You're right, I was in a hurry. This one works.
x <- rnorm(100)
a <- sample(letters[1:4], 100, T)
by.list <- by(x, a, summary)
do.call(rbind, as.list(by.list))
(I would also prefer aggregate.)
Rui Barradas
Em 09-10-2012 19:46, ilai escreveu:
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter wr
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter wrote:
>
> The only wrinkle here (with either rbind or simplify2array) is getting
> the labels correct if the design is not fully crossed -- i.e. if some
> groups are missing so that expand.grid() won't work. Then you might
> have to work harder to ext
Ilai, et. al:
Yes. The OP might also look at the result of:
> t(simplify2array (by.list))
The only wrinkle here (with either rbind or simplify2array) is getting
the labels correct if the design is not fully crossed -- i.e. if some
groups are missing so that expand.grid() won't work. Then you mig
On Tue, Oct 9, 2012 at 11:42 AM, Rui Barradas wrote:
> Hello,
>
> Try
>
> do.call(data.frame, by.list)
>
>
I don't think data.frame inside do.call works in this context. May need it
on the outside to do the job (Only OK here since there is no mixture of
numeric and character/factors in this summa
Hello,
Try
do.call(data.frame, by.list)
Hope this helps,
Rui Barradas
Em 09-10-2012 17:53, Jesus Frias escreveu:
> Dear R-helpers,
>
>
>
> I've got a summary of results from a by() call that I am making with a list
> of more than two of factors not very different from the example in the by()
Dear R-helpers,
Ive got a summary of results from a by() call that I am making with a list
of more than two of factors not very different from the example in the by()
help page
require(stats)
by(warpbreaks[, 1], warpbreaks[, -1], summary)
The result of the command gives a list
6 matches
Mail list logo
