It looks like you are attempting to divide a number by a formula.
> 5 / (a ~ b)
Error in 5/(a ~ b) : non-numeric argument to binary operator
On Fri, Jan 20, 2017 at 12:18 PM, Zeki ÇATAV wrote:
> Hi,
> I'm working on following dataset.
>
>
> > dput(uu5)
> structure(list(grup = structure(c(1L, 1
Hi,
I'm working on following dataset.
> dput(uu5)
structure(list(grup = structure(c(1L, 1L, 2L, 2L), .Label = c("1",
"2"), class = "factor"), bw_grp = structure(c(1L, 2L, 1L, 2L), .Label =
c("0-999",
"1000+"), class = "factor"), deaths = c(6L, 13L, 1L, 2L), pop = c(26L,
67L, 41L, 93L), bw = c(500
On 12-12-16 6:56 PM, Shrupa Sumaria wrote:
Hello,
I wish to carry out the following:
factor_classes <- as.factor(sample(c("BM", "SM", "F"), 10, replace = TRUE))
C <- 5
k <- matrix(0, length(factor_classes), 1)
for (i in length(factor_classes)) {
k[i] <- C*factor_classes[i]
}
I get
Hello,
Try
C*as.integer(factor_classes)
And note that you don't need the loop.
Hope this helps,
Rui Barradas
Em 16-12-2012 23:56, Shrupa Sumaria escreveu:
> Hello,
>
>
> I wish to carry out the following:
>
>
> factor_classes <- as.factor(sample(c("BM", "SM", "F"), 10, replace = TRUE))
>
>
> C
Hello,
I wish to carry out the following:
factor_classes <- as.factor(sample(c("BM", "SM", "F"), 10, replace = TRUE))
C <- 5
k <- matrix(0, length(factor_classes), 1)
for (i in length(factor_classes)) {
k[i] <- C*factor_classes[i]
}
I get the following error message:
non-numeric ar
Write yourself an alternative function to table, for example like this:
tableOfGivenLevels = function(x, levels)
{
n = length(levels)
counts = rep(0, n);
names(counts) = levels
tab = table(x);
counts[match(names(tab), levels)] = tab;
counts;
}
x = sample(c(1:4), 20, replace = TRUE)
ta
"Most likely reason is that the number of unique values in the rows of
habs is not the same."
Yes, I think that is the problem, thank you.
How would I write the code to include 0s in the matrix,
ie, I want to have a record of when 1, 2, or 3 does not get sampled,
to come up with a frequency of e
Not sure ho to run the code since nn is not defined.
Most likely reason is that the number of unique values in the rows of
habs is not the same. That makes the tables produced in the apply
command of different length and apply returns a list instead of a
matrix, which makes the t() or the division
Hello,
For reasons unclear to me I am getting above error message when I change the
value of b in the following code:
rm(list=ls())
library("Hmisc")
set.seed(4) #seems to have an effect on t(apply
b=10
pop.props = c(0.6,0.2,0.2)
x=matrix(pop.props,nrow=nn,ncol=length(pop.
Charles Novaes de Santana wrote:
> Thank you everybody for the help! The solution of my problem is here:
>
> http://climateaudit.org/2009/10/10/unthreaded-23/
>
> "The mv variable is the designated NA for the variable and it appears that
> somebody screwed that up in the file. This workaround worke
Thank you everybody for the help! The solution of my problem is here:
http://climateaudit.org/2009/10/10/unthreaded-23/
"The mv variable is the designated NA for the variable and it appears that
somebody screwed that up in the file. This workaround worked for me:
Print out the function get.var.n
Hi,
Well, I did it, but all my script was on the first message. I don't have any
other variables. I am just reading a NCDF file and trying to read the
variable "tasmax", that has values of temperatures.
The only "new" information I have is the header of the NCDF file
(Spain02D_tasmax.nc), that I
Thank you for your answer, Jim! I will try it and post what I find.
cheers,
Charles
On Wed, Oct 27, 2010 at 3:46 PM, jim holtman wrote:
> put:
>
> options(error=utils::recover)
>
> in your script so that when an error occurs you are dropped into the
> 'browser' so that you can examine the vari
put:
options(error=utils::recover)
in your script so that when an error occurs you are dropped into the
'browser' so that you can examine the variables at that point in time.
There are several references on how to use the debugging tools in R
that will help you resolve your problem. We can not
Hi everyone,
I am a newbie in R and in this discussion list. I am trying to use R package
"ncdf" to read values of temperature from a NCDF file. I did it before to
another file using the function "get.var.ncdf", but now there is an error
that I can not solve, and I would really appreciate if you c
February 2009 1:36 PM
To: r-help@r-project.org
Subject: [R] non-numeric argument to binary operator
Hi,
I compute the value of xi*xj by "for" loops, this how I try:
> x1 <- c(1:3)
> x2 <- c(2:4)
### to compute x1*x2
> (paste("x", 1, sep = ""))*(pas
hi: it's not clear to me what you're trying to do but maybe outer is
what you want ?
outer(x,y)
it takes every value in x and pairs it with every value in y and the
default operation is multiply. see details by doing ?outer.
On Wed, Feb 4, 2009 at 10:36 PM, cruz wrote:
Hi,
I compute t
Hi,
I compute the value of xi*xj by "for" loops, this how I try:
> x1 <- c(1:3)
> x2 <- c(2:4)
### to compute x1*x2
> (paste("x", 1, sep = ""))*(paste("x", 2, sep = ""))
Error in (paste("x", 1, sep = "")) * (paste("x", 2, sep = "")) :
non-numeric argument to binary operator
>
All comments ar
I'm not sure what you are trying to do: modulo arithmetic isn't exactly
splitting a matrix into 2. Or even remotely.
Regardless of the goal, when numbers are shown in quotes, it's a sure
sign that R thinks they are strings, and thus non-number, just as the error
message (not a warning) states.
To
hi i have a huge matrix and want to split it into 2. with the command %%2.
but i get this warning message: *"Error in mmat%%2 : non-numeric argument to
binary operator*"
here's the bit from my matrix:
V1 V2
[1,] "Affymetrix:CompositeSequence:ATH1-
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