Complementing:
findInterval(x[is.finite(x)], 1:20)
On Fri, Oct 1, 2010 at 2:55 PM, Henrique Dallazuanna wrote:
> Try this:
>
> x[is.finite(x)]
>
>
>
> On Fri, Oct 1, 2010 at 2:51 PM, wrote:
>
>> I calculated a large vector. Unfortunately, I have some measurement error
>> in my data and some o
On Oct 1, 2010, at 12:51 PM, mlar...@rsmas.miami.edu wrote:
> I calculated a large vector. Unfortunately, I have some measurement error
> in my data and some of the values in the vector are erroneous. I ended up
> wih some Infs and NaNs in the vector. I would like to filter out the Inf
> and Na
On Fri, Oct 1, 2010 at 10:51 AM, wrote:
> I calculated a large vector. Unfortunately, I have some measurement error
> in my data and some of the values in the vector are erroneous. I ended up
> wih some Infs and NaNs in the vector. I would like to filter out the Inf
> and NaN values and only k
Mike,
Small, reproducible examples are always useful for the rest of the us.
x <- c(0, NA, NaN, 1 , 10, 20, 21, Inf)
x[!is.na(x) & x >=1 & x<= 20]
Is that what you're looking for?
mlar...@rsmas.miami.edu wrote:
I calculated a large vector. Unfortunately, I have some measurement error
in my d
Try this:
x[is.finite(x)]
On Fri, Oct 1, 2010 at 2:51 PM, wrote:
> I calculated a large vector. Unfortunately, I have some measurement error
> in my data and some of the values in the vector are erroneous. I ended up
> wih some Infs and NaNs in the vector. I would like to filter out the Inf
I calculated a large vector. Unfortunately, I have some measurement error
in my data and some of the values in the vector are erroneous. I ended up
wih some Infs and NaNs in the vector. I would like to filter out the Inf
and NaN values and only keep the values in my vector that range from 1 to
2
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