--
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of jagadishpchary
Sent: Thursday, June 18, 2015 1:46 AM
To: r-help@r-project.org
Subje
I think my explanation in the post is not giving the full details on the job
to be done. Sorry for that. Here is what I am doing..
1. I have a SPSS data set with more than 2000 variables. However for test
purpose I have created a temporary data set with 5 variables which I am
reading it to R
gt; Subject: [R] Cross tabulation with top one variable and side as multiple
> variables
>
> Hi:
>
> I have a huge data with lot of variables and I need to check the trend
> variations from year to year. In order to do so, I have to cross tabulate
> the year variable as
There are two issues here... calculation and presentation. The table function
from base R can work with many variables. If your data set is so large that you
have problems with memory then you could investigate data.table or sqldf
packages, which perform the computations but do not present the d
On Jun 9, 2015, at 1:40 AM, jagadishpchary wrote:
> Hi:
>
> I have a huge data with lot of variables and I need to check the trend
> variations from year to year. In order to do so, I have to cross tabulate
> the year variable as top (constant) and all the remaining variables as side
> (attached
Hi:
I have a huge data with lot of variables and I need to check the trend
variations from year to year. In order to do so, I have to cross tabulate
the year variable as top (constant) and all the remaining variables as side
(attached the cross tabulation report). I have searched the forums but th
d
From: Peter Maclean [mailto:pmaclean2...@yahoo.com]
Sent: Sunday, November 10, 2013 12:52 PM
To: dcarl...@tamu.edu
Subject: Re: [R] Cross Tabulation
Thanks. But I am creating lots of tables and I need Regions and
Districts to appear so as to avoid to much editing.
Peter Maclean
Department of
elp-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peter Maclean
Sent: Sunday, November 10, 2013 12:06 AM
To: r-help@r-project.org
Subject: Re: [R] Cross Tabulation
#Would like to create a cross-table (Region, district, response)
and
#(Region, district, cost. The flat table
#Would like to create a cross-table (Region, district, response) and
#(Region, district, cost. The flat table function does not look so good
region <- c("A","A","A","A","B","B", "B", "B", "C","C", "C", "C")
district <- c("d","d","e","e","f","f", "g", "g", "h","h", "i", "j")
response <- c("ye
On Mar 5, 2010, at 11:43 AM, Tarmo Remmel wrote:
Hello,
This is a seemingly simple task, but it has been frustrating me for
too
long, so I am turning to this list for some help.
I have two vectors of factors which are quite long; two simple
examples are
shown here:
No, those are not "
Those are numerical, not factors. If they were factors all levels
would be represented.
> a <- factor(c(1,2,3,4,5), levels = 1:5)
> b <- factor(c(1,2,5,5,6), levels = 1:6)
> table(a, b)
b
a 1 2 3 4 5 6
1 1 0 0 0 0 0
2 0 1 0 0 0 0
3 0 0 0 0 1 0
4 0 0 0 0 1 0
5 0 0 0 0 0 1
On Fri, M
Hello,
This is a seemingly simple task, but it has been frustrating me for too
long, so I am turning to this list for some help.
I have two vectors of factors which are quite long; two simple examples are
shown here:
> a <- c(1,2,3,4,5)
> b <- c(1,2,5,5,6)
If I produce a cross-tabulation of the
Like this?
age<-as.integer(sample(rnorm(100, mean=30, sd=10), replace=T))
height<-as.integer(1+age*rnorm(100,mean=1,sd=0.2))
plot(age, height)
table(age,height)
or
freq=data.frame(table(age,height))
freq<-subset(freq,Freq>0)
freq
bests
milton
On Fri, Aug 14, 2009 at 5:02 AM, rajclinasia wrote
Hi every one,
how to get frequency distributions for one variable across other variable.
ex: var1=age, var2=height i need frequency distribution of age across
height.
Thanks in Advance.
--
View this message in context:
http://www.nabble.com/cross-tabulation-for-frequency-distributions-tp2496853
on 02/27/2009 08:43 AM soeren.vo...@eawag.ch wrote:
> Hello,
>
> might be rather easy for R pros, but I've been searching to the dead end
> to ...
>
> twsource.area <- table(twsource, area, useNA="ifany")
>
> gives me a nice cross tabulation of frequencies of two factors, but now
> I want to con
Hello,
might be rather easy for R pros, but I've been searching to the dead
end to ...
twsource.area <- table(twsource, area, useNA="ifany")
gives me a nice cross tabulation of frequencies of two factors, but
now I want to convert to pecentages of those absolute values. In
addition I'd l
Try this:
> with(unique(x), table(V2, V3))
V3
V2Apple Cake
One 21
On Mon, Sep 29, 2008 at 4:54 AM, Shubha Vishwanath Karanth
<[EMAIL PROTECTED]> wrote:
> Hi R,
>
>
>
> This is a cross tabulation question. Suppose that,
>
>
>
>> d=read.table("clipboard",header=F)
>
>
>
>> d
>
>
?aggregate or have a look at the reshape package.
--- On Mon, 9/29/08, Shubha Vishwanath Karanth <[EMAIL PROTECTED]> wrote:
> From: Shubha Vishwanath Karanth <[EMAIL PROTECTED]>
> Subject: [R] Cross-tabulation Question
> To: [EMAIL PROTECTED]
> Received: Monday, Septembe
> x
V1 V2V3
1 A One Apple
2 A One Cake
3 A One Cake
4 B One Apple
5 B One Apple
6 B One Apple
> tapply(x$V1, list(x$V2, x$V3), function(z) length(unique(z)))
Apple Cake
One 21
>
On Mon, Sep 29, 2008 at 4:54 AM, Shubha Vishwanath Karanth
<[EMAIL PROTECTED]> wrote:
> Hi R
Hi R,
This is a cross tabulation question. Suppose that,
> d=read.table("clipboard",header=F)
> d
V1 V2V3
A One Apple
A One Cake
A One Cake
B One Apple
B One Apple
B One Apple
> table(d$V2,d$V3)
Apple Cake
One 42
Bu
On 14/10/07 5:39 PM, Louis Martin wrote:
> I am looking for an efficient and fast way for doing this:
>
> for (v in 1:dw) {ok <-list1[v,]
>
> for (z in 1:5) {kk = ok[z] ;
> for (o in 1:t) {if (kk== list[o]) n<- n+1}}
> show(n) }
>
> list1 : a data.fra
Howdy,
I am looking for an efficient and fast way for doing this:
for (v in 1:dw) {ok <-list1[v,]
for (z in 1:5) {kk = ok[z] ;
for (o in 1:t) {if (kk== list[o]) n<- n+1}}
show(n) }
list1 : a data.frame with nrow = dw ; ncol = z;
list2 : a data.fram
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