Hi,
that is perfect.
Thanks Sigbert
Am 06.03.23 um 13:08 schrieb Uwe Ligges:
What about
plot(c(0,1), c(0,1), type="n")
legend("top", legend=c("", "a", ""), col=c("blue", "red", "green"),
title="test", y.intersp=c(1,-0.4), lwd=1)
(in recent versions of R)
Best,
Uwe
--
https://hu.ber
What about
plot(c(0,1), c(0,1), type="n")
legend("top", legend=c("", "a", ""), col=c("blue", "red", "green"),
title="test", y.intersp=c(1,-0.4), lwd=1)
(in recent versions of R)
Best,
Uwe
On 06.03.2023 11:34, Sigbert Klinke wrote:
Hi,
I think you are right, legend cannot do it.
Hi,
I think you are right, legend cannot do it. I have now created my own
legend function where I changed only one line and now it works the way I
want it to. But I'm not sure if that might not have other side effects.
I have the impression that the legend and the title start at the same
y
Hi,
thanks, but this does not solve the problem. If I make y.intersp large
enough then it works properly. Maybe I was not clear enough: I want to
have the small distance between the lines and no overlap between the
title and the lines.
Sigbert
Am 04.03.23 um 17:59 schrieb Bert Gunter:
Set
Set the legend position explicitly with x and y values and add xpd = TRUE
to the legend call to clip the plot to the figure region and not the plot
region (the default). Something like this (you may have to fool around with
y.intersp, etc. to allow enough space between the legend lines):
plot(c(0,
Hi,
my MWE is not working as expected:
plot(c(0,1), c(0,1), type="n")
legend("top", legend=c("", "", "a"), col=c("blue", "red", "green"),
title="test", y.intersp=0.2, lwd=1)
The lines are not below the title. I want (nearby) lines as in the plot,
but below the title. Is there a way to achie
This is the solution that best fits my needs.
Thanks everyone for their responses,
Naresh
Sent from my iPhone
On May 6, 2022, at 2:12 PM, David Carlson
mailto:dcarl...@tamu.edu>> wrote:
You can't get exactly what you want with base graphics, but you can get close
by defining line types and co
You can't get exactly what you want with base graphics, but you can get
close by defining line types and colors outside the plot command:
x <- seq(-3, 3, by = 0.01)
lns <- 1:2
clr <- 1:2
matplot(x, cbind(x, x^2), type="l", lty=lns, col=clr)
legend("bottomright", legend = c("x", expression(x^2)), l
Like this? theme(legend.position= 'top'
On Thursday, June 17, 2021, 10:52:04 AM PDT, peri He
wrote:
Dear Friends,
I would like to see my legend outside of a ggplot (at the top).
This code is showing the legend inside of a plot:
theme(legend.position=c(0.15,0.97))
But when I changed
Dear Friends,
I would like to see my legend outside of a ggplot (at the top).
This code is showing the legend inside of a plot:
theme(legend.position=c(0.15,0.97))
But when I changed it to : theme(legend.position=c(-0.15,1.5)) , the legend
disappears.
I would appreciate it if you share your id
John,
The order of legends in ggplot2 depends on the order of factor levels in the
data frame. The linetype can be matched to the factor levels using a named
vector (ggplot2 basically does a lookup).
The biggest problem you have here is that you’re not passing data in the right
form or format
eza.cz/01-dovetek/ | This email and any documents attached to
it may be confidential and are subject to the legally binding disclaimer:
https://www.precheza.cz/en/01-disclaimer/
From: John [mailto:miao...@gmail.com]
Sent: Wednesday, May 23, 2018 3:25 AM
To: PIKAL Petr
Cc: r-help
Subject: Re: [R] lege
ot;solid", "dashed", "dotted", "blank"),
> labels=c("name_b","name_a","name_c", "other"))
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help [mailto:r-help-boun...@r-project.o
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of John
> Sent: Tuesday, May 22, 2018 5:17 AM
> To: r-help
> Subject: [R] legend order in ggplot2
>
> Hi,
>
>I'd like to graph three lines on ggplot2 and I intend the lines to be
> "solid
Hi,
I'd like to graph three lines on ggplot2 and I intend the lines to be
"solid", "dashed", and "dotted". The legend names are "name_b", "name_a",
"name_c". I'd like to legend to present in the order: the "name_b" at the
top, and "name_c" at the bottom.
As a consequence, the legend is indeed i
Not possible to debug your specific problem without sample data [1][2][3], but
learning how to setup and manage factors is a key skill for getting this right.
You will also make it less likely that the email you send gets damaged in
transit if you send plain text email instead of HTML.
[1]
htt
I have following codes for ggplots. The legends are given in the plot do
not match with the values specified in the codes given below. Your helps
highly appreciated.
Greg
library(ggplot2)
p <- ggplot(a,aes(x=NO_BMI_FI_beta ,y=FI_beta ,color= Super.Pathway))+
theme_bw() +theme(panel.border=ele
Thanks Thierry,
I knew there had to be a simpler way, but just could not find it
(facet_wrap() does the trick!).
Just 2 other questions:
- How do I remove the plot titles? I don't find any argument in
facet_wrap() on that...
- How can I add the legend for the outliers?
Thanks again,
Ivan
-
Dear Ivan,
You're making things too complicated.
ggplot(mydata, aes(x = Spot, y = Value)) +
geom_boxplot(aes(colour = Equipment), outlier.colour = "red") +
geom_jitter() +
facet_wrap(~Equipment, scales = "free_y") +
scale_colour_manual(values = c(Leeb = "blue", Shore = "red"))
Best regar
Dear useRs,
I have been using base graphics since a long time and I'm currently
trying to switch to ggplot2. I'm struggling with the legend (which
probably means that my graphic commands are not optimal).
I have copied the output from dput(mydata) at the end of the email.
Here is what I have
All,
Thanks anyway folks, but I'm going to call myself a bonehead and move on
now that I've found it. The key.arrow argument in vectorplot will do what
I need to make a scale legend. Thanks all!
Adrienne
On Tue, Mar 1, 2016 at 9:14 AM, Adrienne Wootten wrote:
> Jim,
>
> Thanks! Interesting
Jim,
Thanks! Interestingly when working with lengthKey it gives me an error
that plot.new hasn't been called after the plot has been created with
vectorplot. Really bizarre to me.
A
On Tue, Mar 1, 2016 at 5:22 AM, Jim Lemon wrote:
> Hi Adrienne,
> I'm not sure if this will help, but lengthKe
Hi Adrienne,
I'm not sure if this will help, but lengthKey in the plotrix package
will display a scale showing the relationship of vector length to
whatever numeric value is being displayed. However, you do have to
sort of the scaling manually.
Jim
On Tue, Mar 1, 2016 at 7:30 AM, Adrienne Wootte
All,
Your help with this is greatly appreciated!
I'm working with the vectorplot function in rasterVis to produce wind
vector maps (pretty much like the code in here -
https://rpubs.com/alobo/vectorplot), but I was wondering about a legend.
The vectors that vectorplot produces are wonderful. Wh
Hi David,
1) set size to a fixed value instead of mapping it to a constant,
i.e., geom_line(size = 2) instead of geom_line(aes(size = 2))
2) perhaps
ggplot(rtest, aes(x=Time, y=Calculated,color=Model, group=Model)) +
geom_line(size = 2) +
geom_point(aes(y=Observed, shape=""),
si
I’m trying to generate a plot with a series of data points and best fit lines
from two stat models. I’m generating the best-fits with another program. I have
the data in a csv file as:
Time,Observed,Calculated,Model
0.000,0.0,13.0810,1C
0.2500,15.,12.5298,1C
0.5000,12.,12.0018,1C
1.0
'q' should be an expression object, not a list of expression objects.
Try defining 'q' as
q <- as.expression(lapply(lambdas, function(l)bquote(lambda==.(l
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Sat, Sep 13, 2014 at 5:55 PM, Julio Sergio Santana
wrote:
> I need to add a legend w
On Sep 13, 2014, at 5:55 PM, Julio Sergio Santana wrote:
I need to add a legend with three entries that should
contain a greek letter (lambda). I learnt that it is
possible using the function expression. So I need to
build the expressions from the lambdas vector, and I
simply cannot do it. This
I need to add a legend with three entries that should
contain a greek letter (lambda). I learnt that it is
possible using the function expression. So I need to
build the expressions from the lambdas vector, and I
simply cannot do it. This is the uggly result I got:
x <- 0:20
cc <- c("yellow
The problem is that you are not actually 'mapping' any variables to
the fill and colour aestethics so ggplot wont produce legends for
those. I'm not sure ggplots are appropiate for what you're trying to
do here but you can sure hack around it a bit, for instance try:
ggplot(tabu, aes(x=weeks, y=T)
Hi All
Following is my dataset.
dput(tabu)
structure(list(weeks = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28,
29, 30), values = c(9.45, 7.99, 9.29, 11.66, 12.16, 10.18, 8.04,
11.46, 9.2, 10.34, 9.03, 11.47, 10.51, 9.4, 10.08, 9.37, 10
IOanna,
If you are trying to distinguish between the type="b" and the type="o" in
the legend, there does not appear to be a way to do this with the legend()
function in base. I found a similar question posted on stackoverflow, and
they suggested a work around for something similar (but not quite
> I want to plot the legend for the following two lines:
> ...
> Any ideas how?
Try ?legend
S Ellison
***
This email and any attachments are confidential. Any use...{{dropped:8}}
__
R
Hello all,
I want to plot the legend for the following two lines:
I have two lines:
X1<-c(0,1,2,3,4)
Y1<-c(0,1,2,3,4)
Y2<-c(5,6,7,8,9)
Y3<-(32,33,34,35,36)
plot(X1,Y3,pch=20)
lines(X1,Y1,lty=1,type='o')
lines(X1,Y2,lty=1,type='b')
lines(X1,Y3,lty=2)
Any ideas how?
Thanks everyone for the help. Dennis, the bquote version work great.
Thanks,
Doug
On 2/7/2014 7:08 PM, Dennis Murphy wrote:
Here's a bquote version:
x=c(1,2,3,4); y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)
# first stats based on data, used to populate legend
wdt_n = 50; wdt_mbias = 0.58
wdt_mae = 2
Here's a bquote version:
x=c(1,2,3,4); y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)
# first stats based on data, used to populate legend
wdt_n = 50; wdt_mbias = 0.58
wdt_mae = 2.1; wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2
On Feb 7, 2014, at 7:54 AM, Douglas M. Hultstrand wrote:
> Hello,
>
> I am trying to generate a plot legend that contains calculated summary
> statistics, one statistic is R^2. I have tried several variations using
> the commands "expression" and "bqoute" as stated on the R help pages. I
>
On 02/08/2014 02:54 AM, Douglas M. Hultstrand wrote:
Hello,
I am trying to generate a plot legend that contains calculated summary
statistics, one statistic is R^2. I have tried several variations using
the commands "expression" and "bqoute" as stated on the R help pages. I
have not been able
Hello,
I am trying to generate a plot legend that contains calculated summary
statistics, one statistic is R^2. I have tried several variations using
the commands "expression" and "bqoute" as stated on the R help pages. I
have not been able to get the R^2 super script correct along with the
Thank you David, it is exactly what I needed.
Regards,Phil
> From: dcarl...@tamu.edu
> To: pmassico...@hotmail.com; r-help@r-project.org
> Subject: RE: [R] legend position
> Date: Mon, 2 Dec 2013 14:29:06 -0600
>
> It is not straightforward unless you want the legend in the
>
mber 2, 2013 1:22 PM
To: r-help@r-project.org
Subject: [R] legend position
Hi all.
I'm ploting a raster and I can't find the proper way to move the
legend. For example,
r = raster(system.file("external/test.grd",
package="raster"))plot(r)
How can I put the legend
Thank you, I'll try to work with lattice.
Regards,Phil
> Date: Mon, 2 Dec 2013 12:06:50 -0800
> From: c...@witthoft.com
> To: r-help@r-project.org
> Subject: Re: [R] legend position
>
> It occurs to me that perhaps you're referring to the 'color bar' on the
It occurs to me that perhaps you're referring to the 'color bar' on the right
of the plot. AFAIK you cannot get at that from the raster::plot method.
However lattice::levelplot does allow you to manipulate or remove that
colorbar.
--
View this message in context:
http://r.789695.n4.nabble.
Thank you for reply.
If I'm not wrong, legend(...) will works for discrete elements. I'm not sure
hot to use it for a colorbar legend sur as the one in the example bellow.
Phil
> Date: Mon, 2 Dec 2013 11:49:19 -0800
> From: c...@witthoft.com
> To: r-help@r-project.org
> S
See ?legend . you can add a legend directly to an existing plot. An
example:
legend('topright',c('hot','cold'),lty=1,col=c('red','green'),bg='white')
Now if you're trying to place the legend outside the plot area (i.e. in some
other part of the window),
you'll need to invoke par(xpd=TRUE) . Se
Hi all.
I'm ploting a raster and I can't find the proper way to move the legend. For
example,
r = raster(system.file("external/test.grd", package="raster"))plot(r)
How can I put the legend at the desired position?
Thank in advance,Phil
[[alternative HT
Hi,
May be:
barplot(m$V3,names.arg=paste(m$V2,m$V1,sep="\n"),col=rainbow(10))
#or
barplot(m$V3,names.arg=m$V2,col=rainbow(20),legend=m$V1, args.legend = list(x =
"topright",box.lwd=0,border=FALSE))
A.K.
On Tuesday, November 26, 2013 1:18 PM, Adel ESSAFI wrote:
Hello;
I have the following tab
Hello;
I have the following table
> m
V2 V1 V3
1 C/L 0 732179
3 C/S 0 803926
19 D/F 0 724924
17 D/I 0 755841
13 D/L 0 731904
15 D/S 0 798289
11 I/F 0 871670
9 I/I 0 897718
5 I/L 0 2628113
7 I/S 0 2628113
2 C/L 1 1107269
4 C/S 1 1395714
20 D/F 1 1181282
18 D/I 1
Hello;
I have the following table
> m
V2 V1 V3
1 C/L 0 732179
3 C/S 0 803926
19 D/F 0 724924
17 D/I 0 755841
13 D/L 0 731904
15 D/S 0 798289
11 I/F 0 871670
9 I/I 0 897718
5 I/L 0 2628113
7 I/S 0 2628113
2 C/L 1 1107269
4 C/S 1 1395714
20 D/F 1 1181282
18 D/I 1
On 2013/9/23 12:52, David Winsemius wrote:
On Sep 22, 2013, at 10:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = 1, pch = 21)
?par
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = "69",
On 2013/9/23 17:11, Jim Lemon wrote:
On 09/23/2013 01:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = 1, pch = 21)
The result is something wired for the line crosses the point in the
legend while the
On 09/23/2013 01:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = 1, pch = 21)
The result is something wired for the line crosses the point in the
legend while the line does not cross the point in the
On Sep 22, 2013, at 10:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = 1, pch = 21)
?par
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = "69", pch = 21)
The result is something wired
t;)
legend1<- legend("top","test",lty=1,pch=21)
A.K.
- Original Message -----
From: Jinsong Zhao
To: R help
Cc:
Sent: Sunday, September 22, 2013 11:54 PM
Subject: [R] legend for the plot with type = "b"
Hi there,
I plot a simple plot with the followin
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = "b")
legend("top", "test", lty = 1, pch = 21)
The result is something wired for the line crosses the point in the
legend while the line does not cross the point in the main plot.
Is there possibility to draw th
ano
> Sent: Tuesday, September 03, 2013 10:59 AM
> To: r-help@r-project.org
> Subject: [R] Legend Help
>
> Hi to everyone and thanks for this service.
>
> I have a doubt with legend, I have seen ?legend, but I don't get the
> way to write in my code the
>
> legen
Hi to everyone and thanks for this service.
I have a doubt with legend, I have seen ?legend, but I don't get the way to
write in my code the
legend that I want,
This is my code:
for( i in 1:4)}
pdf(paste("plotImputed", i,".pdf",sep=""))
plot(a[,6], type="l", main=paste( "I
Dear R-helpers,
I'm trying to combine two box plots having two dependent variables:
var1- Orange.area and
var2- Iridescent.area;
two independent categorical factors (each has two levels - 'High' & 'Low'):
fact1- Quantity
fact2- Quality
the data frame (df) is:
Quantity Quality Orange.are
Hi Robert,
Your legend is for fill, not color, so you need
guides(fill = guide_legend(nrow = 3))
instead of
guides(colour = guide_legend(nrow = 3))
Best,
Ista
On Wed, Aug 28, 2013 at 5:09 PM, Robert Lynch wrote:
> I am having trouble getting my legend to format the way I want it to. I
> sus
I am having trouble getting my legend to format the way I want it to. I
suspect it is something simple.
>
> the code I have is
> library(ggplot2)
> ggplot(Chem.comp, aes(Course, GRADE.)) + geom_boxplot(notch =
> TRUE,aes(fill = COHORT))+
> labs(title = "Comparison between ISE cohorts and Peers
Hello,
how can I visualize the legend in the following ggmap plot ? In the legend
I just want to show the size ranges of the data:
ggmap(map) + geom_point(aes(x=Longitude,y=Latitude), size = dataRd[,2]/12,
col=2, data=dataRd, alpha=0.7, lwd=2)
Thanks
Edoardo
[[alternative HTML version
I thought my reply went to the group last night. i had already resolved it.
in short, before his first reply it was resolved... which is why i didn't offer
additional information. i was honestly taken aback by his response to me. i
don't respond well to vitriol wrapped in attempts to help. i
Nicole,
Since you seem more interested in accusing David of being rude than
recognizing your own rudeness and taking steps to overcome that and
increase your chance of getting useful responses I will quote a few lines
from the posting guide for you (the entire posting guide is available from
the l
by the time your rude reply came ( you are often rude to people so i shouldn't
have been surprised but somehow was) , i had already found my answer, by doing
it MYSELF on her computer and found had not followed some simple instructions.
be well.
~Nicole Ford
Ph.D. student
Graduate Assistant/ In
I did look at ??pie ??graphics, as per my reply. which netted nothing of
value.
thanks.
~Nicole Ford
Ph.D. student
Graduate Assistant/ Instructor
University of South Florida
Government and International Affairs
office: SOC 012M
e: nmhi...@mail.usf.edu
http://gia.usf.edu/student/nford/
On
My point is that you _still_ have not adhered to the Posting Guide request for
sessionInfo() ... I say again. Please read the Posting Guide ... AND PLEASE
STOP posting formatted email.
--
David.
On Feb 25, 2013, at 10:20 AM, Nicole Ford wrote:
> I did look at ??pie ??graphics, as per my repl
On Feb 25, 2013, at 7:37 AM, Nicole Ford wrote:
> hello, all.
>
> one of my students is having an issue with the pie & legend function.
>
> this is her code. (below)
>
> it works just fine for me.
>
> her error is "plot.new has not been called yet". i know this means her pie
> chart is com
hello, all.
one of my students is having an issue with the pie & legend function.
this is her code. (below)
it works just fine for me.
her error is "plot.new has not been called yet". i know this means her pie
chart is coming up blank so the legend will not work.
according to ?graphics thi
Using pch you can use all the symbols in the current font, try:
plot(0:15, 0:15, type='n')
points( (0:255)%%16, (0:255)%/%16, pch=0:255 )
then do it again with
points( (0:255)%%16, (0:255)%/%16, pch=0:255, font=5 )
(font 5 is usually a symbol font, fonts 2, 3, and 4 are bold and italic
versions
Hi there,
I was wondering if there is any R package that one can use for plotting
that has more legend symbols - the standard pch has 18 symbols but I need
~30 for my application- and just using different colors is not an option.
Thank you in advance,
Diviya
[[alternative HTML version de
he title as two lines, but the top line is outside the legend box.
>
> How can I trick the R legend function to make the legend box taller so that
> it contains the top line?
>
You should include an example with dummy data if you wnat tested solutions. You
can try:
lege
-
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77843-4352
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Gabriel Toro
&g
Hi,
I am trying to use a legend title that is a bit too long for one line. To try
to break the title in two lines, I am using
legend (title="Top of Title\nbottom of title", etc. )
R prints the title as two lines, but the top line is outside the legend box.
How can I trick th
Possible? Yes. (see fortune("Yoda"))
Automated using the legend function? No
Automated using another function? possbly somewhere in the 4,000+
packages on CRAN, but I don't know which.
It is doable with the basic tools. You could either find a part of
your graph with open area to put the legend i
I generated maps with the function symbols (graphics). These are basic
maps generated with :
symbols(x,y,circles=myvariable)
where x et y are spatial coordinates corresponding to replicates of
"myvariable".
I would associate legend to this kind of maps, is it possible?
Regards,
Marion.
--
This worked perfectly, thank you!
(Sorry for the delay, was traveling and didn't get a chance to test it until
now.)
Kirsten
On Oct 4, 2012, at 1:30 PM, David Winsemius wrote:
>
> On Oct 3, 2012, at 12:58 PM, Kirsten wrote:
>
>> Hey everyone,
>>
>> I'm working on a contour plot depicting a
On Oct 3, 2012, at 12:58 PM, Kirsten wrote:
> Hey everyone,
>
> I'm working on a contour plot depicting asymptomatic prevalence at varying
> durations of infectiousness and force of infection. I've been able to work
> everything out except for this one - my legend title keeps getting cut off.
Data attached - didn't realize I could do that last night. Here's the data
inport piece of my code, change the pathname to your computer.
asym<-read.csv('/Users/kirstensimmons/Desktop/Asym04.csv')
asym
#put the data into a data matrix
asym_matrix<-data.matrix(asym)
On Thu, Oct 4, 2012 at 6:35
On Oct 3, 2012, at 12:58 PM, Kirsten wrote:
> Hey everyone,
>
> I'm working on a contour plot depicting asymptomatic prevalence at varying
> durations of infectiousness and force of infection. I've been able to work
> everything out except for this one - my legend title keeps getting cut off.
Hey everyone,
I'm working on a contour plot depicting asymptomatic prevalence at varying
durations of infectiousness and force of infection. I've been able to work
everything out except for this one - my legend title keeps getting cut off.
Here's what I have:
filled.contour(x=seq(2,30,length.ou
A quick hack to give you space between the line and point (if you only
used solid lines) is to specify lty='ff' to the legend function.
If you want more control then look at setting trace=TRUE and
plot=FALSE and looking at the printed outcome and the return value
from legend. This does not plot t
On 2012-08-16 0:22, Greg Snow wrote:
You can use the grconvertY function to find the position in the
current user coordinates that corresponds to the top of the device
area (instead of using locator).
Thank you very much. grconvertX() and grconvertY() work very well.
Look at the "merge" argu
You can use the grconvertY function to find the position in the
current user coordinates that corresponds to the top of the device
area (instead of using locator).
Look at the "merge" argument to the legend function.
On Wed, Aug 15, 2012 at 10:04 AM, Jinsong Zhao wrote:
> Hi there,
>
> I draw a
Hi there,
I draw a multiple figure in one plot, like the following:
par(mfcol=c(1,5),mar=c(4,4,0,0)+0.2, oma=c(0,0,3,0))
plot(1:10, type = "b")
plot(1:10, type = "b")
plot(1:10, type = "b")
plot(1:10, type = "b")
plot(1:10, type = "b")
Now, I hope to plot the legend like the following:
legend(
On 09/06/12 13:20, peter dalgaard wrote:
>> I guess I overlook the corresponding part in the manual but how can I
>> modify the distance between the text and the line in a legend?
>>
>> Thank you for any hints!
>
> You mean like this?
>
> plot(0)
> legend(1, .5, legend=c("foo","bar"), lty=1:2, pc
On Jun 9, 2012, at 13:04 , Sebastian Schubert wrote:
> Hi,
>
> I guess I overlook the corresponding part in the manual but how can I
> modify the distance between the text and the line in a legend?
>
> Thank you for any hints!
You mean like this?
plot(0)
legend(1, .5, legend=c("foo","bar"), l
Hi,
I guess I overlook the corresponding part in the manual but how can I
modify the distance between the text and the line in a legend?
Thank you for any hints!
Sebastian
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R-help@r-project.org
Hi Richard,
Thanks for the solution.
A.K.
From: Richard M. Heiberger
To: arun
Sent: Monday, June 4, 2012 1:47 AM
Subject: Re: [R] Legend colors not matching with Intxplot line colors
Thank you for catching that. I will repair it in the next version of
Dear R help,
I am using intxplot() from the library(HH). I have a dataset with 12 treatment
groups. At first, I tried intxplot with no color settings. Then, the legend
color was matching with the plot line colors, but some of the colors were
repeated. So, I set the colors using par.settings
Thank you every body for your suggestion. It does help.
On Fri, Apr 6, 2012 at 2:37 AM, windmagics_lsl wrote:
> I think there may 3 legends should be added in your plot
> the argument col, pch and pt.cex should be in the same length with legend,
> but the objects col, pch
> and cex you defined
I think there may 3 legends should be added in your plot
the argument col, pch and pt.cex should be in the same length with legend,
but the objects col, pch
and cex you defined former have 16*3 length. I guess the follow codes may
work
col <- rep(c("blue", "red", "darkgreen"), c(16, 16, 16))
##
Thanks,
anyway, using build-in R features is preferable for colours
with(data, plot(axis1, axis2, col= c("red", "blue",
"green")[as.numeric(data$Region)]))
legend("topright", legend=levels(data$Region), fill= c("red", "blue",
"green"))
although sometimes can be preferable to get advantage of
He provided data, yet in an inconvenient way at the bottom of his post.
Kumar, please use dput() to provide data to the list, because its much
easier to import:
dput(data)## name data is made up by me
structure(list(Region = structure(c(2L, 2L, 2L, 2L, 2L, 3L, 3L,
3L, 3L, 3L, 1L, 1L, 1L, 1L,
Hi
>
> I have a bivariate plot of axis2 against axis1 (data below). I would
like
> to use different size, type and color for points in the plot for the
point
> coming from different region. For some reasons, I cannot get it done.
Below
> is my code.
>
> col <- rep(c("blue", "red", "darkgreen"
I have a bivariate plot of axis2 against axis1 (data below). I would like
to use different size, type and color for points in the plot for the point
coming from different region. For some reasons, I cannot get it done. Below
is my code.
col <- rep(c("blue", "red", "darkgreen"), c(16, 16, 16))
## C
Thanks - Jason Connor, Rolf Turner and Pascal Oettli.
Either of the following can remove the border surrounding the words.
legend (locator(1), "Important ones", box.col=NA)
legend (locator(1), " Important ones ", bty="n")
regards,
Chintanu
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_
On 08/03/12 18:52, Chintanu wrote:
Hi,
A very simple thing that I'm unable to do. I did look at the help but
While putting a legend on a plot, I don't wish to have the enclosing
border surrounding the words (as given below).
Tried to use the following, but didn't help :
legend (locator(
Hi,
A very simple thing that I'm unable to do. I did look at the help but
While putting a legend on a plot, I don't wish to have the enclosing
border surrounding the words (as given below).
Tried to use the following, but didn't help :
legend (locator(1), border=FALSE, fill=FALSE, "Import
On Feb 16, 2012, at 6:50 AM, David Zastrau wrote:
Hello everyone,
i’ve got a problem with my diagram’s legend. I know i should be able
to figure it out by reading the ‘plot’ and ‘legend’ reference.
However nothing works so it would be kind if anyone could point me
to the necessary parame
I figured it out:
you have to pass the mar-argument to the plot function and than you may
position the legend via inset.
Have a nice day!
From: David Zastrau
Sent: Thursday, February 16, 2012 12:50 PM
To: r-help@R-project.org
Subject: Legend vanishes when placed outside the graph
Hello ever
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