Hello,
These two gives the same results:
aggregate(values ~ sex + status, mydata, sum)
# sex status values
#1 0 0 224
#2 1 0 5227
#3 0 1 11
#4 1 1 552
by(mydata$values, list(mydata$sex, mydata$status), sum)
#: 0
#: 0
#[1] 224
#-
On 2020-07-24 01:48 +0200, Rasmus Liland wrote:
> aggregate(x=list("values"=mydata$values),
> by=list("sex"=mydata$sex,
> "status"=mydata$status),
> FUN=sum)
>
> yields
>
> sex status values
> 1 0 0224
>
On 2020-07-23 18:54 -0400, Duncan Murdoch wrote:
> On 23/07/2020 6:15 p.m., Sorkin, John wrote:
> > Colleagues,
> > The by function in the R program below is not giving me the sums
> > I expect to see, viz.,
> > 382+170=552
> > 4730+170=4900
> > 5+6=11
> > 199+25=224
> > ###
On 23/07/2020 6:15 p.m., Sorkin, John wrote:
Colleagues,
The by function in the R program below is not giving me the sums
I expect to see, viz.,
382+170=552
4730+170=4900
5+6=11
199+25=224
###
#full R program:
mydata <- data.frame(covid=c(0,0,0,
by() chooses **data frame** subsets -- sum() is acting on these frames,
adding up everything in them.
Try this instead:
> by(mydata,list(mydata$sex,mydata$status),function(x)sum(x$values))
: 0
: 0
[1] 224
---
: 1
: 0
[1] 5227
Colleagues,
The by function in the R program below is not giving me the sums
I expect to see, viz.,
382+170=552
4730+170=4900
5+6=11
199+25=224
###
#full R program:
mydata <- data.frame(covid=c(0,0,0,0,1,1,1,1),
sex=(rep(c(1,1,0,0),2)),
status=rep(
6 matches
Mail list logo
