Yes, sorry it auto.arima is in the 'forecast' package. The following produces
the problem:
auto.arima(ts(c(rep(0,104), rep(143, 52), rep(260,33)), frequency=52))
Kevin
Prof Brian Ripley <[EMAIL PROTECTED]> wrote:
> On Thu, 25 Sep 2008, [EMAIL PROTECTED] wrote:
>
> > I am calling auto.ar
On Thu, 25 Sep 2008, [EMAIL PROTECTED] wrote:
I am calling auto.arima with a time series that is about 186
observations long with a frequency of 52. With some time series I get:
1:last.nonzero: result would be too long a vector
Is there something that I can do to the data to avoid this error?
I am calling auto.arima with a time series that is about 186 observations long
with a frequency of 52. With some time series I get:
1:last.nonzero: result would be too long a vector
Is there something that I can do to the data to avoid this error?
Thank you.
Kevin
Hello,
I am calling the auto.arima method in the forecast package at it returns what
seems to be valid Arima output. But when I feed this output to 'predict' I get:
Error in predict.Arima(catall.fit[[.index]], n.ahead = 12) :
'xreg' and 'newxreg' have different numbers of columns
Is there a
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