A::thename works only when thename is exported by the name space A.
A:::thename works only when thename is defined in the name space A.
getAnywhere(thename)$objs$"package:A" always works.
On Mar 25, 6:48 am, Duncan Murdoch wrote:
> hong shen wrote:
> > Hi list,
>
> > I encountered a situation th
Thanks for your reply.
But for some packages, it works. For others, you may get
Error: 'theName' is not an exported object from 'namespace:A'
What does "exported object" mean?
On Mar 25, 6:48 am, Duncan Murdoch wrote:
> hong shen wrote:
> > Hi list,
>
> > I encountered a situation that a data
hong shen wrote:
Hi list,
I encountered a situation that a data frame is defined by two packages. Both of
them are loaded by library(). My questions are
1. How could I tell the data frame is from which package?
find("theName")
will tell you where it found a variable called theName.
2. I
hong shen yahoo.com> writes:
>
> I encountered a situation that a data frame is defined by two packages. Both
of them are loaded by library().
> 2. If I want to reference the data frame from package A insted of B, how can I
do it?
Either change the loading sequence of library(). Or, if you wan
Hi list,
I encountered a situation that a data frame is defined by two packages. Both of
them are loaded by library(). My questions are
1. How could I tell the data frame is from which package?
2. If I want to reference the data frame from package A insted of B, how can I
do it?
Thanks!
hshen
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