Hello,
It looks to me like you want all the values of 'mylist' returned in a
list except for a[i] for each element of a. In this case, length(a) =
4, so you want 4 lists. If this is not what you were trying to do,
perhaps you could explain the pattern between your data and your
desired output.
I found this loop can do this. is there any simple method?
rm(list=ls())
a=c(2,3,5,7)
mylist=list(c(2,3),5,7)
newlist=list()
for (i in 1:4){
for (j in 1:length(mylist)){
newlist[[j]]=mylist[[j]]
if (a[i] %in% mylist[[j]]){
newlist[[j]]=mylist[[j]][mylist[[j]]!=a[i]]
if
There was a recent fortune suggestion along the lines of any simple
English sentence can probably be satisfied with a simple set of R
functions without loops. In this case you appear to be forgetting the
"simple English sentence" part of that formulation.
--
David.
On Jun 28, 2010, at 7:3
my list al is as below:
mylist=list(c(2,3),5,7)
> mylist
[[1]]
[1] 2 3
[[2]]
[1] 5
[[3]]
[1] 7
How could I get the following FOUR lists:
First one
[[1]]
[1] 3
[[2]]
[1] 5
[[3]]
[1] 7
Second one
[[1]]
[1] 2
[[2]]
[1] 5
[[3]]
[1] 7
Third One
[[1]]
[1] 2 3
[[2]]
[1] 7
Last one
[[1]]
[1] 2
On Jun 25, 2010, at 1:00 AM, song song wrote:
my list al is as below:
al=list(c(2,3),5,7)
al
[[1]]
[1] 2 3
[[2]]
[1] 5
[[3]]
[1] 7
and I check the second component, its element is 5, then I remove
this, now
my al is:
al[[2]][al[[2]]!=5]->al[[2]]
al
[[1]]
[1] 2 3
[[2]]
numeric(0)
[
Song -
Set the element to NULL:
al=list(c(2,3),5,7)
al[[2]] = NULL
al
[[1]]
[1] 2 3
[[2]]
[1] 7
- Phil Spector
Statistical Computing Facility
Department of Statistics
my list al is as below:
al=list(c(2,3),5,7)
> al
[[1]]
[1] 2 3
[[2]]
[1] 5
[[3]]
[1] 7
and I check the second component, its element is 5, then I remove this, now
my al is:
al[[2]][al[[2]]!=5]->al[[2]]
> al
[[1]]
[1] 2 3
[[2]]
numeric(0)
[[3]]
[1] 7
The Question is, how I can get the new li
7 matches
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