perfect thanks
On Mon, Sep 22, 2008 at 1:07 PM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> chron values are represented as day + fraction of a day so:
> try this:
>
> aggregate(z, floor, mean)
>
> On Mon, Sep 22, 2008 at 12:56 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
>> I am was going to
chron values are represented as day + fraction of a day so:
try this:
aggregate(z, floor, mean)
On Mon, Sep 22, 2008 at 12:56 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> I am was going to look at the as.yearmon function in the zoo package
> and write a as.day function to aggregate a time seri
I am was going to look at the as.yearmon function in the zoo package
and write a as.day function to aggregate a time series of 96
observations per day into the mean for each day, but I don't know how
to look at the code so that I can convert it into something I can use.
On top of that I believe th
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