Thanks Gabor,
The trick to solve my problem is the %j, many thanks. I've seen now
it's documented in the help page of strptime as you indicate.
But please note that using format="ymd" I do get a chron object
and note that the value is the date without the 2 first digits
> require(chron)
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On Fri, Jun 8, 2012 at 7:16 AM, Jannis wrote:
> The following appears to be pretty "standard" (though not included in chron)
> to me:
>
> b = ISOdate(2001,12,12)
> format(b, '%j')
>
Using POSIXct here is error prone because it needlessly introduces
time zones into a problem where they are not r
The following appears to be pretty "standard" (though not included in
chron) to me:
b = ISOdate(2001,12,12)
format(b, '%j')
or is that what you refer to with
"I know I can make my own using julian" ?
No idea about the other questions though ...
Jannis
On 08.06.2012 10:01, Agustin Lobo w
On Fri, Jun 8, 2012 at 4:01 AM, Agustin Lobo wrote:
> Hi!
> Is not there an standard R function to retrieve the day of the year
> (since 1st Jan of the same year)?
> I know I can make my own using julian, but find it weird that having
> days(), months() etc doy() does not exist as an standard func
Hi Agustin,
You can check and adapt this solution to your needs:
http://stackoverflow.com/questions/9465817/count-days-per-year
Regards,
Carlos Ortega
www.qualityexcellence.es
2012/6/8 Agustin Lobo
> Hi!
> Is not there an standard R function to retrieve the day of the year
> (since 1st Jan of
Hi!
Is not there an standard R function to retrieve the day of the year
(since 1st Jan of the same year)?
I know I can make my own using julian, but find it weird that having
days(), months() etc doy() does not exist as an standard function.
Also, is the following not a bit inconsistent?
> a <- c
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