Hi,
I have fixed this. I replaced the "=" with "<<-". I do not think this
is the most elegant way, so if anyone else has any better ideas they
would be very much apperitiaded.
New lines:
formulaGenotype <<- test_variable~Genotype + Gender
formulaNull <<- test_variable~Gender
Cheers,
Hi,
I have what I suppose is the same problem as this. I am using the
linear mixed model function lme, and this does not seems to take the
attribute "model=TRUE" at the end of the function.
Is there a more general way of solving this problem?
Is my description of the problem below correct (f
Thanks for you help. I also spent a lot of time on it. Your explanation is
very clear.
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On Jan 25, 2012, at 2:02 AM, moli wrote:
I want use survfit() and basehaz() inside a function, but it doesn't
work.
Could you take a look at this problem. Thanks for your help.
Following is my
codes:
library(survival)
n <- 50 # total sample size
nclust <- 5 # number of clusters
clust
> I want use survfit() and basehaz() inside a function, but it doesn't
> work. Could you take a look at this problem. Thanks for your help.
Your problem has to do with environments, and these lines
fmla <- as.formula("Surv(time, event) ~ Z1 + Z2")
BaseFun <- function(x){
start.coxp
Le mardi 24 janvier 2012 à 23:02 -0800, moli a écrit :
> I want use survfit() and basehaz() inside a function, but it doesn't work.
> Could you take a look at this problem. Thanks for your help. Following is my
> codes:
> Error in formula.default(object, env = baseenv()) : invalid formula
>
>
I want use survfit() and basehaz() inside a function, but it doesn't work.
Could you take a look at this problem. Thanks for your help. Following is my
codes:
library(survival)
n <- 50 # total sample size
nclust <- 5 # number of clusters
clusters <- rep(1:nclust,each=n/nclust)
beta0 <- c(1,
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