Thank you very much- I found ?as.formula of great help!
Dimitri
On Tue, Mar 9, 2010 at 6:36 PM, David Winsemius wrote:
> I already answered a very similar question earlier today. It was in the
> context of a question about a different regression function, but the formula
> methods are generic.
I already answered a very similar question earlier today. It was in
the context of a question about a different regression function, but
the formula methods are generic. Look for "Question on passing in
parameter to Cox hazard".
(That does not mean I approve of such fishing expeditions.)
-
Dimitri -
Without commenting on the wiseness of such an approach,
here's one way to do what you want:
regs = lapply(predictors,function(var)lm(data$y~data[,var]))
names(regs) = predictors
Now
regs[['x1']] holds the lm output from the regression of y on x1,
regs[['x2']] holds the lm output fr
Dear R-ers,
I have a data frame data with predictors x1 through x5 and the
response variable y.
I am running a simple regression:
reg<-lm(y~x1, data=data)
I would like to loop through all predictors. Something like:
predictors<-c("x1","x2",... "x10)
for(i in predictors){
reg<-lm(y~i)
etc.
}
B
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