Hi:
Per Baptiste's suggestion (not the iapply one, the plyr one :)
> aaply(b, 1, function(x) sort(x, na.last = FALSE))
Var1 1 2 3 4 5 6
1 1 2 4 5 7 9
2 NA 2 3 3 3 5
HTH,
Dennis
On Tue, Jan 19, 2010 at 2:27 AM, marco salvini wrote:
> Can you please help on the issue?
> I using the appl
Thank you for the answer Linlin,
I am wondering, is there a way to change it so that R will fill matrix's by
rows ?
Tal
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I guess that the matrix dimension changed because matrix in R are
filled by columns. Since you try:
apply(b, 1, function(y) sort(y, na.last=F))
The second parameter make it scan matrix b row by row but store result
by columns, which make the result be a matrix transposed.
If you try:
apply(b, 2, fu
Hi,
I think you could use iapply (search the archives) or the plyr package
to save you from transposing the result.
HTH,
baptiste
2010/1/19 marco salvini :
> Can you please help on the issue?
> I using the apply command on a matrix below the example:
>
> Create a vector
> x =c(5, 3, 2:4, NA, 7,
Hello Marco
What I would do, is use "t" to transpose the matrix.
Why it is that apply switches the matrix, is beyond my knowledge - and I
would love to read more informed replies.
Tal
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Details:---
Contact me: tal.gal...
Can you please help on the issue?
I using the apply command on a matrix below the example:
Create a vector
x =c(5, 3, 2:4, NA, 7, 3, 9, 2, 1, 5)
create a matrix of 2 rows by 6 columns
b=matrix(x, 2,6)
print(b)
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]524791
[2,]33
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