Hello,
Just to say that I wouldn't write the function as John did. I would get
rid of all the deparse/substitute stuff and instinctively use a quoted
argument as a column name. Something like the following.
myfun <- function(frame, var){
[...]
col <- frame[, var] # or frame[[
Typo: "lazy evaluation" not "lay evaluation."
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Dec 5, 2016 at 1:46 PM, Bert Gunter wrote:
> Sorr
Sorry, hit "Send" by mistake.
Inline.
On Mon, Dec 5, 2016 at 1:34 PM, Bert Gunter wrote:
> Inline.
>
> -- Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" com
Inline.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Dec 5, 2016 at 9:53 AM, Rui Barradas wrote:
> Hello,
>
> Inline.
>
> Em 05-12-2016 17:09
> On Dec 5, 2016, at 9:53 AM, Rui Barradas wrote:
>
> Hello,
>
> Inline.
>
> Em 05-12-2016 17:09, David Winsemius escreveu:
>>
>>> On Dec 5, 2016, at 7:29 AM, John Sorkin wrote:
>>>
>>> Rui,
>>> I appreciate your suggestion, but eliminating the deparse statement does
>>> not solve my probl
Hello,
Inline.
Em 05-12-2016 17:09, David Winsemius escreveu:
On Dec 5, 2016, at 7:29 AM, John Sorkin wrote:
Rui,
I appreciate your suggestion, but eliminating the deparse statement does not
solve my problem. Do you have any other suggestions? See code below.
Thank you,
John
mydf <-
dat
Hello,
For some reason I got moderation in reply to Bert's post so I'll retry.
Get rid of 'xx', keep 'yy':
frame[, yy] # this works
Hope this helps,
Rui Barradas
Em 05-12-2016 15:29, John Sorkin escreveu:
Rui,
I appreciate your suggestion, but eliminating the deparse statement does
not solv
Bert is right, that's exactly what I mant.
Rui Barradas
Em 05-12-2016 15:36, Bert Gunter escreveu:
John:
I think you need to re-read about how functions pass arguments and
data frame access works in R.
What Rui meant was to get rid of all the xx stuff and access your column by:
col <- frame[
> On Dec 5, 2016, at 7:29 AM, John Sorkin wrote:
>
> Rui,
> I appreciate your suggestion, but eliminating the deparse statement does not
> solve my problem. Do you have any other suggestions? See code below.
> Thank you,
> John
>
>
> mydf <-
> data.frame(id=c(1,2,3,4,5),sex=c("M","M","M","F"
John:
I think you need to re-read about how functions pass arguments and
data frame access works in R.
What Rui meant was to get rid of all the xx stuff and access your column by:
col <- frame[, yy]
That *does* work.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that pe
Rui,
I appreciate your suggestion, but eliminating the deparse statement does not
solve my problem. Do you have any other suggestions? See code below.
Thank you,
John
mydf <-
data.frame(id=c(1,2,3,4,5),sex=c("M","M","M","F","F"),age=c(20,34,43,32,21))
mydf
class(mydf)
myfun <- function(frame,
I forgot to say that I've commented out the line
# This does not work.
#col <- xx[,"yy"]
Rui Barradas
Em 05-12-2016 15:17, Rui Barradas escreveu:
Hello,
You don't need xx <- deparse(substitute(...)), since you are passing the
data.frame to your function. Just use
myfun <- function(frame,var
Hello,
You don't need xx <- deparse(substitute(...)), since you are passing the
data.frame to your function. Just use
myfun <- function(frame,var){
[...]
# Nor does this work.
col <- frame[,yy]
print(col)
}
myfun(mydf,age)
myfun(frame = mydf, var = age)
[1] 2 3
I can get the name o
I am trying to write a function which, when passed the name of a dataframe and
the name of a column of the dataframe, will allow me to work on the columns of
a dataframe. I can not get my code to work. Please see the code below. Any help
in getting the function to work would be appreciated.
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