>> apply(mt, 1, function(x) x[!is.nan(x)] )
> [[1]]
> [1] 1 3
>
> [[2]]
> [1] 4 5 6
You need to be a little careful with apply:
> mt2 <- matrix(c(1,4,2,5,3,6),2,3)
> apply(mt2, 1, function(x) x[!is.nan(x)] )
[,1] [,2]
[1,]14
[2,]25
[3,]36
Depending on the input you w
On Sep 27, 2011, at 4:02 PM, Ben qant wrote:
Hello,
What is the best way to turn a matrix into a list removing NaN's?
I'm new to
R...
Start:
mt = matrix(c(1,4,NaN,5,3,6),2,3)
mt
[,1] [,2] [,3]
[1,]1 NaN3
[2,]456
> apply(mt, 1, function(x) x[!is.nan(x)] )
[[1]]
Excellent! Thank you!
ben
On Tue, Sep 27, 2011 at 2:07 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> alply is from the plyr package. You'll need to call that if its not already
> loaded.
>
> M
>
>
> On Tue, Sep 27, 2011 at 4:07 PM, R. Michael Weylandt <
> michael.weyla...@gmail.
alply is from the plyr package. You'll need to call that if its not already
loaded.
M
On Tue, Sep 27, 2011 at 4:07 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> Try this:
>
> alply(mt, 1, function(x) as.numeric(na.omit(x)))
>
> The as.numeric() addition may be necessary to strip
Try this:
alply(mt, 1, function(x) as.numeric(na.omit(x)))
The as.numeric() addition may be necessary to strip the extra attributes
na.omit() wants to add.
Michael
On Tue, Sep 27, 2011 at 4:02 PM, Ben qant wrote:
> Hello,
>
> What is the best way to turn a matrix into a list removing NaN's? I
Hello,
What is the best way to turn a matrix into a list removing NaN's? I'm new to
R...
Start:
> mt = matrix(c(1,4,NaN,5,3,6),2,3)
> mt
[,1] [,2] [,3]
[1,]1 NaN3
[2,]456
Desired result:
> lst
[[1]]
[1] 1 3
[[2]]
[1] 4 5 6
Thanks!
Ben
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