Thanks for your comments. Actually only the last group has a single element.
The first group is always "full" of members and as that it works fine. Some
constant spacing between the groups would be good as well and thus I will check
quantiles.
Thanks for the great support and time invested on th
Whatever approach is "best" to define subsets depends completely on the
semantics of the data. Your approach (a fixed number of equally spaced breaks)
is the right one if the absolute ranges of the data is important. It should be
obvious that either the top or the bottom group could contain only
The breaks are just the min() and max() in your groups. Something like
sprintf("[%5.2f,%5.2f]", min(dBin[groups==2]), max(dBin[groups==2]))
... should achieve what you need.
B.
On Nov 4, 2015, at 8:45 AM, Alaios wrote:
> you are right.
> by labels I mean the "categories", "breaks" that m
you are right.by labels I mean the "categories", "breaks" that my data fall
in.To be part of group 2 for example you have to be in the range of [110,223) I
need to keep those for my plots.
Did I describe it more precisely now?Alex
On Wednesday, November 4, 2015 2:09 PM, Boris Steipe
wr
I don't understand:
- where does the "label" come from? (It's not an element of your data that I
see.)
- what do you want to do with this "label" i.e. how does it need to be
associated with the data?
B.
On Nov 4, 2015, at 7:57 AM, Alaios wrote:
> Thanks it works great and gives me group
Thanks it works great and gives me group numbers as integers and thus I can
with which group the elements as needed (which (groups== 2))
Question though is how to keep also the labels for each group. For example that
my first group is the [13,206)
RegardsAlex
On Wednesday, November 4, 20
I would transform the original numbers into integers which you can use as group
labels. The row numbers of the group labels are the indexes of your values.
Example: assume your input vector is dBin
nGroups <- 5 # number of groups
groups <- (dBin - min(dBin)) / (max(dBin) - min(dBin)) # rescale
Thanks for the answer. Split does not give me the indexes though but only in
which group they fall in. I also need the index of the group. Is the first, the
second .. group?Alex
On Tuesday, November 3, 2015 5:05 PM, Ista Zahn wrote:
Probably
split(binDistance, test).
Best,
Ista
Probably
split(binDistance, test).
Best,
Ista
On Tue, Nov 3, 2015 at 10:47 AM, Alaios via R-help wrote:
> Dear all,I am not exactly sure on what is the proper name of what I am trying
> to do.
> I have a vector that looks like
> binDistance
>[,1]
> [1,] 238.95162
> [2,] 143.0859
Dear all,I am not exactly sure on what is the proper name of what I am trying
to do.
I have a vector that looks like
binDistance
[,1]
[1,] 238.95162
[2,] 143.08590
[3,] 88.50923
[4,] 177.67884
[5,] 277.54116
[6,] 342.94689
[7,] 241.60905
[8,] 177.81969
[9,] 211.25559
[10,] 27
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