Subject: [R] shapiro.test
>
>
Hi,
David Winsemius schrieb:
This would imply that ozon is a list or dataframe.
And you tried to give the whole list to a function that only wants a
vector.
And whenever you suspect that your data types clash, try str() to find
out just what kind of thing your data is. Here: str(ozon)
On May 26, 2010, at 3:36 PM, Stefan Scheurer wrote:
Hi,
I am not so sure about an error note I got when using shapiro.test.
I imported some data into R by wrinting it into a .txt file via
tab1<-read.table("etctxt",header=T)
attach(tab1)
The following object(s) are masked _by_ .Gl
Hi,
I am not so sure about an error note I got when using shapiro.test.
I imported some data into R by wrinting it into a .txt file via
> tab1<-read.table("etctxt",header=T)
> attach(tab1)
The following object(s) are masked _by_ .GlobalEnv :
ozon
> ozon$V1 [1] 2.5 3.0 5.6 4.
On Monday 22 June 2009, Gonzalo Quiroga wrote:
> Hi, I need help to perform a Shapiro.test on a data frame, I know that
> this test works only with vector but I guess there most be a way to
> permor it on a data frame instead of vactor by vector (i.e. I've got 40
> variables to analyze and its kind
Try this:
x <- data.frame(A = runif(10), B = rnorm(10))
lapply(x, shapiro.test)
On Mon, Jun 22, 2009 at 3:15 PM, Gonzalo Quiroga
wrote:
> Hi, I need help to perform a Shapiro.test on a data frame, I know that
> this test works only with vector but I guess there most be a way to
> permor it on a
Hi, I need help to perform a Shapiro.test on a data frame, I know that
this test works only with vector but I guess there most be a way to
permor it on a data frame instead of vactor by vector (i.e. I've got 40
variables to analyze and its kinda annoying to do it one by one)
Thanks to anyone that
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