You picked a data set and ask whether the function parameters can fix the
partition. Perhaps you should consider a different data set: rep(47677,9). I
think you cannot "fix" the partition without considering the data also. Given
that, you may be able to go back and manually identify a partition
n Hodgess
> Sent: Wednesday, December 07, 2011 7:15 PM
> To: R help
> Subject: [R] a weird "cut" question
>
> Dear R People:
>
> I have the following data:
>
> > ail.df[,1]
> [1] 47677 47602 47678 47905 47909 47906 47605 47673 47607
> > cut(ail.df[,1
Dear R People:
I have the following data:
> ail.df[,1]
[1] 47677 47602 47678 47905 47909 47906 47605 47673 47607
> cut(ail.df[,1],breaks=3)
[1] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04]
[4] (4.78e+04,4.79e+04] (4.78e+04,4.79e+04] (4.78e+04,4.79e+04]
[7] (4.76e+04,4.77e+04] (4.76
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