mat = "%MM/%DD/%
>> %H:%M:%:S")
>>
>> I would appreciate any help in converting this data frame into xts. I am
>> not sure is the NROW issue is the reason behind the failure or is it the
>> data formate
>>
>> thanks
>>
>&
this data frame into xts. I am not
> sure is the NROW issue is the reason behind the failure or is it the data
> formate
>
> thanks
>
>
> - Original Message -
> From: "R. Michael Weylandt "
>
> To: Muhammad Abuizzah
> Cc: "r-help@R-projec
And to further the example, length() of matrix is not equal to the number
of rows either.
> mm <- matrix(1:6, ncol=2)
> length(mm)
[1] 6
> dim(mm)
[1] 3 2
Also, NROW() and nrow() are different; I'd be cautious about using NROW
without making sure I understood the difference.
> NROW
function (x)
Data frame is list internally so length(df) = ncol(df)
M
On Oct 27, 2011, at 2:44 PM, Muhammad Abuizzah wrote:
> Hi,
>
> I am converting a data.frame to xts. the data.frame is 4 columns and 1000
> rows. I get a message that "NROW (x) must match length(order.by)
> class is data.frame, mode i
Hi,
I am converting a data.frame to xts. the data.frame is 4 columns and 1000
rows. I get a message that "NROW (x) must match length(order.by)
class is data.frame, mode is list
when I run
dim(x) # I get
1000 4 #which is consistent with 1000 rows and 4 columns
NROW (x) # I get
1000
Thanks.
I made it!
Best wishes,
S.
Am 22.02.2011 17:41, schrieb Erik Iverson:
Sandra Stankowski wrote:
is.na function does'nt seem to work, but maybe I'm just dealing with
it in a wrong way.
here's an example
> m <- c(2, 3, 5, 6, 3, 7, -99, -99, 6)
> n <- c(1,1,1,1,1,2,2,2,2)
so my mat
is.na function does'nt seem to work, but maybe I'm just dealing with it
in a wrong way.
here's an example
> m <- c(2, 3, 5, 6, 3, 7, -99, -99, 6)
> n <- c(1,1,1,1,1,2,2,2,2)
so my matrix contains certain missing values
> m[m==-99] <- NA
> o <- data.frame(m, n)
> o
m n
1 2 1
2 3 1
3 5 1
Sandra Stankowski wrote:
is.na function does'nt seem to work, but maybe I'm just dealing with it
in a wrong way.
here's an example
> m <- c(2, 3, 5, 6, 3, 7, -99, -99, 6)
> n <- c(1,1,1,1,1,2,2,2,2)
so my matrix contains certain missing values
Thank you for the example.
You're construct
Hi Sandra,
What about ?is.na function ?
Hope this help
Regards,
ML
Le 22/02/11 16:11, Sandra Stankowski a écrit :
> NROW(data[jan,16] != NaN)
--
Mohamed Lajnef,IE INSERM U955 eq 15#
Pôle de Psychiatrie#
Hôpital CHENEVIER
?is.nan
Peter Ehlers
On 2011-02-22 07:11, Sandra Stankowski wrote:
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
certain column.
this was my guess:
(given is a data frame with 2069 rows and 17 cols)
NROW(data[jan,16] != NaN)
("jan" is defined this way: jan<-
Sandra,
Please provide a small, reproducible example of this issue.
You probably want to use ?is.nan and not the inequality
operator.
Similar example, contrast:
x <- NA
is.na(x)
x == NA
Sandra Stankowski wrote:
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
cer
Hey there,
I tried to count the number of rows, where my data isn't NaN in a
certain column.
this was my guess:
(given is a data frame with 2069 rows and 17 cols)
NROW(data[jan,16] != NaN)
("jan" is defined this way: jan <- which(data[,2]==1, arr.ind= TRUE))
but I only get the number of c
12 matches
Mail list logo
