or how about
lm(myData$response~as.matrix(myData[2:4]))
hth, david
Juliet Hannah wrote:
>
> Hi All,
>
> I had posted a question on a similar topic, but I think it was not
> focused. I am posting a modification that I think better accomplishes
> this.
> I hope this is ok, and I apologize if it
Dear Juliet,
Why don't you use *apply() instead a for() loop? Here is a starting point:
> apply(myData[,-1],2,function(x) coefficients(lm(response~x)))
var1 var2 var3
(Intercept) 0.10438369 0.10415221 0.1176728
x -0.03354243 0.02429041 -0.2240759
Note
Hi All,
I had posted a question on a similar topic, but I think it was not
focused. I am posting a modification that I think better accomplishes
this.
I hope this is ok, and I apologize if it is not. :)
I am looping through variables and running several regressions. I have
reason to believe that
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