Also, here is a similar solution, even more compact,
not involving zoo:
plot(y ~ x, na.omit(data.frame(x, y)), lty = 3, type = "l")
lines(y ~ x)
On Wed, Apr 16, 2008 at 11:18 PM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> Try this which interpolates the NAs using na.approx from zoo
> drawing
Try this which interpolates the NAs using na.approx from zoo
drawing the interpolated series with lty=3 and then overwrites
solid lines with the gaps using lines.
library(zoo)
plot(y ~ x, as.data.frame(na.approx(zoo(cbind(x, y, lty = 3, type = "l")
lines(y ~ x)
On Wed, Apr 16, 2008 at 8:56 P
On 17/04/2008, at 12:56 PM, DinoDragon wrote:
> This maybe a silly question. I'm trying to figure out a way to draw
> a line from a data set which contain NA. Say, I have a set of data as:
>
> x <- c(1.1 2.2 NA 4.4 5.5) ; y <- c(1:5) # as x,y of point a, b,
> c, d, and e.
>
> I would like to
This maybe a silly question. I'm trying to figure out a way to draw a line from
a data set which contain NA. Say, I have a set of data as:
x <- c(1.1 2.2 NA 4.4 5.5) ; y <- c(1:5) # as x,y of point a, b, c, d, and e.
I would like to plot this to a line by using dot-line to connect the two
adjac
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