Or you could take advantage of R's automatic recycling:
> x$b <- rep(1:3, length=nrow(x))
> x
a b
1 1 1
2 2 2
3 3 3
4 4 1
5 5 2
6 6 3
7 7 1
8 8 2
9 9 3
10 10 1
Thanks for providing a simple reproducible example.
Sarah
On Wed, Jul 20, 2011 at 6:20 PM, Dimitri Liakhovitski
Never mind - found it:
x<-data.frame(a=1:10)
x$b<-rep(1:3,nrow(x)%/%3,len=nrow(x))
Dimitri
On Wed, Jul 20, 2011 at 6:15 PM, Dimitri Liakhovitski
wrote:
> Apologies, for a very simple question. I forgot how to do it -
> although I remember reading about getting a warning in such a
> situation.
>
Apologies, for a very simple question. I forgot how to do it -
although I remember reading about getting a warning in such a
situation.
I have a data frame. It happens to be 10 rows but it could be 11 or 3 or 13...
x<-data.frame(a=1:10)
I need to add variable "b" that is a sequence of 1:3 - repeat
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