What does this have to do with date formats?? Please do not use "reply" to
discuss unrelated matters; even if you change the header, threading mail
readers will become confused.
Approach is a non-factor (the output says so), so treated as numerical, i.e.
you are effectively doing a linear regre
I am relatively new to R and I have problem figuring out why the data file
appear to be read in fine, but the one way ANOVA is not calculated
correctly. In other problems this works fine.
This program is listed at the end, and the small text file in online.
There are 24 data points in three group
Does this do what you want?
sasf <- c('31.12.1959','1.1.1960','1.2.1960')
dt <- as.Date(sasf, format='%d.%m.%Y')
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 1/27/12 7:45 AM, "Fischer, Felix" wrote:
>Hi everybo
On Jan 27, 2012, at 18:58 , David Winsemius wrote:
>
> On Jan 27, 2012, at 10:45 AM, Fischer, Felix wrote:
>
>> Hi everybody,
>>
>> i have a csv-file, containing dates in an akward sas format, where
>> 31.12.1559 is -1, 1.1.1960 is 1, 2.1.1960 is 2 and so on (see
>> http://www.sfu.ca/sasdoc/
On Jan 27, 2012, at 10:45 AM, Fischer, Felix wrote:
Hi everybody,
i have a csv-file, containing dates in an akward sas format, where
31.12.1559 is -1, 1.1.1960 is 1, 2.1.1960 is 2 and so on (see http://www.sfu.ca/sasdoc/sashtml/lrcon/zenid-63.htm
). Is there any function in R to convert th
Hi everybody,
i have a csv-file, containing dates in an akward sas format, where 31.12.1559
is -1, 1.1.1960 is 1, 2.1.1960 is 2 and so on (see
http://www.sfu.ca/sasdoc/sashtml/lrcon/zenid-63.htm ). Is there any function in
R to convert this into -M-D easily?
Best,
Felix
Dr. rer. nat. Dipl
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