On Sun, Apr 8, 2012 at 11:57 AM, Duncan Murdoch
wrote:
> On 12-04-07 4:51 PM, Henrik Bengtsson wrote:
>>
>> On Sat, Apr 7, 2012 at 1:30 PM, Mark Heckmann
>> wrote:
>>>
>>> Hello,
>>>
>>> using the<<- assignment operator I do not understand why the following
>>> does not work.
>>>
>>> l<<- list()
On 12-04-07 4:51 PM, Henrik Bengtsson wrote:
On Sat, Apr 7, 2012 at 1:30 PM, Mark Heckmann wrote:
Hello,
using the<<- assignment operator I do not understand why the following does not
work.
l<<- list()
l
list()
l$arg1<<- "test"
error in l$arg1<<- "test" : Objekt 'l' not found
?"<<-" says:
On Sat, Apr 7, 2012 at 5:01 PM, Mark Heckmann wrote:
> Thanks! I'll try to stick to that advice!
> Maybe there is a better way... Here is what I want:
>
> I want to save some default settings for a package.
> The user can change these using a function similar to par().
> I do not want to use optio
On Sat, Apr 7, 2012 at 2:01 PM, Mark Heckmann wrote:
> Thanks! I'll try to stick to that advice!
> Maybe there is a better way... Here is what I want:
>
> I want to save some default settings for a package.
> The user can change these using a function similar to par().
> I do not want to use optio
Thanks! I'll try to stick to that advice!
Maybe there is a better way... Here is what I want:
I want to save some default settings for a package.
The user can change these using a function similar to par().
I do not want to use options() here as it will be quite a lot of parameters.
I was thinking
On Sat, Apr 7, 2012 at 1:30 PM, Mark Heckmann wrote:
> Hello,
>
> using the <<- assignment operator I do not understand why the following does
> not work.
>
> l <<- list()
> l
> list()
> l$arg1 <<- "test"
> error in l$arg1 <<- "test" : Objekt 'l' not found
>
> ?"<<-" says: "The operators <<- and
Hello,
using the <<- assignment operator I do not understand why the following does
not work.
l <<- list()
l
list()
l$arg1 <<- "test"
error in l$arg1 <<- "test" : Objekt 'l' not found
?"<<-" says: "The operators <<- and ->> cause a search to made through the
environment for an existing defini
Joshua, Dennis ans Henrique I'm immensely indebted to you. Thanks to
you I resolved my problem - a code works perfectly. I put the code,
maybe someone finds it's helpful.
f1 <- readLines(file("file1.txt"))
f2 <- readLines(file("file2.txt"))
for ( i in seq_along(f1)){
assign(f1[i],as.numeric(unli
Try this:
mapply(assign, x, list(y1, y2, y3), MoreArgs = list(envir = globalenv()))
On Fri, Nov 19, 2010 at 8:57 AM, Robert Ruser wrote:
> Hello R Users,
> I have vectors
> x <- c("a2","b7","c8")
> y1 <- c(1,2,3,2)
> y2 <- c(4,2,7,5,4,3,8)
> y3 <- c(1:10)
> and I want to assign values form vect
On Fri, Nov 19, 2010 at 3:20 AM, Robert Ruser wrote:
> a2 a should get the values.
Lists are a nice way to allow variable data (e.g., vectors, data
frames, matrices, etc. all of different sizes) but still group related
things (such as data from a single file) together, kind of like
putting all yo
Hi:
On Fri, Nov 19, 2010 at 2:57 AM, Robert Ruser wrote:
> Hello R Users,
> I have vectors
> x <- c("a2","b7","c8")
> y1 <- c(1,2,3,2)
> y2 <- c(4,2,7,5,4,3,8)
> y3 <- c(1:10)
> and I want to assign values form vector y1 to a new variable which
> name comes from the 1st value of the vector x et
Thank you, but unfortunately it's not resolve my problem. After
writing in R console e.g. a2 a should get the values.
Do you know how to read file 2 into R?
2010/11/19 Joshua Wiley :
> Hi Robert,
>
> What about a named list? This will generalize to your two text files
> one with data, the other
Hi Robert,
What about a named list? This will generalize to your two text files
one with data, the other with names.
x <- c("a2","b7","c8")
y1 <- c(1,2,3,2)
y2 <- c(4,2,7,5,4,3,8)
y3 <- c(1:10)
dat <- list(c(1,2,3,2), c(4,2,7,5,4,3,8), c(1:10))
names(dat) <- c("a2","b7","c8")
dat
# example
dat
Hello R Users,
I have vectors
x <- c("a2","b7","c8")
y1 <- c(1,2,3,2)
y2 <- c(4,2,7,5,4,3,8)
y3 <- c(1:10)
and I want to assign values form vector y1 to a new variable which
name comes from the 1st value of the vector x etc. How to do it using
only vector x. As a result I should have:
a2 <- y1
b7
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