On 2015-05-10 21:14, David Winsemius wrote:
On May 10, 2015, at 6:11 AM, ce wrote:
yes indeed :
foo <- lapply(foo, function(x) if(x[1] == 1 ) {x[2] <- 0; x
}else{x} )
would work. But if the list is too long, would it be time consuming
rather than just updating elements that meet the if cond
5 06:00 PM
To: "ce"
CC: "David Winsemius" , r-help@r-project.org
Subject: Re: [R] how to update a value in a list with lapply
You can do the timing yourself on a dataset which you feel is typical of your
usage.E.g., define a function the implements each algorithm > f1 <-
e{x} )
>
> would work. But if the list is too long, would it be time consuming
> rather than just updating elements that meet the if condition?
>
> thx
> ce
>
>
> -Original Message-
> From: "David Winsemius" [dwinsem...@comcast.net]
> Date:
The data.table package was invented in large part to get around that design
concern.
--
David.
>
> thx
> ce
>
>
> -Original Message-
> From: "David Winsemius" [dwinsem...@comcast.net]
> Date: 05/09/2015 08:00 PM
> To: "ce"
> CC: r-help
s" [dwinsem...@comcast.net]
Date: 05/09/2015 08:00 PM
To: "ce"
CC: r-help@r-project.org
Subject: Re: [R] how to update a value in a list with lapply
On May 9, 2015, at 4:35 PM, ce wrote:
> Dear All,
>
> I have a list, using lapply I find some elements of the list, and then I
On May 9, 2015, at 4:35 PM, ce wrote:
> Dear All,
>
> I have a list, using lapply I find some elements of the list, and then I want
> to change the values I find. but it doesn't work:
>
> foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
> lapply(foo, function(x) if(x[1] == 1 ) x )
> $A
> [1] 1 3
Dear All,
I have a list, using lapply I find some elements of the list, and then I want
to change the values I find. but it doesn't work:
foo<-list(A = c(1,3), B =c(1, 2), C = c(3, 1))
lapply(foo, function(x) if(x[1] == 1 ) x )
$A
[1] 1 3
$B
[1] 1 2
$C
NULL
lapply(foo, function(x) if(x[1]
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